Try this
pdf("~/graph.pdf")
par(mar=c(8, 4, 4, 2))
barplot(d2, legend= c("SYCL", "CUDA"), beside=
TRUE,las=2,cex.axis=0.7,cex.names=0.7,ylim=c(0,80), col=c("#9e9ac8",
"#6a51a3"))
dev.off()
See ?par to see the details for adjusting margins and other plot features.
David
On Tue, Jun 13, 2023 at 5
Your first data column appears to contain character data (e.g. SYCL) which
cannot be converted to numeric. You also appear to have 0's in the numeric
columns which will cause problems since log(0) is -Inf. Barplots are useful
for categorical data, but not continuous, numeric data which are better
h
Could you have columns that are not character or integer so that y is never
defined in the function?
count1a(1:5/3)
Error in count1a(1:5/3) : object 'y' not found
David Carlson
On Mon, Aug 8, 2022 at 1:35 PM Erin Hodgess wrote:
> OK. I'm back again. So my test1.df is 236x390 If I put in
Here is one way to get the table you are describing. First some made up data:
dta <- structure(list(tree = c(27, 47, 33, 31, 45, 54, 47, 27, 33, 26,
14, 43, 36, 0, 29, 24, 43, 38, 32, 21, 21, 23, 12, 42, 34), shrub = c(19,
29, 27, 31, 5, 24, 6, 37, 4, 6, 59, 7, 23, 15, 32, 1, 31, 37,
30, 44, 40, 1
Just use
names(unlist(df[, "VarY", drop=FALSE]))
# [1] "VarY1" "VarY2" "VarY3" "VarY4" "VarY5"
When you extract a single column from a data frame it converts it to a
vector by default.
David L Carlson
On Fri, May 6, 2022 at 1:05 PM Hooiveld, Guido
wrote:
> Dear all, I wrote a some code in wh
You can't get exactly what you want with base graphics, but you can get
close by defining line types and colors outside the plot command:
x <- seq(-3, 3, by = 0.01)
lns <- 1:2
clr <- 1:2
matplot(x, cbind(x, x^2), type="l", lty=lns, col=clr)
legend("bottomright", legend = c("x", expression(x^2)), l
Sorry, The last three lines should read:
all <- apply(results, 1, function(x) length(intersect(x,
seq(sides)))==sides)
sum(all)/reps
results <- as.data.frame(results)
To generalize them for values of sides other than 6.
On Fri, Apr 22, 2022 at 11:05 PM Paul Bernal wrote:
> Thank you so much Da
You need to add "-": ` (dat3 <- dat1[-unique(c(BadName, BadAge,
BadWeight)), ])` which makes the command NOT).
David
On Sun, Jan 30, 2022 at 11:00 AM Val wrote:
> Thank you David. What about if I want to list the excluded rows? I used
> this (dat3 <- dat1[unique(c(BadName, BadAge, BadWeight
It is possible that there would be errors on the same row for different
columns. This does not happen in your example. If row 4 was "John6, 3BC,
175X" then row 4 would be included 3 times, but we only need to remove it
once. Removing the duplicates is not necessary since R would not get
confused, b
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