I do not see any posting on this topic from Jeff Newmiller.
I seek a way to “teach” R that "2021-07-25” represents a Year, Month, and Day.
Greg Coats
> Fuel <- c(50.45, 61.48, 59.07, 55.40, 30.63, 41.35, 32.81, 49.86, 62.99,
> 89.37)
> plot (Fuel)
> Dates <- c("2021-07-25", "2021-08-27", "2021-09
# Column 1 is the Year
# Column 2 is the Month
# Column 3 is the Day
# Column 4 is the Fuel
Fuel <- c(50.45, 61.48, 59.07, 55.40, 30.63, 41.35, 32.81, 49.86, 62.99, 89.37)
plot (Fuel)
2021 7 25 50.45
2021 8 27 61.48
2021 9 26 59.07
2021 11 4 55.40
2021 11 22 30.63
2021 11 26
, 2021, at 1:07 PM, Gregory Coats via R-help
> wrote:
>
> On my MacBook, I do not have, and do not know how to install, library(hms).
> Greg Coats
>
>> library(hms)
> Error in library(hms) : there is no package called ‘hms’
>> Install.libraries(“hms”)
> Error: u
On my MacBook, I do not have, and do not know how to install, library(hms).
Greg Coats
> library(hms)
Error in library(hms) : there is no package called ‘hms’
> Install.libraries(“hms”)
Error: unexpected input in "Install.libraries(“"
>
[[alternative HTML version deleted]]
__
Thank you very much.
In addition to what your did, for event 1, I would like to draw a horizontal
line connecting from day 1 to day 2 to day 3 to day 4.
Then, for event 2, I would like to draw a horizontal line connecting from day 1
to day 2 to day 3 to day 4.
Similarly for events 3, and 4. Is th
Dan, Thank you for this guidance.
Unfortunately, I do not have the library lubridate, and I do not at this moment
know where to go to get this library for an Apple MacBook.
> library(lubridate)
Error in library(lubridate) : there is no package called ‘lubridate’
Greg Coats
Reston, Virginia USA
Thank you. Let me redefine the situation.
Each time an event starts, I record the date and time.
Each day there are 4 new events. Time is the only variable.
I would like to graphically show how the time for events 1, 2, 3, and 4 for the
current day compare to the times for events 1, 2, 3, and 4 fo
I need a plot that shows the date and time that each event started.
This ggplot command was publicly given to me via this R Help Mailing LIst.
But the result of issuing the ggplot command is an Error in FUN message.
ggplot(myDat, aes(x=datetime, y = Y_Var)) + geom_point()
Error in FUN(X[[i]], ...)
cification, the as.POSIXct function works as expected
>> on Mac:
>>>
>>> myDat <- read.table(text =
>>> "datetime
>>> 2021-03-11 10:00:00
>>> 2021-03-11 14:17:00
>>> 2021-03-12 05:16:46
>>> 2021-03-12 09:17:02
>>> 2021-
time
> 2021-03-11 10:00:00
> 2021-03-11 14:17:00
> 2021-03-12 05:16:46
> 2021-03-12 09:17:02
> 2021-03-12 13:31:43
> 2021-03-12 22:00:32
> 2021-03-13 09:21:43",
> sep = ",", header = TRUE)
>
> myDat$datetime <- as.POSIXct(myDat$datetime, tz = &quo
My computer is an Apple MacBook. I do not have POSIX.
The command
myDat$datetime <- as.POSIXct(myDat$datetime, tz = "", format = "%Y-%M-%d
%H:%M:%OS")
yields the error
Error in `$<-.data.frame`(`*tmp*`, datetime, value = numeric(0)) :
replacement has 0 rows, data has 13
Please advise, How to p
I store in a text file the dates and times that an event occurred.
How do I direct R to import these text characters, and store the year, month,
day, hour, minute, and second as a date?
How do I then plot this series of dates?
2021-03-11 10:00:00
2021-03-11 14:17:00
2021-03-12 05:16:46
2021-03-12
I reported this behavior on Thu Jan 7, 2021.
You did nothing wrong.
No fix has been issued.
This evening, I upgraded from R 4.0.2 to the Duke University R 4.0.3 for Apple
Mac. Now all I can get from R 4.0.3 is this red error message (that means
nothing to me). Is there an easy fix? Greg
2021-01
I upgraded from R 4.0.2 to R 4.0.3 for Apple Mac at Duke University. Now, the
only output I get from R 4.0.3 is an error message. Greg Coats
2021-01-07 22:58:42.997 R[8311:37566] Warning: Expected min height of view:
() to be less than or equal to 30
but got a height of 32.00. This error wil
After calling plot, I draw a horizontal line representing the median with aline.
abline (h=median(walk_seconds), lty=1, lwd=2.0, col="firebrick4")
Then, I want to label that line as the median and do so by calling mtext.
mtext (side=4, "median", col="firebrick4", adj=“0.50”)
The dilemma is I do no
I need to be able to draw and label a vertical line, representing the date of
some arbitrary event. The date of the first entry is 2013-11-29. How would I
draw, and label a red vertical line at 2019-04-06? Greg
gcdf<-read.table(text="2013-11-29 19.175
2014-01-20 10.072
2014-02-12 10.241
2014-03-
I would like to be able to draw and label a vertical line, representing the
date of some arbitrary event. The date of the first non-zero entry is
2013-11-29. How would I draw and label a red vertical line at 2019-04-06? Greg
gcdf<-read.table(text="2013-11-29 00.000
2013-12-29 19.175
2014-01-20 1
I added a zero initial entry to the data set. Greg
gcdf<-read.table(text="2013-11-29 00.000
2013-12-29 19.175
2014-01-20 10.072
2014-02-12 10.241
2014-03-02 05.916
> On Dec 16, 2020, at 12:32 PM, Gregory Coats via R-help
> wrote:
>
> Jim, Thank you!
> The data set be
Jim, Thank you!
The data set begins
gcdf<-read.table(text="2013-12-29 19.175
2014-01-20 10.072
2014-02-12 10.241
I note that data begins in 2013. But the plot command does not show this first
entry in 2013, and instead shows the second data pair as the first data pair.
As a consequence, plot does
.652",
> header=TRUE,stringsAsFactors=FALSE,
> col.names=c("date","gallons"))
> gcdf$date<-as.Date(gcdf$date,"%Y-%m-%d")
> plot(gcdf$date,gcdf$gallons,main="Gallons by date",
> xlab="Date",ylab="Gallons")
>
> J
Starting with year-month-day, for the variable gallons, I can easily plot the
variable gallons, while disregarding the date.
gallons <- c (15.973, 18.832, 17.392, 14.774, 19.248, 14.913, 15.226, 14.338,
18.777, 19.652)
plot (gallons, type="l", xlab="X label", ylab="Y label", col="blue”)
How do
Today, I downloaded, and installed the June 6, 2020 version of R, from the CRAN
official site at Carnegie Mellon University. Unfortunately, while the CMU
compiled Mac OS X R application provides access to base R stat functions, like
mean, it does not provide me with access to any of R’s more adv
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