Re: [R] 4.5.0 | update/install BH

could choose the CRAN mirror.) > > > Actually, BH was not on the list, but > >> system.time(install.packages("BH")) > trying URL > 'https://cloud.r-project.org/bin/macosx/big-sur-x86_64/contrib/4.5/BH_1.87.0-1.tgz' > Content type 'application/x-gzip' length 13900146 bytes (1

[R] 4.5.0 | update/install BH

So, I decided to update from 4.4.3 -> 4.5.0. Updating all packages in one shot (selecting all of the offered updates) failed, on all my machines (Linux, Windows - lots of RAM, lots of CPU speed). So, tried the updates a few at a time. Didn't take me long to discover that the 'culprit' was the B

Re: [R] [External] converting MATLAB -> R | element-wise operation

Very interesting - thanks! Most of my problems are not limited by compute speed, but its clear that for some sorts of compute-intensive problems, sweep might be a limiting approach. On 2/29/2024 6:12 PM, Richard M. Heiberger wrote: > I decided to do a direct comparison of transpose and sweep. >

Re: [R] [External] converting MATLAB -> R | element-wise operation

[,2] [,3] > [1,] 0.5 0.667 0.75 > [2,] 2.0 1.667 1.50 > R matrices are column-based. MATLAB matrices are row-based. > >> On Feb 27, 2024, at 14:54, Evan Cooch wrote: >> >> So, trying to convert a very long, somewhat technical bit of lin alg >> MA

[R] converting MATLAB -> R | element-wise operation

So, trying to convert a very long, somewhat technical bit of lin alg MATLAB code to R. Most of it working, but raninto a stumbling block that is probaably simple enough for someone to explain. Basically, trying to 'line up' MATLAB results from an element-wise division of a matrix by a vector wi

[R] linear programming in R | limits to what it can do, or my mistake?

Question for 'experts' in LP using R (using the lpSolve package, say) -- which does not apply to me for the sort of problem I describe below. I've run any number of LP's using lpSolve in R, but all of them to date have objective and constraint functions that both contain the same variables. This

Re: [R] reference generated var name in loop

ames=1:5) for(nm in names(parms)) { tmp.nm <- paste0(nm, '_r') ranvec[[tmp.nm]] <- rnorm(5, parms[nm], 0.25) } On Fri, May 26, 2023 at 8:50 AM Evan Cooch wrote: Greetings -- I'm trying to write some code that basically does the following: 1\ user inputs a list of parameter na

[R] reference generated var name in loop

Greetings -- I'm trying to write some code that basically does the following: 1\ user inputs a list of parameter names, and parameter values. 2\ code parses this list, extracting parameter names and values separately 3\ loops over the number of parameters, and for each parameter, generates so

Re: [R] extract parts of a list before symbol

ut that may be overkill as simply converting to a vector if ALL parts are of the same type will work too: names(as.vector(test)) [1] "a" "b" "c" To get one at a time: names(as.vector(test))[1] [1] "a" You can do it even simple by looking at the attribute

[R] extract parts of a list before symbol

Suppose I have the following list: test <- list(a=3,b=5,c=11) I'm trying to figure out how to extract the characters to the left of the equal sign (i.e., I want to extract a list of the variable names, a, b and c. I've tried the permutations I know of involving sub - things like sub("\\=.*"

[R] interval between specific characters in a string...

Was wondering if there is an 'efficient/elegant' way to do the following (without tidyverse). Take a string abaaabbabaaab Its easy enough to count the number of times the character 'b' shows up in the string, but...what I'm looking for is outputing the 'intervals' between occurrences of '

Re: [R] conditional output of string to file n times...

Figured it out on my own. Basically, use the replicate command for each line of the data.frame, then appending to a file. On 7/6/2021 9:27 AM, Evan Cooch wrote: Suppose I have a file with the the following structure - call the two space-separated fields 'label' and 'count':

[R] conditional output of string to file n times...

