This question is about column names returned by the aggregate function.
Consider the following example
df <- data.frame(
id = c(rep('11',30),rep('22',30),rep('33',30)),
value = c(rnorm(30,2,0.5), rnorm(30,3,0.5), rnorm(30,6,0.5))
)
aggregate(df[,c("value"),drop=FALSE], by=list(id=df$id), m
Thank you both for your response. As the names suggest, I am plotting the
sales & price data for items over time to understand the how certain items may
be more responsive than others to price changes.
Another way of displaying this information on the same chart as the one showing
sales, would
I am trying to plot this dataset using ggplot2:
df <- data.frame(
sid = c(rep('11',30),rep('22',30)),
time = rep(ISOdate(year = 2010, month = 1, day = 1:30),2),
sales = c(rnorm(30, 1000, 20),rnorm(30, 900, 10)),
price = c(rnorm(30, 2, 0.5),rnorm(30, 3,0.5))
)
Plotting just the sales
ing seems to work:
data.frame(sapply(col2.uniq, function(col) {
wcol <- which(col==col2)
as.numeric(rowSums(data.frame(data.df[,wcol]))>0)
}))
I had to wrap data.df[,wcol] in another data.frame to handle situations where
wcol had one element. Is there a better approach?
---- Chuck Whi
Hello -- I am trying to merge columns in a dataframe based on substring matches
in colnames. I would appreciate if somebody can suggest a faster/cleaner
approach (eg. I would have really liked to avoid the if-else piece but rowSums
does not like that). Thanks.
data.df <- data.frame(aa=c(1,1,0),
;
>
> Since this question properly belongs on the ggplot2 list, it is being cc'ed
> there as well.
>
> HTH,
> Dennis
>
> On Mon, Feb 1, 2010 at 6:06 PM, Chuck White wrote:
>
> > Hello, I am trying to plot time-series data with certain weeks highlighted
> &g
Hello, I am trying to plot time-series data with certain weeks highlighted
using symbols.
require(ggplot2)
#plotting time series data
timescale <- seq(as.Date("01/01/09","%m/%d/%y"), length.out=12, by=7)
data.all <- data.frame(
id = c(rep('111',12),rep('222',12),rep('333',12)),
week=c(ti
Hello -- I posted this question yesterday and for some reason the post seems to
be attached to the wrong thread. Also, I extended my test a little and it seems
to indicate the problem is with spm. I would appreciate any help. Thanks.
==
lib
I am not able to get spm function in SemiPar to work with plyr. Here's an
example:
library(plyr)
library(SemiPar)
data <- data.frame(id=c(rep("111",100),rep("222",200)),
value=c(rnorm(100,2,1),rnorm(200,10,5)))
#this works
data111 <- data[data$id=="111"
Yesterday I posted the following question (my apologies for not putting a
subject line):
=question==
Hello -- I would like to know of a more efficient way of writing the following
piece of code. Thanks.
options(stringsAsFactors=FALSE)
orig <- c(rep('11
Yesterday I posted the following question (my apologies for not putting a
subject line):
=question==
Hello -- I would like to know of a more efficient way of writing the following
piece of code. Thanks.
options(stringsAsFactors=FALSE)
orig <- c(rep('11
Yesterday I posted the following question (my apologies for not putting a
subject line):
=question==
Hello -- I would like to know of a more efficient way of writing the following
piece of code. Thanks.
options(stringsAsFactors=FALSE)
orig <- c(rep('11
Hello -- I would like to know of a more efficient way of writing the following
piece of code. Thanks.
options(stringsAsFactors=FALSE)
orig <-
c(rep('',10),rep('',20),rep('',30),rep('',40))
orig.unique <- unique(orig)
system.time(df <- as.data.frame
Hello -- I am trying to create a dataframe whose rows are the cross product of
rows in two other dataframes. Here's an example:
A = data.frame(F1=c('1','2','3','2'))
B = data.frame(F2=c('4','5'))
C = data.frame()
for (x in unique(A[,'F1'])) {
C = rbind(C, cbind(F1=x,B))
}
How can I achieve t
Consider the following example:
x <- c(2,4,3,6)
y <- c(4,9,5,10)
z <- factor(c(1,1,2,2))
summary(lm("y ~ x + z"))
The above works fine.
Suppose I change z so that
x <- c(2,4,3,6)
y <- c(4,9,5,10)
z <- factor(c(1,1,2,NA))
summary(lm("y ~ x + z"))
the last row/observation is not considered in the
or
will the additional column be added to df1?
Thanks.
David Winsemius wrote:
>
> On Nov 10, 2009, at 12:36 PM, Chuck White wrote:
>
> > df1 -- dataframe with column date and several other columns. #rows
> > >40k Several of the dates are repeated.
> >
df1 -- dataframe with column date and several other columns. #rows >40k
Several of the dates are repeated.
df2 -- dataframe with two columns date and index. #rows ~130 This is really a
map from date to index.
I would like to create a column called index in df1 which has the corresponding
inde
Hello -- I am unable to build R 2.9.2 on IBM PowerPC AIX5.3. I would
appreciate any help in this matter.
===details==
Machine: IBM PowerPC_POWER5 / 4 proc, 1499 MHz 64-bit / AIX 5.3.0.0
Building R 2.9.2 using gcc/g++/gfortran 4.2.4
Config.site changes
My sincere apologies. This message was intended for the rpy2 mailing list.
Thanks.
Uwe Ligges wrote:
> Which previous message? Should we all look up the archives now? Please
> cite and stay within the same thread.
>
> Thank you,
> Uwe LIgges
>
>
>
>
>
After I posted the previous message, I repeated the process on a windows
machine with Python 2.6 and still get the same error.
I would appreciate any help.
__
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Input: dataframe with 300+columns for a regression. It consists of sets of
factors whose names have the same structure. For example, aa1,aa2,aa3 could be
one set of factors.
After reading in the dataframe, I would like to compute the density
(%nonzeroes) for certain groups of factors and delete
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