Clearly something has gone terribly wrong. Everyone is saying use S3. This
is an online discussion... So someone needs to support S4.
Which frighteningly seems to be me! I'd caution you now... I first used an
S4 object about two weeks ago and still have no real idea if they do what I
think they do
So either:
XX contains some non-finite numbers
Or
Something produced from it does.
Non finite means things like 1÷0. R might show Inf or -Inf. But if there is
maths happening in the function it might be passing something to it the is
a 0 and so creating a Inf.
But if there is a test of is.fini
acf wants a time series, so tries to make one:
as.ts(myts)
Time Series:
Start = 19357
End = 20027
Frequency = 1
[1] 24957 NA NA NA NA NA NA NA NA NA
[11] NA NA NA NA NA NA NA NA NA NA
[21] NA NA NA NA
This isn't my field. But I'd have expected a sentence along the lines of:
Stock prices were obtained from Yahoo Stocks[1] using the Quantmod R
statistics package[2].
1. Yahoo Citation
2. Quantmod citation
That is readable. A further sentence:
All analytical code is available from a publicly acc
Indeed.
When I try and recreate your problem I fail to find a problem.
But almost certainly the issue lies in the file, or the reading of said
file.
Currently the code is
fname <- "Buzz.txt"
All <- fname
That results in All containing "Buzz.txt" not the CONTENT of a file called
Buzz.txt.
As
Am I being "thick" here
..
mutate(data, *# text
Is interpretated as mutate (data, *
The star is the character...
(Data is the line above being piped)
Why have the comments been *'d?. Is that the source error or a posting
error here?
On Tue, 17 Dec 2024, 14:57 Ivan Krylov via R-help,
wrote:
I've not checked the code, but I think that result would happen if mean
uses something like
if (na.rm == TRUE) {
# do something to remove the NA's
}
And as uses something like
If (na.rm != FALSE) {
# do something to remove the NA's
}
Or perhaps ever na.rm == T
If you ever see posts from B
Well to complicate things, I don't think RULES is the answer.
This is a cryptic crossword clue. They usually contain the answer twice
(well... Cryptically!!)
Writes in C or R, say.
I think the answer is CODER
If you look up the definition of say in the dictionary one option is:
1. give in
And to answer the dependency question.
Neither is dependent on the other. But both can be complimentary.
If you consider that SQL*may* be a route to accessing your data (if it's in
a database).
And R *may* be a route to analysis of the data.
If the data is in a CSV file, Excel file, API etc. y
And R Studio has an import data function that will provide a import
command..
BUT
Spreadsheet is a broad scope
On Thu, 5 Dec 2024, 23:38 Martin Møller Skarbiniks Pedersen, <
traxpla...@gmail.com> wrote:
> On Thu, 5 Dec 2024 at 23:16, Figueiredo, Carlos via R-help
> wrote:
> >
> > Hi there
> >
Carlos you are gonna have to provide at least a tiny smidge of information
Reagent dataset? What is this?
What is your problem with creating a script in R Studio. File New..
It kinda feels this is either "how do I use R studio" (in which case
YouTube feels your friend) or "how do I use some very
Why can't you do:
df0 |> mutate( ... ) |>
mutate( ... ) |>
mutate( ... )
I've simplified the code to show passing the result of the first line to
the next rather than focussing on the detail. This would work with %>% as
well as |> but I am anticipating that the more modern native pipe ( |> )
Avi
I fear this was all a huge social experiment.
Testing if a post titled "sexy way" would increase engagement...
On Sat, 28 Sep 2024, 07:21 , wrote:
> I see a book coming:
> "666 ways to do the same thing in R ranked by sexiness."
>
> Kidding aside, if you look under the covers of so
>> if it can be made available. It does look like the finial step of
> reading
> >> the data into raster failed, so then did the rest of th commands.
> >>
> >> -Roy
> >>
> >>
> >> > On Sep 25, 2024, at 3:24 PM, CALUM POLWART
>
Noticeable lack of silence in the group on this one.