Suppose I have a file with the the following structure - call the two space-separated fields 'label' and 'count': ABC 3 DDG 5 ABB 2 What I need to do is parse each line of the file, and then depending on the value of count, write out the value of 'label' to a new file, but 'count' times. In

Re: [R] problem(s) compiling RWinEdt

On 4/22/2019 2:00 PM, William Dunlap wrote: > Trying adding INSTALL_opts="--no-test-load" to your > install.packages(type="source",...) command.   This package is being > too clever in its .onAttach function. > > Bill Dunlap > TIBCO Software > wdunlap tibco.com > > Thanks -

[R] problem(s) compiling RWinEdt

[Note: if this should go to one of the other R maillists, apologies...and let me know *which* other list...] I use the WinEdt editor for ll my TeX work, and several years back, installed the RWinEdt package in R to allow me to use WinEdt as my R edtior as well. Worked, and continues to work,

Re: [R] A general question about using Bayes' Theorem for calculating the probability of The End of Human Technological Civilisation

Just curious -- if R-help is a moderated list (which  in theory , it is -- my posts have been 'modertated', to the degree that they aren't released to the list until someone approves them), and if these 'statistics discussion' questions are inappropriate to the mission (as described), then...wh

Re: [R] looking for 'tied rows' in dataframe

> index for a 1-based indexing system. > > hold=apply(test,1,which.max) > hold[apply(test,1,isUnique)==FALSE] <- 0 > hold > [1] 1 2 0 > > > >> On Mar 17, 2019, at 8:17 PM, Evan Cooch wrote: >> >> Solved -- >> >> hold=apply(test,1,which.max)

Re: [R] looking for 'tied rows' in dataframe

Solved -- hold=apply(test,1,which.max)     hold[apply(test,1,isUnique)==FALSE] <- 'T' Now, all I need to do is figure out how to get <- 'T' from turning everything in the matrix to a string. On 3/17/2019 8:00 PM, Evan Cooch wrote: Got relatively close - below:

Re: [R] looking for 'tied rows' in dataframe

Got relatively close - below: On 3/17/2019 7:39 PM, Evan Cooch wrote: Suppose I have the following sort of structure: test <- matrix(c(2,1,1,2,2,2),3,2,byrow=T) What I need to be able to do is (i) find the maximum value for each row, (ii) find the column containing the max, but (iii) if

[R] looking for 'tied rows' in dataframe

Suppose I have the following sort of structure: test <- matrix(c(2,1,1,2,2,2),3,2,byrow=T) What I need to be able to do is (i) find the maximum value for each row, (ii) find the column containing the max, but (iii) if the maximum value is a tie (in this case, all numbers of the row are the sam

Re: [R] options other than regex

Numbers -- thanks. Another clever trick. On 5/25/2018 11:54 AM, Greg Minshall wrote: > Evan, > > are you really looking at numbers, or just at character strings (that, > in your case, happen to be numbers)? if just characters, this rather > odd combination of strsplit() and Reduce() might do the

Re: [R] options other than regex

ení odpovědnosti: > https://www.precheza.cz/01-dovetek/ | This email and any documents attached > to it may be confidential and are subject to the legally binding disclaimer: > https://www.precheza.cz/en/01-disclaimer/ > >> -Original Message- >> From: R-help [mailt

[R] options other than regex

Hi -- I'm looking for alternatives to regex for a fairly simply 'reformatting' problem. Alternatives only because a lot of folks have trouble parsing/interpreting regex expressions, and I'm looking for suggestions for something more 'transparent'. Here is an example of what I'm trying to do.

