Hi all. Sorry to bother you.
I have a table like the following
A B C D E F
G1 0 1 1 0 1 1
G2 0 1 1 0 1 1
G3 0 0 0 0 0 1
H1 1 1 1 1 1 1
H2 1 0 1 1 0 1
H3 1 0 1 1 0 1
I already know G1, G2 and G3 belong to the same group and H1, H2 and H3 belong
to the other group. I want
Hi All. Sorry to bother you. I have a question about fisher exact test.
I counted the presence of gene mutation in two groups of samples. My data is as
follows
Presence Absence
GroupA 46
GroupB 511
When using the formula of fisher exact test
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