I'm not an expert useR but I asked a similar question to stack overflow
that might give you new ideas.
http://stackoverflow.com/questions/17458556/how-can-i-speed-up-this-sapply-for-cross-checking-samples
On Thu, Aug 15, 2013 at 2:30 AM, Praveen Surendran
wrote:
> Dear Doran, Bert and Roger,
>
with making this work.
The end result I'm hoping for would be an image exactly like the one
I've read in (Rlogo.jpg for this small example). I turned off
dev.copy lines because I'm not sure on the guidelines for file writing
functions.
Thanks,
Hans Thompson
Forgive me If I made an
Hello.
I have a two statement logical that if NA is returned for the second
statement I want to rely on result of the first statement. I still would
like to use both when I can though.
x <- c(1:5)
y <- c(1,2,NA,4,5)
x < 5 & x-y == 0
How can I trick R to refer back to (x < 5) where it is NA on t
Hello r-help,
I've been banging my head against the computer in an attempt to learn how
to divide my matrix into segments by rows. I want to be able to return each
segment as a newly named object. I've tried looking at the apply functions
and creating a for loop but brain no work. Here's the bas
If I have a two column data frame like:
> dat <- cbind("x"=c(1:100),"y"=c(100:1))
How can I create an array that splits every ten rows of that data frame
into a third dimension of an array so that:
> newarray[,,1]
,,1
x y
1 100
2 99
3 98
... ...
10 91
,,2
xy
11 90
12 89
...
I have been trying to find a way to label my cluster with the colors I want
using factors. I am not having a good time. I can make the plot I'm
looking for but how can I make it so I specify that my ordered factors have
ordered colors (1= "blue", 2="green", 3="red")?
x <- c(rnorm(10,1,1),rnorm(1
I know that there are quite a few packages out that there for cluster
analysis. The problem that I am facing is finding a package that will not
incorporate all my samples into clusters but just the samples that fit a
threshold (that I have not set yet and may need help finding the right
level) for
res[, k <- k + 1] <- midpoint(cx, cx - dist)
>res[, k + 1] <- midpoint(colx, colx - 1)
>res
> }
>
> lapply(seq_len(length(l1)), function(i) fun1(l1[[i]], l2[[i]]))
> lapply(seq_len(length(l1)), function(i) fun2(l1[[i]], l2[[i]]))
>
>
> If I'm
The function I am giving for context is cbind. Are you asking how I would
like to apply the answer to my question?
I am trying to take the results of a Fluidigm SNP microarray, organized by
assay into a list (each component is the results of one assay), find
coordinate midpoints ([1,] and [2,] of
Yes. This gives me:
[,1] [,2] [,3] [,4]
[1,]1234
[2,]2345
[,1] [,2] [,3] [,4]
[1,]6789
[2,]789 10
BUT, how can I have it still within components like
[[1]]
[,1] [,2] [,3] [,4]
[1,]1234
[2,]23
I'm confused why I haven't made clear what I am asking for help with.
I have two different lists with two (or many) components, [[1]] and [[2]].
One of the list has components with dim=c(2,3) and the other has dim=c(2,2).
I want to create a new list with components dim=c(2,4) by binding togeth
The combination of column means in cbind is what I am trying to do. I just
don't know how to do it for every component (2 in this case) of the list.
I've been able to work with R to apply a function across all components when
there is just one list but I am having trouble working with multiple li
#If I have two lists as follows
a1<- array(1:6, dim=c(2,3))
a2<- array(7:12, dim=c(2,3))
l1<- list(a1,a2)
a3<- array(1:4, dim=c(2,2))
a4<- array(5:8, dim=c(2,2))
l2<- list(a3,a4)
#how can I create a new list with the mean across all arrays within the
list, so all components are included
Where can I find the posting guide? I've been trying to use "A handbook of
Statistical Analyses Using R" and google searching but I will be reading "An
Introduction to R" now that I see its better to starting out then using the
"?function". sorry.
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I meant (1,1) as an (x,y) coordinate. I am trying to find the function to
return the coefficient of the line running through:
>B
x y
a 1 1
and all the points in:
>A
x y
a 1 3
b 2 2
c 3 1
hope that is more clear. Thanks again Rui.
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Thank you to everyone in this forum that has been helping me with the basic R
skills while I learn to apply them.
I would like to take the coefficient of two coordinates. One of them comes
from two different columns in a table:
>A
x y
a 1 3
b 2 2
c 3 1
the other is set and
Thanks Rui and Jeff,
I thought that transposing the matrix would let me plot it the way I thought
it would but it did not. How can I take:
matrix "e":
AAB BAB CCD DCD
x 1.75 2.25 3.25 3.75
y 6.25 6.75 7.25 7.75
and treat the x and y rows as the x and y axis values and plot th
Is there a function I can use to invert the final table rows and columns?
I'd like to plot the x and y so that I can place them with another point and
get coefficient values. So:
AAB BAB CCD DCD
x 1.75 2.25 3.25 3.75
>y 6.25 6.75 7.25 7.75
to "A"
x y
AAB
BA
Yes. This worked very well for what I am trying to do. The only problem I
had though was figuring out why
dimnames(a) <- list(c("x","y"), LETTERS[1:4])
would not list the rows as x and y. I changed it though to
letters[24:25]
Thanks again Petr.
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Hello, this forum was very helpful yesterday with a simple question I had on
working with tables. What function will I need to use to do the following.
Move matrix a:
AB C D
x1234
y5678
to the mean of B&C and C&D:
BC CD
x 2.5 3.5
y
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