Thank you all ;)
On Wed, Jul 3, 2013 at 4:28 PM, S Ellison wrote:
> > Now I have question: what about y=b fitting? is there any model to
> > force or impose the ax to be zero
>
> Rui Barradas has answered correctly for a simple lm case.
>
> You can also do
> lm(y~1) to obtain an estimated
Greetings to every body.
we know that for linear regression: two-parameter fitting in R: (for a and
b as slope and intercept)
[a] for y=ax+b type models we use: lm(y~x)
[b] for y=axtype models we use: lm(y~0+x) => forced to pass through
origin
Now I have question: what about y=b fitting
,
>
> type=c("p","b"),lcol=1,rcol="red",xtickpos=month,xticklab=month))
>
> legend(5,13000,legend=c("Music","Actor"),text.col=c("black","red"),col=c("black","red"))
>
> #I tried to change t
Hi dear all, the following code is correct. but I want to use non-numeric
x-axis, for example
if I replace time <- seq(0,72,6) by
month <-
c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec","Pag")
Ofcourse I use factor(month) instead of time; but I didn't get similar
plo
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