Re: [R] building random matrices from vectors of random parameters

Makes sense, although (re-)learning what aperm does wasn't a wasted exercise. Thanks! On 9/28/2017 1:22 PM, Jeff Newmiller wrote: > The use of aperm is unnecessary if you call array() properly. > > ms <- array(c(rep(0, 5),so,sa*m,sa), c(5, 2, 2)) [[alternative HTML version deleted]] _

Re: [R] building random matrices from vectors of random parameters

Sure -- thanks -- only took me 3-4 attempts to get aperm to work (as opposed to really thinking hard about how it works ;-) On 9/28/2017 11:55 AM, Duncan Murdoch wrote: > On 28/09/2017 9:10 AM, Evan Cooch wrote: >> Thanks for both the mapply and array approaches! However, although &g

Re: [R] building random matrices from vectors of random parameters

> > In fact, this is what is returned by the mapply approach, while the > array approach returns the transpose. I gather the 'missing step' is > to use aperm, but haven't figured out how to get that to work...yet. ms <- array(c(rep(0, 3),sa*m,so,sa), c(3, 2, 2)) ms_new <- aperm(ms,c(1,3,2));

Re: [R] building random matrices from vectors of random parameters

Thanks for both the mapply and array approaches! However, although intended to generate the same result, they don't: # mapply approach n = 3 sa <- rnorm(n,0.8,0.1) so <- rnorm(n,0.5,0.1) m <- rnorm(n,1.2,0.1) mats = mapply(function(sa1, so1, m1) matrix(c(0,sa1*m1,so1,sa1),2,2,byrow=T), sa, so,

[R] building random matrices from vectors of random parameters

Suppose I have interest in a matrix with the following symbolic structure (specified by 3 parameters: sa, so, m): matrix(c(0,sa*m,so,sa),2,2,byrow=T) What I can't figure out is how to construct a series of matrices, where the elements/parameters are rnorm values. I'd like to construct separate

Re: [R] update numeric values of list with new values...

> test.new > $a > [1] 4 > > $b > [1] 5 > > $c > [1] 6 > > Cheers, > Bert > > > > > Bert Gunter > > "The trouble with having an open mind is that people keep coming along > and sticking things into it." > -- Opus (aka Berkele

Re: [R] update numeric values of list with new values...

Solved it: test <- list(a=1,b=2,c=3) new <- c(4,5,6) hold <- as.list(new) updated_test <- replace(test,c(1:3),hold) $a [1] 4 $b [1] 5 $c [1] 6 mean.parms <- as.list(mean.parms) mm.parms <- replace(far.parms,c(1:length(far.parms)),mean.parms) On 9/22/2017 10:34 AM

[R] update numeric values of list with new values...

Suppose I have the following: test <- list(a=1,b=2,c=3) I also have a vector (or list, or something else...) with new numbers new <- c(4,5,6) What I'm trying to figure out is how to take the list, and update the numbers from {1,2,3} to {4,5,6} So, in the end,I want the 'update' test list to

Re: [R] selecting dataframe columns based on substring of col name(s)

Thanks to all the good suggestions/solutions to the original problem. On 6/21/2017 3:28 PM, David Winsemius wrote: >> On Jun 21, 2017, at 9:11 AM, Evan Cooch wrote: >> >> Suppose I have the following sort of dataframe, where each column name has a >> common structur

[R] selecting dataframe columns based on substring of col name(s)

Suppose I have the following sort of dataframe, where each column name has a common structure: prefix, followed by a number (for this example, col1, col2, col3 and col4): d = data.frame( col1=runif(10), col2=runif(10), col3=runif(10),col4=runif(10)) What I haven't been able to suss out is h

[R] pull stat out of summary

Continuing my learning curve after 25_ years with using SAS. Want to pull the "Mean" forom the summary of something... test <- rnorm(1000,1.5,1.25) hold <- summary(test) names(hold) [1] "Min.""1st Qu." "Median" "Mean""3rd Qu." "Max." OK, so "Mean" is in there. So, is there a short fo

Re: [R] lagging over consecutive pairs of rows in dataframe

diff(rslt)) Or with base R aggregate(mydata, by = list(group = mydata$exp), FUN = diff) HTH Ulrik On Fri, 17 Mar 2017 at 17:34 Evan Cooch wrote: Suppose I have a dataframe that looks like the following: n=2 mydata <- data.frame(exp = rep(1:5,each=n), rslt = c(12,15,7,8,24,28,33,15,22,11

