me.
Many thanks again,
Colin.
-Original Message-
From: Uwe Ligges [mailto:lig...@statistik.tu-dortmund.de]
Sent: 14 January 2010 14:06
To: Colin Millar
Cc: Gabor Grothendieck; r-help@r-project.org
Subject: Re: [R] R package dependencies
For the original question:
> what are a packa
lapply(fnames, function(x) {download.file(x, tmpf); unzip(tmpf,
list = TRUE)})
ndlls <- sapply(pkg.contents, function(x) sum( grepl( ".dll", x $ Name )))
pkg.summ <- data.frame(pkg = rownames(available), dll = ndlls)
Thanks again,
Colin.
From: Ga
Hi there,
My question relates to getting information about R packages. In particular i
would like to be able to find from within R:
what are a packages dependencies
what are a packages reverse dependencies
does a package contain a dll
The reason i ask is:
The organisation that i work
@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Colin Millar
Sent: 27 November 2009 16:41
To: Anastasia; r-help@r-project.org
Subject: Re: [R] Simple Function doesn't work?
Hi,
You would also make your code more efficient and possible more readable
by doing
ReturnsGrid
Hi,
You would also make your code more efficient and possible more readable
by doing
ReturnsGrid <-
function(x, y, m)
{
x + (seq.int(m) - 1) * (y - x) / m
}
(xx <- ReturnsGrid(0, 9, 3))
#[1] 0 3 6
And if you want to supply vector x and y you could do something like
(there are probably better
And if you want to do both do
invisible( lapply(c("scrn","dx"), aar) )
but I think you will have to use multiple ifs rather than switch if you
intend to add more functionality...
.
.
.
I think you just missed some commas out...
aar <-
function(command = c("scrn", "dx", "df")) {
command <-
I think you just missed some commas out...
aar <-
function(command = c("scrn", "dx", "df"))
{
command <- match.arg(command)
switch(command,
scrn = cat("scrn :Screening","\n"),
dx = cat("dx:Diagnosis","\n"),
df = cat("df:Don't Forget","\n")
)
}
Colin.
Ps you don'
Hi,
try ?table
# for example
(s3 <- table(s))
# and if you want a single value
s3["a"]
# or
s3[1]
HTH,
Colin.
From: r-help-boun...@r-project.org on behalf of Marc Giombetti
Sent: Tue 17/11/2009 22:55
To: r-help@r-project.org
Subject: [R] Basic ques
-help-boun...@r-project.org]
On Behalf Of Colin Millar
Sent: 17 November 2009 16:10
To: Zhiyuan Jason ZHENG; r-h...@stat.math.ethz.ch
Subject: Re: [R] Calculating the power of a negative number
Hi,
Look at
?NumericConstants
At the bottom of the details section you will find:
"Note t
Hi,
Look at
?NumericConstants
At the bottom of the details section you will find:
"Note that a leading plus or minus is not regarded by the parser as part
of a numeric constant but as a unary operator applied to the constant."
See
?Syntax
for precedence information.
Hope this helps,
Co
Or alternatively store as a list and export later if you want
... after some tidying ...
library(lattice)
columns <- 8:153
plots <- vector("list", length(columns))
j <- 0
for (i in columns)
{
plots[[ j <- j+1 ]] <-
histogram( ~ data[,i] | data[,2],
ylab = "Frequency", xlab = "S
Sounds like a homework question ...
if y = a + bx + e, where e ~ N(0, sigma^2)
the log likelihood of the slope parameter and intercept parameters, a and b,
and variance sigma^2 given n data points y and covariates x is
f(a,b, sigma; y, x) = -0.5*n*log(2 * pi) - n*log(sigma) - 0.5 / sigma^2
A quick google on 'normality test' (no quotes) gives
http://en.wikipedia.org/wiki/Normality_test. This gives you a few more tests
than the KS test.
Cheers,
Colin.
Steve Lianoglou wrote:
> Hi,
>
> I think you can also use a qq-plot to do the same, no? You won't get a
> statistic score + p.valu
Hi,
This should work - head is quite a usefull summary function
head(df.mydata[df.mydata$A=="X" & df.mydata$C < 2, ],3)
Colin.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Noah Silverman
Sent: 26 August 2009 10:54
To: ottorin
Or perhaps use a temporary vector might be neater?
tmp <- with(df.mydata, B[A=="X" & C < 2])
df.mydata[order(tmp) %in% 1:3,] # gives df with highest three values of B
or
head(df.mydata[order(tmp),],3) # gives first 3 rows of df sorted by B
Colin.
-Original Message-
From: r-help-boun..
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