Sorry for the dumb question, but I couldn't figure this out myself.
Consider the following:
> str <- c("abc","def")
> array(str, c(2,1))
[,1]
[1,] "abc"
[2,] "def"
How can i obtain the outcome of the second instruction without
specifying the number of rows?
Thank you in advance,
Francesco.
On Thu, Dec 24, 2009 at 4:38 AM, Brian G. Peterson wrote:
>
> data <- matrix(rnorm(100), nrow=10) # 10 x 10
> apply(data,2,cumsum)
>
> if you want to store the partial sums
> (that was an important bit of information you left out)
>
>
Thank you for your suggestion. However, I gave information onl
Il giorno mer, 23/12/2009 alle 22.14 -0500, David Winsemius ha scritto:
> > for(i in 1:n){
> >submat <- data[1:i,]
> >C <- colSums(submat)
> >}
> >
> In R the loop is not necessary, even confusing as you are demonstrating:
>
> > mat <- matrix(rnorm(100), nrow=10) # 10 x 10
> > colSu
So I see from help([[) what's happening: thank you very much.
Il giorno mer, 23/12/2009 alle 18.59 -0800, Henrik Bengtsson ha scritto:
> Use
>
>submat <- data[1:i,, drop=FALSE]
>
> /H
>
> On Wed, Dec 23, 2009 at 6:46 PM, Francesco Napolitano
> wrote:
&
Hi all,
I'm trying to learn R after years of Matlab's experience. Here is an
issue I couldn't solve today.
Consider the following piece of code (written by memory):
for(i in 1:n){
submat <- data[1:i,]
C <- colSums(submat)
}
The problem is that at the first iteration, data[1:1,] redu
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