Re: [R] lagging over consecutive pairs of rows in dataframe

by = list(group = mydata$exp), FUN = diff) HTH Ulrik On Fri, 17 Mar 2017 at 17:34 Evan Cooch wrote: Suppose I have a dataframe that looks like the following: n=2 mydata <- data.frame(exp = rep(1:5,each=n), rslt = c(12,15,7,8,24,28,33,15,22,11)) mydata exp rslt 11 12 21 15

Re: [R] lagging over consecutive pairs of rows in dataframe

On 3/17/2017 12:58 PM, Ulrik Stervbo wrote: > Hi Evan > > you can easily do this by applying diff() to each exp group. > > Either using dplyr: > library(dplyr) > mydata %>% > group_by(exp) %>% > summarise(difference = diff(rslt)) > > Or with base R > aggregate(mydata, by = list(group = mydata

[R] lagging over consecutive pairs of rows in dataframe

Suppose I have a dataframe that looks like the following: n=2 mydata <- data.frame(exp = rep(1:5,each=n), rslt = c(12,15,7,8,24,28,33,15,22,11)) mydata exp rslt 11 12 21 15 327 428 53 24 63 28 74 33 84 15 95 22 10 5 11 The variabl

Re: [R] matrix merge, or something else?

Slick -- thanks. On 3/10/2017 1:26 AM, Jeff Newmiller wrote: test2[ , colnames( test1 ) ] <- test1 __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http

Re: [R] concatenating range of columns in dataframe

On 3/10/2017 2:24 AM, Ulrik Stervbo wrote: Hi Evan, the unite function of the tidyr package achieves the same as Jim suggested, but in perhaps a slightly more readable manner. Ulrik I use perl for scripting, so readability isn't a big factor. ;-) Thanks! ___

Re: [R] concatenating range of columns in dataframe

On 3/10/2017 1:48 AM, Jim Lemon wrote: Hi Evan, How about this: df2<-data.frame(Trt=df[,1],Conc=apply(df[,2:5],1,paste,sep="",collapse="")) Jim Thanks! __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/m

Re: [R] concatenating range of columns in dataframe

On 3/10/2017 2:23 AM, Bert Gunter wrote: I think you need to spend some time with an R tutorial or two, especially with regard to indexing. Unless I have misunderstood (apologies if I have), df$Conc <- apply(df[,-1],1,paste,collapse="") does it. -- Bert \ Thanks -- sage advice. ___

[R] concatenating range of columns in dataframe

Suppose I have the following data frame (call it df): Trt y1 y2 y3 y4 A1A 1001 A1B 1100 A1 C 0 10 1 A1D 111 1 What I want to do is concatenate columns y1 -> y4 into a contiguous string (which I'll call df$conc), so that the final df looks l

[R] matrix merge, or something else?

Suppose I have the following two matrices, both with same number of rows (3), but different number of columns (3 in test1, 4 in test2). test1 <- matrix(c(1,1,0,1,0,-1,-1,-1,0),3,3,byrow=T); test2 <- matrix( rep( 0, len=12), nrow = 3) I label the rows and columns of the two matrices as follows:

Re: [R] evaluating function over seq of values

Note that in your likelihood function, N can be a vector of values, so you can compute the likelihood for all values of N and just access the value you want via subscripting rather than repeatedly computing it for different N's. OK -- that is the part I'm stuck at - pointers to how to do preci

[R] evaluating function over seq of values

The MWE (below) shows what I'm hoping to get some help with: step 1\ specify the likelihood expression I want to evaluate using a brute-force grid search (not that I would do this in practice, but it is a convenient approach to explain the idea in a class...). step 2\ want to evaluate the lik