I've not got time to test currently. But my experience of geo location
files - they often had more than 2 dimensional data. In other words you
might have a boundary of a region as an object with long and lat for maybe
100 data points making up t
I think there is a typo in your reprex l(x^2) ??
mydt[1,2] contains a list. Which when unlisted contains a load of data.
I'm not sure what you are asking for? Are you trying to unlist that and
have it as a row? Sort of pivot.wider if you like or unnest in tidyverse
concepts?
I think the data.tab
Rui's solution is good.
Bert's suggestion is also good!
For Berts suggestion you'd make the list bit
list(mean = mean_narm)
But prior to that define a function:
mean_narm<- function(x) {
m <- mean(x, na.rm = T)
if (!is.Nan (m)) {
m <- NA
}
return (m)
}
Would do what you suggested in your r
Add:
key = list(points=16:17)
Into the dotplot section possibly without the autokey
On Fri, 13 Sep 2024, 08:19 Christopher W. Ryan,
wrote:
> I am making a dotplot with lattice, as follows:
>
> dd %>% dotplot( segment ~ transit_time, groups = impact, data = .,
>as.table = TRUE,
Bert
I thought she meant she wanted to replace the NAs with the 6. But I could
be wrong.
It looks like the data is combined from cbind.
I'm going to give tidyverse examples because it's (/s) *"always"* (/s)
easier.
require(tidyverse)
# impute the missing NAs
myData <- cbind(VB1d[,1],s1id[,1])
cmd
taskkill /PID 1234
Will kill process 1234 if you know it id
So shell.exec can likely do this for you
On Sat, 17 Aug 2024, 12:31 Duncan Murdoch, wrote:
> On 2024-08-17 6:21 a.m., SIMON Nicolas via R-help wrote:
> > I would like to stop a dos shell windows following the cmd (execute)
> comma
Unless I'm missing the point, you are sending the summary data MS1s to the
plot. Is that not a VERY unusual way to do it. Let box plot do the
summary? Otherwise what do you want the notches to show?
On Fri, 16 Aug 2024, 17:21 Chris Evans via R-help,
wrote:
> That's not really a reprex Sibylle.
returning the list.
> Use of "<<-" is rarely a good idea in R.
>
> -- Bert
>
> On Fri, Aug 9, 2024 at 1:53 AM CALUM POLWART wrote:
> >
> > OK. The fact it's in a function is making things clearer.
> >
> > Are you trying to update the value
} else {
> + {print ("cond21"); cat(cond21)}
> + }}
> > try1(joint12=TRUE)
> [1] "joint12"
> TRUE
> [1] "marg1"
> FALSE
> > try1(marg1=TRUE)
> [1] "marg1"
> TRUE
> [1] "joint12"
> FALSE
> > try
Is something wrong in the initialisation part that we don't see?
joint12 <- marg1 <-F
marg1 <-T
if (joint12) {
print ("joint 12")
cat (joint12)
}
if (marg1) {
print("marg 1")
cat(marg1)
}
Would probably be my diagnostic approach
On Fri, 9 Aug 2024, 04:45 Steven Yen, wrote:
> Can som
But have we lured you to the dark side with the tidyverse yet ;-)
On Mon, 22 Jul 2024, 15:22 Bert Gunter, wrote:
> Thanks.
>
> I found this to be quite informative and a nice example of how useful
> R-Help can be as a resource for R users.
>
> Best,
> Bert
>
> On Mon, Jul 22, 2024 at 4:50 AM G
The tidy solution is rename
literally:
z |> rename(foo = 2)
Or you could do it with other functions
z |> select ( 1, foo = 2)
Or
z |> mutate( foo = 2 ) |> # untested (always worry that makes the whole
column 2)
select (-2)
But that's akin to
z$foo <- z[2]
z[2] <- null
On Sun, 21 Jul 2024,
I sometimes think people on this list are quite rude to posters.
