Thank you, Terry.
So in the spline model, how to do the interpretation for HR? For linear
term, the HR can be interpreted as "comparing a person with age 65, for
example, against mean age. But if there is no defined centering point in
spline, what's the compared value when we do the interpretation?
Hi all,
I have some questions about the predicted HR in coxph function including
psline covariate.
If just fitting covariate as linear form, by default, the reference value
for each of predictions type (linear predictor, risk and terms) is the mean
covariate within strata.
If the psline is speci
Dear R-helpers,
I am using the package "gee" to run a marginal model.
Here is the output.
In my simulated data, both x and z are time-varying, so I include their
interaction terms with time indicator (i.e. tind=0, if time 1, and 1 if time
2)
The data is simulated, so the true parameter of z both
Hello R helpers,
I have a quick question about loop and next
In my loop, I have some random generation of data, but if the data doesn't
meet some condition, then I want it to go next, and generate data again for
next round.
# just an example..
# i want to generate the data again, if the sum is s
1 2 1
> > ta[as.character(a)]
> a
> 4 3 2 3
> 1 2 1 2
> >
> HTH
> Ray Brownrigg
>
> On Mon, 07 Feb 2011, Jorge Ivan Velez wrote:
> > Hi Carrie,
> >
> > Try
> >
> > > x <- rle(a)
> > > rep(x$lengths, x$lengths)
&g
Hello R-helpers,
I have a question about counting numbers.
Here is a simple example.
a=c(2, 3, 3,4)
> table(a)
a
2 3 4
1 2 1
so, I can to create another variables that has the corresponding counting
numbers.
In this case, I want to have:
b=c(1,2,2,1)
Is there any way coding for this ?
Thanks
Here is a paper that gives an review of matching
Elizabeth A. Stuart. (2010) Matching Methods for Causal Inference: A
Review and a Look Forward. Statistical Science; 25(1):1-21.
In the paper, there is a list of R packages that does matching.
hope this helps.
On Tue, Feb 1, 2011 at 2:01 PM, Bi
)
>4000112 bytes
b=rnorm(P*P)*1000
D2=matrix(b, nrow=P)
object.size(D2)
>8000112 bytes
On Wed, Oct 6, 2010 at 5:44 AM, David Winsemius wrote:
>
> On Oct 5, 2010, at 11:17 PM, Carrie Li wrote:
>
> Thank you, Henrik! That makes more sense now.
>> You mentioned that every do
or R. )
I appreciate your explanation and helps!
On Tue, Oct 5, 2010 at 8:32 PM, Henrik Bengtsson wrote:
> On Tue, Oct 5, 2010 at 5:21 PM, Carrie Li wrote:
> > I am sorry that it has been couple days.
> > I've read the website you provided below, but still don't quite know if
&g
On Sat, Oct 2, 2010 at 12:22 PM, Marc Schwartz wrote:
> On Oct 2, 2010, at 11:14 AM, Carrie Li wrote:
>
> > Hi everyone,
> >
> > If I run on a 64-bit R, what is the maximum matrix size that it can
> handle ?
> > Is a matrix 20,000 x 20,000 possible on 32 bit ?
>
Hi everyone,
If I run on a 64-bit R, what is the maximum matrix size that it can handle ?
Is a matrix 20,000 x 20,000 possible on 32 bit ?
Thanks for answering!
Carrie--
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing lis
Aug 2010, peter dalgaard wrote:
>
>
>> On Aug 10, 2010, at 3:52 AM, Carrie Li wrote:
>>
>> Thanks. I found the code in the link you gave me very helpful.
>>> But, I just have few questions regarding the code.
>>> It seems to me that in (from wikipdeia)Deming
Thanks. I found the code in the link you gave me very helpful.
But, I just have few questions regarding the code.
It seems to me that in (from wikipdeia)Deming regression, it assumes that
the ratios of the variances of two measurement errors are constant for all
pairs of (x_i, y_i). However, if the
Hi,all,
I posted this question couple of days again, but haven't gotten any answers
back. I would like to post it again, and if you have any ideas, please let
me know. Any helps and suggestions are very much appreciated.
The problem is about linear regression with both y and x have measurement,
a
Hi, R-helpers,
I am working on a problem of measurement error modeling. (I am new to this
filed)
The model I am dealing with is simple. Consider a linear regression y= beta0
+ beta1 * x + error, in which x is measured with errors. (the variance of
errors are known. )
I looked up the package simex
Hi, all
I am doing a optimization problem using nlminb. It seems to me that the
result is kind of sensitive to the starting value. (It happened that the
resulting parameter doesn't change from the starting value.) Any suggestions
on giving the starting value ? or any other function that can do
opt
Hello everyone,
I have a question about integration of two density function
Intuitively, I think the value after integration should be 1, but they are
not. Am I missing something here ?
> t=function(y){dnorm(y, mean=3)*dnorm(y/2, mean=1.5)}
> integrate(t, -Inf, Inf)
0.3568248 with absolute error
gt; Ralf
>
> On Thu, Jun 24, 2010 at 10:35 PM, Carrie Li
> wrote:
> > Hi everyone,
> >
> > I am confused regarding the function "density".
> > suppose that there is a sample x of 100 data points, and plot(density(x))
> > gives it's pdf ?