Re: [R] creating lists of random matrices

>> >> Hi, >> >> See ?replicate >> >> Example: >> >> ## Create a list of 5 2x2 matrices > > > Sorry, correction on my reply. > > I copied the wrong output, It should be: > > > replicate(5, matrix(rnorm(4), 2, 2), simplify = FALSE) > Perfect does the trick. Thanks also for the lapply solutions fro

[R] creating lists of random matrices

So, its easy enough to create a random matrix, using something like (say) matrix(rnorm(4),2,2) which generates a (2x2) matrix with random N(0,1) in each cell. But, what I need to be able to do is create a 'list' of such random matrices, where the length of the list (i.e., the number of said ra

Re: [R] problems compiling packages | 3.3.0 | Linux

OK -- thanks. I used to compile from source routinely, but could never get thee 'hand rolled' version of R to play nice with some external applications (specifically, jags, and openbugs). On 6/2/2016 5:41 PM, Marc Schwartz wrote: On Jun 2, 2016, at 10:35 AM, Evan Cooch wrote: Up

[R] problems compiling packages | 3.3.0 | Linux

Updated my R install on my GNU/Linux boxes (running RHEL 6.xx), using latest from CRAN (i.e., not compiling from source), and while said upgrade seemed to go fine, am having all sorts of problems with getting some packages to compile (either during an initial install attempt, or upgrade to exis

Re: [R] embedding expression into title in R plot

On 1/11/2016 2:08 PM, William Dunlap wrote: I tend to use bquote, as in x_label <- bquote(bold(species) ~ (italic(N1))) plot(1:10,main=bquote("This is the expression for" ~ .(x_label) * "!")) Thanks -- I thought I'd tried something very close to this in my various attempts, but it

Re: [R] different coloured axis title labels for different axes

On 1/11/2016 1:54 PM, William Dunlap wrote: The following shows how to get different colors for most features of a scatterplot: plot(1:11,log(1:11),ann=FALSE,axes=FALSE,col="pink",pch=16) box(col="gray") title(xlab="X Axis Label", col.lab="light blue") title(ylab="Y Axis Label", col.lab="light

Re: [R] embedding expression into title in R plot

David -- On 1/11/2016 1:01 PM, David Winsemius wrote: On Jan 11, 2016, at 7:59 AM, Evan Cooch wrote: Suppose I've specified that the xlab for a plot is expression(bold(species~(italic(N1 In other words, I want the axis label to be bold, italic 'species (N1)' Now, I wan

[R] embedding expression into title in R plot

Suppose I've specified that the xlab for a plot is expression(bold(species~(italic(N1 In other words, I want the axis label to be bold, italic 'species (N1)' Now, I want the title for the plot to be have this label embedded in the title. Say, 'This is the plot for Species (N1)'. For a var

[R] different coloured axis title labels for different axes

Consider a simple plot of X vs Y. There are elements on the plot that represent X, or Y, that are presented in different colours (say, blue for X, red for Y). Rather than use a legend, I would like to have the title label for the X-axis be in blue, and the title label for the Y-axis be in re

[R] column means dropping column minimum

Suppose I have something like the following dataframe: samp1 <- c(60,50,20,90) samp2 <- c(60,60,90,58) samp3 <- c(25,65,65,90) test <- data.frame(samp1,samp2,samp3) I want to calculate column means. Easy enough, if I want to use all the data within each column: print(colMeans(test),na.rm =

Re: [R] JAGS 4.x, rjags 4.x problems | Linux

On 11/5/2015 9:45 AM, Rainer Hurling wrote: Am 04.11.2015 um 21:36 schrieb Evan Cooch: On 11/4/2015 2:08 PM, Evan Cooch wrote: Greetings -- This has also been posted on the jags forum, but since I suspect the problem is more 'R-related' than jags, will aos post here. Decided t

Re: [R] JAGS 4.x, rjags 4.x problems | Linux -- solved

Well, sort of. I got sufficiently frustrated that I completely uninstalled R, jags, and everything related. Did a re-install using only versions of R nd JAGS found in the epel repo. No muss, no muss -- all works. Out of curiosity, uninstalled again, and tried my usual sequence of manually com