I'm afraid I'm likely to join in with some rudeness?
1. "Here is some code that works but also doesn't" is probably not going to
get you an answer
2. I provide no information about the data it works on or doesn't
3. I tell you I'm u
Do you receive RDS objects from unknown (untrusted) sources?
?? If not - the security issue is a non-issue as I understand it.
On Thu, 16 May 2024, 16:21 Vega, Ann (she/her/hers) via R-help, <
r-help@r-project.org> wrote:
> I help to coordinate the USEPA's R user group. We have over 500 member
I don't think that gives the summary of event numbers without extra work.
library(survival)
fit <- survfit( Surv(time,status)~sex,data=lung)
summary(fit)$n.event
[1] 3 1 2 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 3 1 1 1 1 1 2
[38] 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
More difficult than it should be IMO.
survminer package is often helpful. But if you want to avoid dependency:
library(survival)
fit <- survfit( Surv(time,status)~sex,data=lung)
surfable <-summary(fit)$table
surfable
# just the events
surfable[,"events"]
On Wed, 15 May 2024, 21:42 Dennis Fishe
data.table's fread is also fast. Not sure about error handling. But I can
merge 300 csvs with a total of 0.5m lines and 50 columns in a couple of
minutes versus a lifetime with read.csv or readr::read_csv
On Mon, 8 Apr 2024, 16:19 Stevie Pederson,
wrote:
> Hi Dave,
>
> That's rather frustratin
That's almost certainly going to be either the utf-8 character in the path
OR the use of one drive which isn't really a subfolder as I understand it.
When I've had these issues in the past, I've been able to mount a drive
(say U:/ ) which sites further down /up the folder tree so that R just
calle
t to do this is to keep
> my main programs compact.
>
> Steven from iPhone
>
> On Feb 21, 2024, at 12:44 AM, CALUM POLWART wrote:
>
>
> Are you asking to source lines 5-10 of a file for instance?
>
> Never seen that done in R. Feels a dodgy thing to do as changing l
Are you asking to source lines 5-10 of a file for instance?
Never seen that done in R. Feels a dodgy thing to do as changing line will
screw things up. On the other hand - I'd often have functions in a file
called perhaps "functions.R" and source("functions.R")
Then I can call an individual func
I don't use term, but I've just tested it and this is reproducable.
Is it a bug? Not sure. If you hit c after getting the message it will
cancel the q() request.
On Fri, 9 Feb 2024, 17:21 Duncan Murdoch, wrote:
> That looks to me like a bug, but I don't use Windows any more, so I
> won't offer
And your other option - recode what gets imported. It may well be you will
actually want the blanks to be NAs for instance rather than blank. I'm
assuming the True and False are >$0 and $0 from your description. (Or maybe
vice versa). So I'd have made my column name something like
"OverZeroDollars"
help(read_docx) says that the function only imports one docx file. In
> order to read multiple files, use a for loop or the lapply function.
>
I told you people will suggest better ways to loop!!
>
> docx_summary(read_docx("Now they want us to charge our electric cars
> from litter bins.docx"))
It sounded like he looked at officeR but I would agree
content <- officer::docx_summary("filename.docx")
Would get the text content into an object called content.
That object is a data.frame so you can then manipulate it. To be more
specific, we might need an example of the DF
You can loop thi
textreadr would be the obvious approach.
When you say it is depreciated do you mean it's not available on cran?
Sometimes maintaining a package on cran in just a pain in the ass.
devtools::install_github("trinker/textreadr")
Should let you install it.
In theory docx files are actually just zip
You could easily omit the Page X of xX, but leave the timestamp
Then add Page X of XX programmatically using pdftools or some similar pdf
command line tools.
On Sat, 2 Dec 2023, 22:35 , wrote:
> Having read all of the replies, it seems there are solutions for the
> question and the OP points ou
Can you provide a very simplified version of how the PDF is created?
