Hi John
> 1). Assume now I can calculate these "adjusted" standard deviation from
> sparse PCA, should the percent variation explained by each sparse PC be
> calculated using the sum of all these "adjusted" variance (i.e. square of the
> "adjusted" standard deviation) as the denominator (then t
Hi John
I am currently traveling and have sporadic net access, I therefore can only
answer briefly. It's also quite late, I hope what follows still makes sense...
> For regular PCA by prcomp(), we can easily calculate the percent of total
> variance explained by the first k PCs by using cumsum(
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