Re: [R] JAGS 4.x, rjags 4.x problems | Linux

On 11/4/2015 3:31 PM, Yvan Richard wrote: Hi Evan The last version of rjags on CRAN is 4.4. Have you tried it? http://cran.stat.auckland.ac.nz/web/packages/rjags/index.html I did have the same problem before updating it, but it now works on my Ubuntu with the new JAGS version. Cheers, -Yvan

Re: [R] JAGS 4.x, rjags 4.x problems | Linux

On 11/4/2015 2:08 PM, Evan Cooch wrote: Greetings -- This has also been posted on the jags forum, but since I suspect the problem is more 'R-related' than jags, will aos post here. Decided to 'upgrade' from jags 3.x.x to 4.x.x today, on my GNU/Linux boxes (which run la

Re: [R] JAGS 4.x, rjags 4.x problems | Linux

installed. Seem reasonable? Not sure what to do about it, but... On 11/4/2015 3:42 PM, Evan Cooch wrote: On 11/4/2015 3:31 PM, Yvan Richard wrote: Hi Evan The last version of rjags on CRAN is 4.4. Have you tried it? http://cran.stat.auckland.ac.nz/web/packages/rjags/index.html I did have the

[R] JAGS 4.x, rjags 4.x problems | Linux

Greetings -- This has also been posted on the jags forum, but since I suspect the problem is more 'R-related' than jags, will aos post here. Decided to 'upgrade' from jags 3.x.x to 4.x.x today, on my GNU/Linux boxes (which run latest RHEL). Here are the basic details: 1\ used R 3.2.2 compil

Re: [R] 'strange' R graphics problem | Linux...

phics display. I have R 3.1.1 installed on my Ubuntu 14.04 > machine, that, as expected I have not had any problems with... I tried > to install 3.2.2 and 3.2.1 from source and got a very strange compile > error, which I need to sort out -- recompiling 3.1.1 failed as well... &g

Re: [R] 'strange' R graphics problem | Linux...

On 10/14/2015 4:00 PM, Evan Cooch wrote: > > > On 10/14/2015 3:51 PM, Thomas Adams wrote: >> Evan, >> >> I have Ubuntu 14.04 and 15.10 at home and have not had problems, but >> I don't think I've been using R 3.2.2 — I'll try this evening. > &g

Re: [R] 'strange' R graphics problem | Linux...

t. > Thanks very much. I have a couple of Linux Mint 17.x systems as well -- I'll see if they throw the same problem at me/us. > Tom > > On Wed, Oct 14, 2015 at 8:36 AM, Evan Cooch <mailto:evan.co...@gmail.com>> wrote: > > So, am running 3.2.2 on a Centos 6.xx bo

Re: [R] 'strange' R graphics problem | Linux...

for chuckles, roll back to 3.2.1, and see what happens. > > Tom > > On Wed, Oct 14, 2015 at 2:47 PM, Evan Cooch <mailto:evan.co...@gmail.com>> wrote: > > Tom -- > > On 10/14/2015 3:35 PM, Thomas Adams wrote: >> Evan, >> >> N

Re: [R] 'strange' R graphics problem | Linux...

TRUE FALSE http/ftp sockets libxmlfifo cledit iconv TRUETRUETRUETRUETRUE TRUE NLS profmem cairo ICU long.double libcurl TRUE FALSETRUETRUETRUE FALSE On 10/14/2015

[R] 'strange' R graphics problem | Linux...

So, am running 3.2.2 on a Centos 6.xx box. Code executes fine, but I'm having a heck of a time with graphics. I don't think this is related to R in the broad sense, but how it is interacting with graphics on the system. here is a description of the problem. 1\ something simple: test <- rnorm(

[R] extracting every nth character from a string...

