~ 113, data = NAMA) :
Very few studies. Solution may be unstable.
Thanks for your help,
Damien
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r
om the output I am
using:
f2c@concomitant@coef
However, how do I know which variables are significant?
Any help is welcomed!
Best
Damien
--
View this message in context:
http://r.789695.n4.nabble.com/flexmix-concomitant-model-and-significance-of-variables-tp4712809.html
Sent from the R help m
em is that it will take me more than a
month to run it.
Is there a way to increment with the first code I used or a way of running
the second code faster (I have more than 1 million rows)
Thanks!
Cheers,
Damien
[[alternative HTML version deleted]]
_
ters function.. and so on..
Does someone know if it's possible to do it?
Is it possible to define by myself the html/00index.html file that will
be use in my package?
If it's not possible, how could I add the alphabetic subsections that
exist in most of package
Hi,
I would obtain a random value between two (for example between 40.15 and 56.58
I would have only one value).
I'm looking for a package/a function which could do this.
Could anybody help me please?
Cordialement
Damien Landais
__
R-h
I'm running R 2.9.1 on winXP, using the library plyr.
Can anyone explain to me what is going wrong in this code? (in particular
see lines marked with **) Trying to modify objects in a list
created using dlply seems to corrupt the objects in the list.
> library(plyr)
> d=as.data.fr
he problem remain, try get help with the colleagues.
>
> best
>
> milton
>
> On Thu, Jul 9, 2009 at 10:58 AM, Damien Moore wrote:
>
>> Hi List
>>
>> I'm having difficulty understanding how plm should work with dynamic
>> formulas. See the comman
Hi List
I'm having difficulty understanding how plm should work with dynamic
formulas. See the commands and output below on a standard data set. Notice
that the first summary(plm(...)) call returns the same result as the second
(it shouldn't if it actually uses the lagged variable requested). The
2
0 0 4
0 0 6
0 0 8
0 0 10
0 4 0
0 4 2
...
Could anybody help me?
I don't work on a special package to do it...
Thanks
Cordialement
Damien Landais
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/
ot;z","E","taille")
g=gstat(id="zinc",formula=mydata[,4]~1,locations=~x+y+z,data=mydata)
g.var=variogram(g,cutoff=2500,width=100)
modele=vgm(model="Exp",range=2000)
vario=fit.variogram(g.var,modele)
Thanks!
Cordialement
Damien Landais
___
Hi,
I would know how to plot two variograms on a same graph. I can plot one by one
but I would draw both on the same one.
Is it possible? Do i need any special package?
Thanks!
Cordialement
Damien Landais
__
R-help@r-project.org mailing list
https
On 8 Sep, 20:15, Prof Brian Ripley <[EMAIL PROTECTED]> wrote:
> On Mon, 8 Sep 2008, Damien wrote:
> > Hi all,
>
> > I'm looking into opening an url on a server which requires
> >authentication.
>
> > After failing to find some kind of connection str
René Sachse wrote:
> Damien schrieb:
>
> > I'm looking into opening an url on a server which requires
> >authentication.
>
> Under a Windows Operating System you could try to start R with the
> --internet2 option. This worked in my case.
Thanks René it did the
url string fed to the web server?
Thanks,
Damien
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
14 matches
Mail list logo