On Sat, 2 Dec 2023, 14:39 Dennis Fisher, wrote:
> OS X
> R 4.3.1
>
> Colleagues
>
> I often create multipage PDFs [pdf()] in which the text "Page X" appears
> in the margin. These PDFs are created automatically using a massi
This is doable. But it's also considered a data visualisation hell! So
Hadley didn't make it easy.
I can provide more details on how to do it later (replying from phone just
now). BUT there is very much a question of should you be plotting like
that. It's probably worth giving it serious thought b
ded. An example might be aspects of the ggplot program
> where you may get a mysterious order of presentation in the graph unless
> you create a factor with the order you wish to have used and avoid it
> making one invisibly.
>
> From: CALUM POLWART
> Sent: Saturday, November 4, 2
I might have factored the gender.
I'm not sure it would in any way be quicker. But might be to some extent
easier to develop variations of. And is sort of what factors should be
doing...
# make dummy data
gender <- c("Male", "Female", "Male", "Female")
WC <- c(70,60,75,65)
TG <- c(0.9, 1.1, 1.2,
Charity
There is OFTEN confusion what we mean when we say "R".
R is effectively a single bit of software with a ton of other bits of
software as optional extras. You might think of some of those optional
extras like apps on a phone. You'd say you have a phone when you can open
the box and power
Using readr to read the data might let you clean it on the way in...
readr::read_csv("filename.csv", col_types = list(rep(col_numeric(),6))
On Mon, 25 Sep 2023, 16:54 Ebert,Timothy Aaron, wrote:
> An update please:
> Collectively we have suggested removing commas from the "E..coli" column,
> ch
It does often behave better if you say to it "that doesn't seem to be
working" and perhaps some error message
It is afterall a language tool. Its function is to provide text that seems
real.
If you ask it a science question and ask it to provide references in
Vancouver format, it can format the r
+ geom_ribbon(stat = "smooth",
se = TRUE,
alpha = 0, # or, use fill = NA
colour = "black",
linetype = "dotted")
Does that work?
On Sat, 12 Aug 2023, 06:12 Rui Barradas, wrote:
> Às 05:17 de 12/08/2023, Thomas Subia via R-help escreveu:
>
I'm looking for a way to do some live data analysis taking audience votes,
presenting their results, potentially posing some new questions to vote on,
and present those and vote.
I'm interested in any suggestions from the collective minds here about the
potential best approaches.
I can obviously
I was just replying to say which bit do you consider the indicator.
But I see Boris has provided a Chat GPT solution.
Running it hopefully shows you how to change colours on various parts.
On Fri, 21 Jul 2023, 22:43 Jeff Newmiller, wrote:
> plotly is _not_ associated with posit. I think you
t; I will find the ggplot help.
>
> But I have tried everything, including what you have suggested and nothing
> works.
>
> Kind regards,
> Maria
>
>
>
>
>
>
> Στις Κυριακή 16 Ιουλίου 2023 στις 11:22:36 μ.μ. GMT+1, ο χρήστης CALUM
> POLWART έγραψε:
>
&
Try adding
scale_y_log10()
This is a general R help list. It's not a ggplot list and you are likely to
be chased off to ggplot's package maintainers nominated support pages.
But really a Google search should surely have found this?
On Sun, 16 Jul 2023, 22:51 Maria Lathouri via R-help,
wrote:
Chris replied off list to say he hadn't directed the OP to NHS R Community
so it seems prudent to point a link here for eternity -- because there will
be another NHS Security Audit with questions that don't fit R properly and
the guys in the community may be best placed to answer them
Linky:
https
Chris
Presumably you've also pointed her to the NHS R community and in particular
is slack group?
There are so many variables in what was even being asked it's going to take
some time to work through, did the mean R or R Studio or R Studio Cloud...
Before any packages..
