Hi,
Suppose I have a the data frame given by:
> dput(toy.df)
structure(list(id = c(1, 2, 1, 2), time = c(1L, 1L, 2L, 2L),
value = c(1, 2, 2, 3)), .Names = c("id", "time", "value"), row.names = c(NA,
4L), class = "data.frame")
that is:
> toy.df
id time value
1 11 1
2 21 2
3
t; #0.1091573 1.000
>
> A.K.
>
>
> On Saturday, February 15, 2014 3:19 PM, David Romano
> wrote:
> Hi folks,
>
> I'm having trouble with code that used to work, and I can't figure out
> what's going wrong. I'd be grateful for any help in sortin
Hi folks,
I'm having trouble with code that used to work, and I can't figure out
what's going wrong. I'd be grateful for any help in sorting this out.
Suppose I define a matrix
> mm <- matrix(1:15, 25,2)
and compare the first 15 values of column 1 of mm to the values remaining
in the same colum
in advance for you help,
David
On Fri, May 3, 2013 at 4:56 PM, David Romano wrote:
> Hi everyone,
>
> I'm trying to use apply (with a call to zoo's rollapply within) on the
> columns of a 1.5Kx165K matrix, and I'd like to make use of the other cores
> on my machine
(I neglected to use reply-all.)
-- Forwarded message --
From: David Romano
Date: Sat, May 4, 2013 at 11:25 AM
Subject: Re: [R] how to parallelize 'apply' across multiple cores on a Mac
To: Charles Berry
On Sat, May 4, 2013 at 9:32 AM, Charles Berry wrote:
> Davi
t; Research Engineer (Solar/BatteriesO.O#. #.O#. with
> /Software/Embedded Controllers) .OO#. .OO#. rocks...1k
> ---
> Sent from my phone. Please excuse my brevity.
>
> Da
Hi everyone,
I have large data frame, say df1, with 165K columns, and all but the first
four columns of df1 are numeric. I transformed the numeric data and
obtained a matrix, call it data.m, with 165K - 4 columns, and then tried to
create a second data frame by replacing the numeric columns of
Hi everyone,
I'm trying to use apply (with a call to zoo's rollapply within) on the
columns of a 1.5Kx165K matrix, and I'd like to make use of the other cores
on my machine to speed it up. (And hopefully also leave more memory free: I
find that after I create a big object like this, I have to save
Sorry, this was meant to go to the full list. -David
On Sun, Feb 10, 2013 at 2:15 PM, David Romano wrote:
>
>
> On Sun, Feb 10, 2013 at 1:59 PM, Bert Gunter wrote:
>
>> Please read the Help before posting.
>>
>> ?"$" says:
>>
>
> It helps to
On Sun, Feb 10, 2013 at 1:40 PM, Duncan Murdoch wrote:
> On 13-02-10 4:06 PM, David Romano wrote:
>
>> Hi everyone,
>>
>> I ran into the issue below while trying to execute a command of the form
>>
>> apply(list.names,1, function(x) F(favorite.list$x) )
&
Hi everyone,
I ran into the issue below while trying to execute a command of the form
apply(list.names,1, function(x) F(favorite.list$x) )
where list.names is a character vector containing the names of the elements
of favorite.list and F is some function defined on a list element.
Namely, the
On Sat, Feb 9, 2013 at 11:43 AM, Uwe Ligges wrote:
>
>
> On 08.02.2013 20:14, David Romano wrote:
>
>> Hi everyone,
>>
>> I'm not exactly sure how to ask this question most clearly, but I hope
>> that
>> giving the context in which it occurs for me
e same, but with the first lda scores, so I
have the same questions about lda directions, too.
Any light you could shed on these questions would be very welcome!
Thanks in advance,
David Romano
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R-help@r-
ze for having missed
it.As to the "variables collinear" warning, it's still not clear to me
what level of correlation will trigger it.
