Re: [R] recursive lapply and keeping track of data

Hello William, that's exactly what I needed. I didn't consider lapply'ing over seq_along(data) instead of data, very useful. Thanks a lot! Giovanni On Mon, Aug 14, 2017 at 10:02 PM, William Dunlap wrote: > You could replace your 'depth' argument with one that shows where in the > original data

[R] recursive lapply and keeping track of data

Hello, I'm writing a program that takes a tree in input (nested lists) and returns a copy of it replacing the leaves with something else (eg: a computation done on the original leaves). In the example below, the tree is composed by countries and cities, and the leaves (children of the cities) are

Re: [R] define a list with names as variables

On Fri, Aug 4, 2017 at 4:25 PM, Bert Gunter wrote: >> f <- function(foo,bar) structure(list(bar),names =foo) > >> f("hello","world") > $hello > [1] "world" > > Cheers, > Bert Thanks Bert, I didn't know about "structure()". Giovanni __ R-help@r-project

Re: [R] define a list with names as variables

Hello Thomas, Ulrik, thanks for your suggestions. Giovanni On Fri, Aug 4, 2017 at 12:13 PM, Thomas Mailund wrote: > Do you mean like this? > > >> f <- function(foo, bar) { > + result <- list(bar) > + names(result) <- foo > + result > + } > >> (x <- f("hello", "world")) > $hello > [1] "wo

[R] define a list with names as variables

Hello, I'm having troubles defining a list where names are variables (of type character). Like this, which gives "foo" instead of "world" (the way I meant it is that "world" is the value of the variable foo). Any hint? > f <- function(foo, bar) { list(foo = bar) } > x <- f("hello", "world") > nam