Suppose I had the following string, which has length of integer multiple of some value n. So, say n=2, and the example string has a length of (2x4) = 8 characters. str <- "ABCDEFGH" What I'm trying to figure out is a simple, base-R coded way (which I heuristically call StrSubset in the follo

Re: [R] specifying dimensions of a graphic (not the window...)

On 2/8/2015 7:41 PM, Evan Cooch wrote: > Greetings -- > > Graphics newbie (I generally don't use R for graphics, so if the > question is 'obvious', point that out gently ;-) > > I'm trying to use levelplot in the lattice package, to generate what > I&

[R] specifying dimensions of a graphic (not the window...)

Greetings -- Graphics newbie (I generally don't use R for graphics, so if the question is 'obvious', point that out gently ;-) I'm trying to use levelplot in the lattice package, to generate what I'll call a 'decision table', where optimal decisions (discrete, on the interval [0.0,0.5] by incr

Re: [R] naming rows/columns in 'array of matrices' | solved

The (obvious, after the fact) solution at the bottom. D'oh... On 1/30/2015 2:07 PM, Evan Cooch wrote: Suppose I have the following situation: I have an array of 2 matrices, where each matrix is (2x2): P <- array(0, c(2,2,2)) P[,,1] <- matrix(c(1,2,3,4),2,2,byrow=T); P[,,2]

[R] naming rows/columns in 'array of matrices'

Suppose I have the following situation: I have an array of 2 matrices, where each matrix is (2x2): P <- array(0, c(2,2,2)) P[,,1] <- matrix(c(1,2,3,4),2,2,byrow=T); P[,,2] <- matrix(c(5,6,7,8),2,2,byrow=T); I want to label rows and columns of each matrix in the array, such that P would look l

Re: [R] cbind in a loop...better way? | summary

Thanks! On 10/9/2014 1:52 PM, David L Carlson wrote: Actually Jeff Laake's can be made even shorter with sapply(mat_list, as.vector) David C -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Evan Cooch Sent: Thursday, Octo

Re: [R] cbind in a loop...better way? | summary

) + David Carlson (1) for their suggestions. On 10/8/2014 3:12 PM, Evan Cooch wrote: ...or some such. I'm trying to work up a function wherein the user passes a list of matrices to the function, which then (1) takes each matrix, (2) performs an operation to 'vectorize' the matrix (i.e.,

Re: [R] cbind in a loop...better way?

ion, TX 77840-4352 > > -Original Message- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On > Behalf Of Evan Cooch > Sent: Wednesday, October 8, 2014 2:13 PM > To: r-help@r-project.org > Subject: [R] cbind in a loop...better way? > > .

[R] cbind in a loop...better way?

...or some such. I'm trying to work up a function wherein the user passes a list of matrices to the function, which then (1) takes each matrix, (2) performs an operation to 'vectorize' the matrix (i.e., given an (m x n) matrix x, this produces the vector Y of length m*n that contains the colum

Re: [R] optim, L-BFGS-B | constrained bounds on parms?

You could also use Rvmmin that has bounds, or nmkb from dfoptim (though you cannot start on bounds). One 'negative' for dfoptim is that is doesn't automatically generate the Hessian (as far as I can tell). Rather nice to be able to do so for other calculations that usual follow after the op

Re: [R] optim, L-BFGS-B | constrained bounds on parms?

On 9/19/2014 11:32 AM, Prof J C Nash (U30A) wrote: One choice is to add a penalty to the objective to enforce the constraint(s) along with bounds to keep the parameters from going wild. This generally works reasonably well. Sometimes it helps to run just a few iterations with a big penalty sca

[R] optim, L-BFGS-B | constrained bounds on parms?

