Dear expert,
I want to combine 4 figures in the same plot. Each bar plot is related
to the image() plot. I want to bar width is extractly the same width
as grid width in the image() plot. The up-barplot and the
left-barplot. I have pasted my code to follow. How can I modify for
this purpose? Thank
Dear expert,
How can I make follow codematrix function more faster?
top20.dat <- top20.dat[,7:length(top20.dat[1,])]
top40.dat <-
read.table("top40snps.ped",header=F,sep="\t",stringsAsFactors=F)
row.names(top40.dat) <- top40.dat[,1]
top40.dat <- top40.dat[,7:length(top40.dat[1,])]
codematrix <- f
John Kane,
Thanks. It makes some of sense. But it seems not exactly what I want.
I just remember it need using mtext and adjust margin. I saw such of
example long time ago, but I have forgotten it.
On Fri, Feb 8, 2013 at 3:32 PM, John Kane wrote:
> Here is a rough example of what you want. You w
Thank your reminder.
Here is the example code:
a<- rnorm(1000,0,1)
b<-rnorm(1000,0,2)
c<-rnorm(1000,0,3)
d<-rnorm(1000,0,4)
par(mfrow=c(2,2))
hist(a)
hist(b)
hist(c)
hist(d)
I want to add A, B, C and D on each top left.
On Fri, Feb 8, 2013 at 2:35 PM, John Kane wrote:
> Yes there probably is if
Dear list,
Is there a elegant way to name multiple ordered plot as A, B, C and D?
Just put A, B, C and D on the top left corner of each plot.
Usually I do it in Illustrator, but I think in R should there is a way.
Could you please provide a example?
Thank you very much in advance.
set 2 (area2
> parameter). You probably want:
> venn.plot <- draw.pairwise.venn(
> area1 = 3186 + 5880,
> area2 = 325 + 5880,
> cross.area = 5880);
>
> Paul
>
>
> -Original Message-
> From: hiek...@gmail.com [mailto:hiek...@gmail.com] On Behalf Of Fabrice Tou
Dear list,
When I use VennDiagram package, I got a error as follow:
venn.plot <- draw.pairwise.venn(
area1 = 3186,
area2 = 325,
cross.area = 5880);
Error in draw.pairwise.venn(area1 = 3186, area2 = 325, cross.area = 588) :
Impossible: cross section area too large.
Does anyone have suggestion
require("fortunes")
Loading required package: fortunes
>fortune("<<-")
I wish <<- had never been invented, as it makes an esoteric and dangerous
feature of the language *seem* normal and reasonable. If you want to dumb down
R/S into a macro language, this is the operator for you.
-- Bill Venabl
Dear list,
When I read some source code, I find lot of place used symbol <<- , e.g.
lastTime <<- newTime;
What is the meaning here?
Also, I find some method with the name start with dot, e.g.
.RowStandardizeCentered = function(x) {
div = sqrt( rowSums(x^2) );
div[ div == 0 ] =
Thank you for your reply.
I used debian system. I will try parallel. Thanks.
uname -a
Linux m1000e1-m610-6 2.6.26-2-amd64 #1 SMP Tue Mar 9 22:29:32 UTC 2010
x86_64 GNU/Linux
sessionInfo()
R version 2.14.2 (2012-02-29)
Platform: x86_64-unknown-linux-gnu (64-bit)
locale:
[1] C
attached base pack
Dear list,
I am using mclapply(from multicore) to use multiple cores on one
server. If I do not use mclapply, just one core, my R problem will use
4G memory. When I use mclapply and set mc.cores =10, each core will
use 4G memory. So totally it will use 40G memory. Is it possible let
each core to s
I think multicore is one of answer if you can write your function in to lapply.
On Mon, Jun 18, 2012 at 12:14 PM, R. Michael Weylandt
wrote:
> I would argue (somewhat emphatically) that the parallel facilities you
> are looking at are absolutely not for `for` loops. `for` loops are a
> control st
Peter,
Thank you. In fact, I am also very interesting to WGCNA.
On Sat, Jun 16, 2012 at 3:29 AM, Peter Langfelder
wrote:
> On Fri, Jun 15, 2012 at 8:04 AM, Ingezz wrote:
>> Dear Peter,
>>
>> I am trying to apply the WGCNA meta-analysis for two (or more) microarray
>> datasets-tutorial to my own
0 and 1 means zero or 1 match.