On Wed, 17 May 2023, 10:4
Obviously running R is pretty fundamental to running R studio. So it seems
rather odd to be thinking you'd need to stop using R studio unless you are
doing something odd
On Fri, 7 Apr 2023, 02:18 Sorkin, John, wrote:
> I have also had difficulty running R in RStudio. Has anyone else had
> proble
R studio sometimes isn't happy with i386 versions. Although I thought they
had put support back in. If you have the option for 64bit, use 64bit R.
I've also had similar issues when R couldn't find the executable.
But absolutely would expect if you post this on the community forum someone
would be
This doesn't sound like it is R failing, it sounds like you don't know the
appropriate connection details for the server. You need to find them out
and come back rather than simply try different username and passwords...
Can you connect to the server using any other ODBC connection and those
crede
On Wed, 4 Jan 2023, 21:29 Ebert,Timothy Aaron, wrote:
>
> As you are plotting strings, you could put a space character in front of
> the December dates so that they are first.
> date<-c(" 12-29"," 12-30","01-01")
> That fixes the problem in this example. You can order all the dates by
> putting m
I get frustrated by our peers who reply "please provide a worked example"
but OMG... Please provide a worked example!
You can't use:
source("filename.Rmd") as it isn't a simple set of R code.
You can do:
Rmarkdown::render("filename.Rmd")
You can also knit child files. But it is completely uncl
https://stackoverflow.com/questions/49679699/time-series-plot-change-x-axis-format-in-r
Is as good a solution as possible using ts I think.
On Sat, 24 Dec 2022, 18:58 Upananda Pani, wrote:
> Dear All,
> I have the data set with daily dates (5-days trading in a week) and price
> data. I want
I don't think this is an R issue, it's a HTML tables issue // browser issue.
There are some hacks using background image (not R specific).
BUT before you do any of this... Consider if colour is your answer! 8% of
males are colour blind, so your table isn't as accessible as you may think
it is. T
You asked for base R but also said or using other methods. So for
completeness here is a solution using Tidyverse
library(tidyverse)
data_original <- data.frame(
year = c('1990', '1999', '1990', '1989'),
size = c('s', 'l', 'xl', 'xs'), n = c(99, 33, 3, 4) )
data_original |>
pivot_wider(
Can you provide a sample of say the first 3 rows then the last 2 rows
before the CSV starts.
Are there always the same number of lines at the top? Or can it vary
depending what non-sense the Met Office decided to contaminate it with?
This should be solvable with some sample data.
Base R or Tidyv
the change(s) using
> Excel.
>
>
>
> For future reference, when I look at your solutions below, what do you
> mean by “value to delete”? Could that just be a row number? I was wanting
> to delete something like the 18th row in the dataframe?
>
>
>
> *From: *CALUM P
>From the file? Or the data frame once its loaded?
What format is the file? CSV?
Do you know the line that needs deleted?
mydf <- read.csv("myfile.csv")
mydf2 <- mydf[-columnName == "valuetodelete", ]
# Note the - infront of column name
# or perhaps columnName != "value to delete", ]
write.csv
Not very clear what you are trying to do. But I'd have thought possibly
dplyr left_join might be a solution for you. The base R equivalent is
merge().
It might be a rbind or cbind can do it too.
On Wed, 27 Jul 2022, 03:30 Ranjeet Kumar Jha,
wrote:
> Hello Everyone,
>
> I have dataset in a part
As has been said, it's not for R CRAN to fix. This is open source code. If
the package maintainer is no longer keen anyone can fork the code, maintain
it and release it back to Cran and provided it meets their rules it would
be available for all. (If it doesn't you just need to provide the install
www.9folders.com/>
From: Marc Schwartz
Sent: Friday, 4 September 2020 18:32
To: POLWART, Calum (SOUTH TEES HOSPITALS NHS FOUNDATION TRUST)
Cc: R-help; Terry Therneau
Subject: Re: [R] Survival Object - is 12month survival = 365days
On Sep 4, 2020, at 11:45 AM, POLWART,
Using survfit I can get the '1 year' Survival from this dataset which holds
survival in days:
require (survival)
survfit( Surv(time, status) ~sex, data=colon)
summary (fit, 365)
My current real world data I'm calculating time using lubridate to calculate
time and since it made the axis easy I j
I'm writing a quite large document in Rmarkdown which has financial data in it.