Or, something to that effect. Following is an example of what I'm working with basic ABO blood type ML estimation from observed type (phenotypic) frequencies. First, I generate a log-likelihood function. mu[1] -> mu[2] are allele freqs for A and B alleles, respectively. Since freq of O allele i

Re: [R] help using extrafont package | R graphics

"Garamond", type = "n") > text(1, 1, "Some Text", cex = 5) > showtext.end() > dev.off() > > > A more detailed introduction of the showtext package is available at > http://statr.me/2014/01/using-system-fonts-in-r-graphs/. Hope this > would be

[R] help using extrafont package | R graphics

Greetings -- Submitted this a little while ago -- for some reason, still being held up by the moderator. Trying again... For a host of reasons, I need to use/embed Garamond font with various R graphics for a particular publication. I've figured out how to more or less get there from here, usi

[R] extrafont query | importing only 1 TTF

Greetings -- For a host of reasons, I need to use/embed Garamond font with various graphics for a particular publication. I've figured out how to more or less get there from here, using the following sequence: library(extrafont) Then, I need to import the system fonts (Windoze box). So, I us

Re: [R] R2winBUGS & WinBUGS gui

> > Yes, sure, and indeed, it is a shame that nobody of those people who > want it to work under Linux is trying to submit patches to make it work. > > > I agree, but I *think* the primary reason for this is that it requires installing Blackbox as a PASCAL compiler. For much of the Linux commun

Re: [R] R2winBUGS & WinBUGS gui

> > No. The idea is to use BRugs, i.e. OpenBUGS in such cases. If OpenBUGS > lacks some features, you are certainly welcome to implement them and > send patches to Andrew Thomas. > Just finished trying the install of openBUGS under linux yet again. Same problems (more or less), which I'll list

Re: [R] R2winBUGS & WinBUGS gui

> > No. The idea is to use BRugs, i.e. OpenBUGS in such cases. If OpenBUGS > lacks some features, you are certainly welcome to implement them and > send patches to Andrew Thomas. > > Thanks very much. I thought as much, but given that I have had a 0% success rate in getting OpenBUGS to run on

[R] R2winBUGS | option to turn off GUI?

Greetings - I run a multi-pro server box (GNU/Linux), on which I've installed winBUGS under wine. Works fine, and plays nice with r2WinBUGS, provided everything is done through a graphical front-end (either by working from console, or using a virtual desktop via VNC or equivalent). However, I'

[R] R2winBUGS & WinBUGS gui

I am trying to figure out if it is possible to run winBUGS from within R, using R2winBUGS, without having winBUGS spawn any windows (basically - 'true' batch - no GUI actions at all). The reason being I have a machine which I (and several others) ssh/telnet into, and would like to run winBUGS w

Re: [R] really dumb question | loop counters in

Duncan Murdoch wrote: > On 21/09/2007 6:54 PM, Evan Cooch wrote: >> Thanks, but there is nothing in section 9.2.2 that mentions >> seq(x,y,z) or anything close in a for loop. All it says is (basically): >> >> >> There is also a for loop construction whic

Re: [R] really dumb question | loop counters in

x27;, with an example, I'll stand corrected. Duncan Murdoch wrote: > On 21/09/2007 4:20 PM, Evan Cooch wrote: >> Paul Hiemstra wrote: >>> Hi, >>> >>> This works: >>> >>> for(i in seq(1,100,5)) { >>> print(i) >>> } >>

Re: [R] really dumb question | loop counters in

Paul Hiemstra wrote: > Hi, > > This works: > > for(i in seq(1,100,5)) { > print(i) > } > > Very similar to the way python does this kind of loop. > Indeed it is - thanks for the tip. I'm still puzzled why I can't find a single piece of the standard [R] language documentation that shows this. In

Re: [R] really dumb question | loop counters in

Thanks. And thanks for the C-style tip. Greg Snow wrote: > Try: > > for(x in seq(0,1,by=0.01)) { > print(x) > } > > The for loop in S/R is what some languages call a foreach loop, you need > to provide a vector of the values to loop over. > > If you really want a C style for loop, then just realiz

[R] really dumb question | loop counters in

Basically new to [R] - as a programming environment at least (had lots of recent experience compiling it on our Opteron-based servers). Was trying to write some simple little scripts (in advance of porting over some bigger things from other environments - like MATLAB), when I realized that hand