>
Hi everyone,
I am confused regarding the function "density".
suppose that there is a sample x of 100 data points, and plot(density(x))
gives it's pdf ?
or it's more like histogram only ?
thanks for any answering
Carrie
[[alternative HTML version deleted]]
__
Thanks!
Both suggestions are very helpful.
One more question:
Can I use Vectorize to solve double integration question ?
Now that
f=function(x, y) {dnorm(y, mean= 0.75/x)*dnorm(x, mean=0.6,
sd=0.15)}
And I want to integrate x first,then y. Ravi used sapply, which is good, but
it seems to be that
Hello, everyone,
I have a question about integration of product of two densities.
Here is the sample code; however the mean of first density is a function of
another random variable, which is to be integrated.
##
f=function(x) {dmvnorm(c(0.6, 0.8), mean=c(0.75, 0.75/x))*dnorm(x, mean=0.6,
sd=0.15
Dear R-helpers,
I am working on an optimization problem, and I tried to use nlminb function
to solve it. But now I have an equality constrain, the Langrange multiplier
can solve it. However I would like to know if there is any existing function
or package solving this kind of problem. Any suggest
e because you have the same number of 0's and
> 1's within each strata. If that would not be the case, option 1 would not
> work. That's why I provided you a second option.
>
> Best,
> Jorge
>
>
> On Thu, Jun 3, 2010 at 7:24 PM, Carrie Li <> wrote:
>
akes 3 values, and same as
the binary part, it's all 0 0 1 1 1 for each stratum. Is there way to make
them complete randomly different over the strata ?
Thank you again!
Carrie
On Thu, Jun 3, 2010 at 7:24 PM, Carrie Li wrote:
> Thanks! Jorge
> Just one more question I don't get
se, e.g. you do not know
> # how many 0's and 1's you have within each strata
> spd <- with(d, split(d, x))
> do.call(c, lapply(spd, function(comp)
> with(comp, ifelse(t == 0, rbinom(sum(t==0), 1, 0.2),
> rbinom(sum(t!=0), 1, 0.8)
>
> HTH
Dear R-helpers,
I would like to generate a binary random variable within a stratum's
stratum. Here is a simple example.
## x is the first level strata index, here I have 3 strata.
x=c(rep(1,5), rep(2,5), rep(3,5))
## within x, there is a second strata indexed by t=0 and t=1
t=rep(c(0,0,1,1,1),3
Dear R-helpers,
I would like to generate a variable that takes 0 or 1, and each subject has
different probabilities of taking the draw.
So, which of the following code I should use ?
suppose there are 5 subjects, and their probabilities of this Bernoulli
variable is p=c(0.2, 0.9, 0.15, 0.8, 0.7
Hi, dear R-helpers,
I have a simple question regarding selecting subset of a variable based on
another variable.
Here is the example:
xx=rnorm(10)
id=sample(1:10, 10)
temp=c(6, 1, 8, 2)
Now, all I want is xx's that their id are 6, 1, 8, 2, instead of the
position.
Any suggestions ?
Thank you
Dear r-helpers,
I have a small dataset (n<50), and I want to compute the Hodges Lehmann
exact confidence interval.
So far, I know that "pairwiseCI" has the function "HL.diff". The description
is as follows :
HL.diff calculates the Hodges-Lehmann confidence interval for the difference
of locations
nt!
Thank you!
On Fri, Feb 5, 2010 at 12:24 AM, David Winsemius wrote:
>
> On Feb 4, 2010, at 11:53 PM, Carrie Li wrote:
>
> Thank you, David
>> Here is an example :
>>
>>
>> Z=matrix(rnorm(20), nrow=4)
>> index=replicate(4, sample(1:5, 3))
>&
matrix "index"
And, since I have large P, so I would like to avoid loop.
Any quick way to do this ?
Thanks again!!
Carrie
On Thu, Feb 4, 2010 at 10:39 PM, David Winsemius wrote:
>
> On Feb 4, 2010, at 9:51 PM, Carrie Li wrote:
>
> Dear R-helpers ,
>>
>&g
Dear R-helpers ,
I have a simple loop as follows, however, to be more efficient, I would like
to use any apply functions (tapply, I suppose)
But how can I do this ? I am not very clear about this.
# Z is a P * Q matrix
# so for each row of Z, I would like to pull out only some of the elements,
an
Dear R-helpers,
I have a question about giving index.
Suppose that I have a vector say, id=1:5, and each of them have some given
index but some of them may share the same index
Now, I have another vector, and I want to give it a index based what just
defined.
# 5 subjects
test1=1:5
# corresponding
Dear R-helpers,
I have a question about giving index.
Suppose that I have a vector say, id=1:5, and each of them have some given
index but some of them may share the same index
Now, I have another vector, and I want to give it a index based what just
defined.
# 5 subjects
test1=1:5
# corresponding
Dear R-helpers,
I have a question about giving index.
Suppose that I have a vector say, id=1:5, and each of them have some given
index but some of them may share the same index
Now, I have another vector, and I want to give it a index based what just
defined.
# 5 subjects
test1=1:5
# corresponding
Dear r-help group,
I am creating a package that has some FORTRAN code under windows. I have
read through "Writing R Extension" but still not so clear about the steps.
Before R CMD build, how can I create a dynamic library and later in my R
function using dyn.load ("xxx.dll") ?
If I already have
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