I format that data using scales::dollar() currently something like this:
>
> require (scales)
> x = 10
> cat (dollar (x, prefix ="£", big.mark=","))
£100,000
But actually, I'd quite like to get £100k out in tha
Well I get the issue with finite precision. As in SQRT(2) * SQRT(2) is not 2.
What surprised me was that seq(1.4, 2.1, by=0.001) starts at 1.3999
and not 1.4!
-Original Message-
From: PIKAL Petr [mailto:petr.pi...@precheza.cz]
Sent: 17 January 2019 14:30
To: POLWART, Calum
Ben Tupper; POLWART, Calum (COUNTY DURHAM AND DARLINGTON NHS FOUNDATION
TRUST)
Cc: r-help@r-project.org
Subject: RE: [R] I can't get seq to behave how I think it should
Hi
Or you could use rounding.
which(round(lut, 3)==1.8)
[1] 401
Cheers
Petr
> -Original Message-
> From:
I am using seq with the expression seq(1.4, 2.1, by=0.001) to create a sequence
of references from 1.4 to 2.1 in 0.001 increments. They appear to be created
correctly. They have a related pair of data which for the purposes of this we
will call val. I'm interested in the content on the row wi
Before I go and do this another way - can I check if anyone has a way of
looping through data in odfWeave (or possibly sweave) to do a repeating
analysis on subsets of data?
For simplicity lets use mtcars dataset in R to explain. Dataset looks like
this:
> mtcars
mpg cyl disp
Hi Jim
Working on basis of exact match. but the 25% inncrements are rounded to
imtegers, so like buying from a shop priced in whole numbers but changeis what
you expect not 'roughly right'
Thanks
Calum
On 27 Dec 2015, at 22:04, Jim Lemon
mailto:drjimle...@gmail.com>> wrote
ht simplify this?
Sent from TypeMail<http://www.typeapp.com/r>
On 27 Dec 2015, at 08:00, "Polwart Calum (COUNTY DURHAM AND DARLINGTON NHS
FOUNDATION TRUST)" mailto:calum.polw...@nhs.net>> wrote:
***
Hello,
I previously submitted the below query to r-sig-geo, but have had no
response. Before I start bothering individual maintainers, I wonder
if anyone on this list has any experience with the package and (or!)
can diagnose my problems?
Thanks,
Calum
Hello,
I am having a little trouble with
preciated,
Thanks,
Calum
--
View this message in context:
http://r.789695.n4.nabble.com/Inverse-of-Probit-tp4680752.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo
Calum
Hi Calum,
I can only answer from the perspective of someone who calculated
doses of alcohol for experimental subjects many years ago. It was not
possible to apply a linear function across the range due to a number
of factors. One is that BAC, which was the target value, is dependent
upon
ts function in R that can easily do that and
almost then report from some inputs a single number that is the "best fit"?
Calum
This message may contain c
se, absence of evidence is not evidence of absence. Failing to
> reject the null hypothesis that the
> distributions are different is not proof that the distributions are equal.
Yes absolutely - however I'm half expecting to detect a difference and so then
dismiss using A as a surrog
I have a dataset which for the sake of simplicity has two endpoints. We would
like to test if two different end-points have the same eventual meaning. To
try and take an example that people might understand better:
Lets assume we had a group of subjects who all received a treatment. The could
This may be a really obvious question but I just can't figure out how to do it.
I have a small dataset that I am trying to compare to some controls. It is
essential that the controls are matched on Cancer Stage (a numerical factor
between 1 and 4), and then ideally on Age (integer), Gender (fac
On Tue, 17 Apr 2012 10:44:40 -0400, Denis Chabot wrote:
> Hi,
>
> I cannot make a reproducible example easily for my problem, so I'll
>
describe it as best as I can.