My apologies,
David
On Wed, Feb 6, 2013 at 12:21 PM, David Romano wrote:
> Hi everyone,
>
> I'm trying to vectorize an applicat
Hi everyone,
I'm trying to vectorize an application of lda to each 2D slice of a 3D
array, but am running into trouble: It seems there are quite a few 2D
slices that trigger either the "variables are collinear" warning, or worse,
trigger a "variable appears to be constant within groups" error and
2,list)
>
> mapply("%*%",mlist,vlist[1:2],SIMPLIFY=FALSE)
> #[[1]]
> #[,1]
> #[1,] 19
> #[2,] 22
> #[3,] 25
> #[4,] 28
> #
> #[[2]]
> #[,1]
> #[1,] 67
> #[2,] 74
> #[3,] 81
> #[4,] 88
>
> A.K.
> - Original Mes
Hi everyone,
I'd like to be able to apply lda to each 2D matrix slice of a 3D array, and
then use the scalings to obtain the corresponding lda scores.
I can use 'apply' to get a list of the lda output for each 2D slice, and
can create a list of the resulting scalings, but I'm not sure how to
mult
t;
>
> For the column numbers you can do
>
> colnums <- which(colidx)
>
> Hope this helps,
>
> Rui Barradas
>
> Em 12-12-2012 17:14, David Romano escreveu:
>>
>> Hi everyone,
>>
>> Suppose I have a 3D array of datasets, where say dimension 1 corr
Sorry, I just realized I didn't send the message below in plain text.
-David Romano
On Wed, Dec 12, 2012 at 9:14 AM, David Romano wrote:
>
> Hi everyone,
>
> Suppose I have a 3D array of datasets, where say dimension 1 corresponds
> to cases, dimension 2 to datasets
27;m not sure how to produce.
My second question is: 2) Having answered question 1), now suppose there
may be datasets containing NA value -- how could I select the subset of
values from dimension 2 corresponding to the datasets for which this is
true (again using *apply?)?
Thanks in advance for any lig
On Tue, Dec 4, 2012 at 2:12 PM, David Romano wrote:
>
>
> On Tue, Dec 4, 2012 at 10:22 AM, Duncan Murdoch
> wrote:
>
>> On 04/12/2012 12:54 PM, David Romano wrote:
>>
>>> Hi everyone,
>>>
>>> I normally include a call to browser() as I'
avior is the following:
file bugcheck.r:
browser()
a <- 1
b <- 2
> source("bugcheck.r")
Called from: eval(expr, envir, enclos)
Browse[1]>
>
> ls()
[1] "a" "b"
> a
[1] 1
> b
[1] 2
I'd be gratefu
at 6:46 AM, Bert Gunter wrote:
> David:
>
> You seem to be getting lost in basic R tasks. Have you read the Intro
> to R tutorial? If not, do so, as this should tell you how to do what
> you need. If so, re-read the sections on indexing ("["), replacement,
> and NA's.
data frame into a vector-like list of elements (which
I would hope would work).
I'd be grateful for any suggestions!
Thanks,
David Romano
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by replacing the anonymous function by c, we obtain a more elegant but
more wasteful solution.
Thanks again for everyone's help,
David Romano
On Fri, Sep 7, 2012 at 11:12 AM, David Romano wrote:
> Hi folks,
>
> Suppose I create the character vector charvec by
>
> > cha
splitlist
[[1]]
[1] "a1" "b1"
[[2]]
[1] "a2" "b2"
I was wondering whether there is already a function which can extract
the "a" and "b" parts of the list splitlist; that is, that can return
the same vectors as those created by c("a1&q
I need to multiply to very large, nonsparse matrices, and so get the
error "allocMatrix: too many elements specified".
Is there a way to set the limit for allocMatrix?
In my case, the two matrices, A and B, are nxm and mxp where m is
small, so I could subdivide each into blocks of submatrices
A=r
On Sun, Jul 29, 2012 at 7:08 AM, R. Michael Weylandt <
michael.weyla...@gmail.com> wrote:
> On Sat, Jul 28, 2012 at 10:48 AM, David Romano
> wrote:
> > Context: I'm relatively new to R and am working with very large
> datasets.
> >
> > General problem: I
uot;mat")' retrieves
no objects. Why is this?
I'd be grateful for any help on either my specific questions, or
suggestions of a better ways to address the issue of limited memory.
Thanks,
David Romano
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