Want to remove the word "Energy"?
gsub("( Energy){0,1},{0,1} Inc[.]{0,1}", "", DF)
On Thu, May 31, 2012 at 11:45 AM, mdvaan wrote:
> Thanks! That works like a charm, but I am not sure if I fully understand the
> syntax. I looked at the gsub page but still couldn't
Dear list,
I want to run two independent calculation (A, B) and then combined
their results to do a plot in R. Before I just run calculation A
first, then calculation B. It will take some times. I just have one
server with multiple core. I noticed that there are some nice package
in R for parallel
Thank you for your sharing
I got it.
On Tue, Sep 27, 2011 at 9:44 PM, David Winsemius wrote:
>
> On Sep 27, 2011, at 3:19 PM, Fabrice Tourre wrote:
>
>> Dear list,
>>
>> How can I detect a package is installed or not? If not, then install it.
>>
>> For ex
Dear list,
How can I detect a package is installed or not? If not, then install it.
For example, in a script, I want to check the package DESeq is
installed or not. If not, then I will using this script to install it.
source("http://www.bioconductor.org/biocLite.R";)
biocLite("DESeq")
The pseud
Thanks. Before I never used findInterval function. It seems very nice.
On Wed, Apr 6, 2011 at 11:20 PM, David Winsemius wrote:
>
> On Apr 6, 2011, at 9:46 AM, Fabrice Tourre wrote:
>
>> Dear Henrique Dallazuanna,
>>
>> Thank you very much for your suggestion.
>>
This is extractly what I want. Thank you very much.
On Wed, Apr 6, 2011 at 5:22 PM, Petr PIKAL wrote:
> Hi
>
>
> r-help-boun...@r-project.org napsal dne 06.04.2011 10:48:04:
>
>> Dear list,
>>
>> I have a dataframe with two column as fellow.
>>
>> > head(dat)
>> V1 V2
>> 0.15624 0.94
Try this:
>
> fil <- sapply(ran, '<', e1 = dat[,1]) & sapply(ran[2:(length(ran) +
> 1)], '>=', e1 = dat[,1])
> mm <- apply(fil, 2, function(idx)mean(dat[idx, 2]))
>
> On Wed, Apr 6, 2011 at 5:48 AM, Fabrice Tourre wrote:
>> Dear list,
>
Dear list,
I have a dataframe with two column as fellow.
> head(dat)
V1 V2
0.15624 0.94567
0.26039 0.66442
0.16629 0.97822
0.23474 0.72079
0.11037 0.83760
0.14969 0.91312
I want to get the column V2 mean value based on the bin of column of
V1. I write the code as fellow. It wor
Hi Rex,
Thanks for you explain. In fact, my question is: When I observed that
there are 6 or more balls in one box, what is this probability? The
ball is randomly put into the boxes.
I think it is: 1-pbinom(6,142,1/491) = 2.272026e-08.
When the sample size is large, how should I do this? using ch
Hi List,
I have a question to calculate probability using R.
There are 491 boxes and 142 balles. If the ball randomly put into the
box. How to calculate the probability of six or more there are in one
box?
I have try :
dbinom(6,142,1/491)
1-pbinom(6,142,1/491)
But I think I have some unclear
Hi list,
I want to plot two plot in the same figure. I set par(new=TRUE). But
it does not work.
library(lattice)
myPanel <- function(x,...)
{
panel.histogram(x,alpha=0.4,...)
ltext(0.4,1.5,paste("Mean=","0.05",digit=2)),cex=0.8)
ltext(0.8,1.5,paste("s.d.=","0.06",digit=2)),cex
population is all individual.
sample is a part of population.
If the sample size is enough large, mean(sr*sr)-mean(sr)*mean(sr) will
almost equal to cov(sr, sr).
On Wed, Jan 19, 2011 at 3:59 PM, Alaios wrote:
> Dear Josh,
> I would like to thank you for your reply.
>
>
> I think that it is clear
Hi
Thanks for you suggestion. I used histograme in lattice packages. If
it is possible lattice can do it, it will be better.
On Mon, Jan 17, 2011 at 3:28 PM, Peter Ehlers wrote:
> On 2011-01-17 02:26, Fabrice Tourre wrote:
>>
>> Hi all,
>> How to plot as the coordinate a
Hi all,
How to plot as the coordinate as in my attachment? I want to trim the
coordinate and one of plot as the figure in attachment. Does any one
have such example?
Thanks.
<>__
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using dget to try this data.
dget("probesnum")->a
some data length is 3, some is 4.
thanks.
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