YOU KIND OF NEED ONE...
>>
a=test1$période[21]
>
>> b=test2$date[22]
> a f
> argin-left:5px;
width:100%">b
>
> [1] "2011
to death. I'm not sure how that affects things but hoping it makes life
simpler.
Calum
This message may contain confidential information. If yo...{{dropped:21}}
_
You are correct my censoring is happening on an event - (dis)continuation of
treatment - not on reaching a cumulative cost.
Calum
This message may
years so it will be impossible to get an average for years.
So the censored patients will be those still on treatment (the event being
stopping treatment)
I'll give what you've suggested a go.
Thanks
Calum Polwart BSc(Hons) MSc MRPharmS SPres IPres
Network Pharmacist - NECN and
survival curve functions to plot an X
axis that is $ rather than date? If not is there some other way to achieve this?
Thanks
Calum
This message may contain confidential information
I might be missing something really obvious, but is there an easy way to locate
all non-unique values in a data frame?
Example
mydata <- numeric()
mydata$id <- 0:8
mydata$unique <- c(1:5, 1:4)
mydata$result <- c(1:3, 1:3, 1:3)
> mydata
$id
[1] 0 1 2 3 4 5 6 7 8
$unique
[1] 1 2 3 4 5 1 2 3 4
$r
> I run the script and it exports a PDF called "version 1".
> I want it to check if "version 1" already exists. If so,
> then I want the new graphs to be exported as
> "version 2", and so on.
>
> Is it possible to do it in R?
Someone may know a way. However its certainly possible to execute a co
exported table
would not ideally be pure numbers.
- As a p value usually links two columns I might have expected to use a merged
cell which again brings me back to my original question ;-)
Thanks
Calum Polwart BSc(Hons) MSc MRPharmS SP IP
Network Pharmacist - North of Engla
Solved my own problem by using:
odfTable.matrix(
as.matrix (
with (mydata, table (site_id, reaction))
)
)
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Hi guys I'm hoping someone can help me with this. It should be easy but it
seems to get stuck for no obvious reason! I am trying to set a report up in
odfWeave so that we can re-run the same analysis at 3 time points as the data
matures and provide an 'instant' report.
To simplify the situati
this is where I go off topic! Am I right? I know its off topic - so what I'd
like to know is can someone point me to where I can find out?
Then if it is a monte-carlo can someone point me to a good
>LinZhongjun wrote:
>>
> >I ran Winbugs under R. I could get the results, but I kept getting the error
> >messages:
>>
> >Error in
> > file(con, "wb") : cannot open the connection
> >In addition: Warning messages:
> >1: In file.c
Sorry I'm having one of those moments where I can't find the answer but I bet
its obvious...
I'm outputting my results to a file using sink()
Is there a command simillar to php's echo command that would allow me to add
some text to that file ie:
dataFr$a = 1:10
dataFr$b = 2*1:10
sink ("filepat
>> col=c("blue","red")mydfr$[treatment]
>
> Yes, but I would like to use the function for lots of other dataframes
> as well, so embedding 'mydfr' in the function is not the ideal
> solution...
In that case I'd try something like:
myplot <- function(..., tmnt) {
plot(...,
pch=19,
> I have got 27 graphs to export (not a lot...I know!). How can I fit all of
> them into a single file like PNG without adjusting the size of the graphs?
> What's in my mind is like pasting graphs into Word, in which I can just
> scroll down to view the graphs.
Pretty sure PNG can only cope with s
>
> # I tried defining a function like this
> myplot <- function(...)plot(..., pch=19, col=c("blue","red")[treatment])
>
> # So i can call it like this:
> with(mydfr, myplot(Xmeas, Ymeas))
>
> # but:
> Error in plot.xy(xy, type, ...) : object 'treatment' not found
>
basically that is something like
rves... so I'm sure it must be possible to automate.
Ta
Calum
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