Hi,
I would rather have a Statistics related question hope experts here can provide
some suggestions. I have posted this request in some other forum but failed to
generate meaningful response
I am looking for some technical document on deriving the Distribution function
for sum of 2Â ReLU(đť‘‹)=max{
= "%d%b%Y%H%M%OS")
[1] "2018-01-03 16:00:00 GMT"
_
Arun Kumar Saha, FRM
QUANTITATIVE RISK AND HEDGE CONSULTING SPECIALIST
LinkedIn: http://in.linkedin.com/in/ArunFRM
Personal : http://WWW.ARUNSAHA.IN <http://WWW.ARUNSAHA.IN>
___
Hi All,
I have been given three raw data csv files related to an advertising
campaign. Impressions, clicks and conversion. They asked me to suggest
optimisation suggestions using uni variable and multi variable analysis.
The clicks or conversions are spread across various parameters like device,
c
which method in statistics is completely free from model misspecification?
Thanks and regards,
_
Arun Kumar Saha, FRM
QUANTITATIVE RISK AND HEDGE CONSULTING SPECIALIST
Visit me at: http://in.linkedin.com/in/ArunFRM
Can the Statisticians here develop some good Statistical tool to stop this
Spamming keeping Type-I error almost zero?
Thanks and regards,
_
Arun Kumar Saha, FRM
QUANTITATIVE RISK AND HEDGE CONSULTING SPECIALIST
Visit me at: http
.
_
Arun Kumar Saha, FRM
QUANTITATIVE RISK AND HEDGE CONSULTING SPECIALIST
Visit me at: http://in.linkedin.com/in/ArunFRM
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PLEASE do read the posting guide http
ne you may
then use VAR simulation code.
HTH,
Thanks and regards,
_____
Arun Kumar Saha, FRM
QUANTITATIVE RISK AND HEDGE CONSULTING SPECIALIST
Visit me at: http://in.linkedin.com/
within Asymptotic concept. Then apply your
statistical test on that realized series.
You may repeatedly generate TS and check the distribution of estimated
model parameters etc.
HTH
_
Arun Kumar Saha, FRM
QUANTITATIVE RISK AND HEDGE CONSULTING
HTH
_____
Arun Kumar Saha, FRM
QUANTITATIVE RISK AND HEDGE CONSULTING SPECIALIST
Visit me at: http://in.linkedin.com/in/ArunFRM
__
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PLEASE do rea
tistical inference sense. To get that, I think above regression
approach would be handy.
HTH
Thanks and regards,
_____
Arun Kumar Saha, FRM
QUANTITATIVE RISK AND HEDGE CONSULTING SPECIALIST
Visit
On reply to the post
http://r.789695.n4.nabble.com/using-lapply-td3345268.html
Dear Kushan, this may be a good start:
## assuming 'instr.list' is your list object and you are applying
my.strat() function on each element of that list, you can use lapply
function as
lapply(instr.list, function(x)
I gave you hint only, however whatever you done is correct.
On Mon, Aug 2, 2010 at 4:30 AM, n.a.s wrote:
> Hi,
>
> But i didn't understand why you did it like this qnorm(40/200)??
>
> I already found the answer qnorm(.20,181,7.3) and qnorm(.80,181,7.3)
>
>
> Thanks.
>
>
> On Mon, Aug 2, 2010 a
probably :
a <- rep("HH:MM:SS", 5)
substring(a, 7) = "00"
a
Not sure if there is an R way to do this or a regular express way, but here
is what I am trying to do.
I've got lots of data where the format is HH:MM:SS, but I need to format it
like HH:MM:00, i.e. round the second down to zero.
What
Hi all,
say, I have following vector :
x <- c(rep(5, 5), rep(3,4), rep(5,10))
Now I want to get the index numbers where elements of that vector changes
i.e. in above example I want to get a vector with elements : 6, 10. Because
at that indices, element of original vector changes value.
Is there
Hi, Currently I am a .net programmer and would like to use R for my
statistical computations engine. I already have installed RServer250.exe so
that I could call R from my .net programming environment, however
unfortunately, i could not be able to find RServer250.exe in the R-(D) COM
Interface reg
I would like to know about the skewness function bundled in fBasics package.
Is it population measure of skewness or sample estimate?
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Hi all,
Is there any R package on "European/American oprions pricing"? And on
calculation of it's sensitivities?
Regards,
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PL
oh now I got, R is taking unbiased estimator, anyways thanks
On Sun, Jul 27, 2008 at 2:54 PM, Arun Kumar Saha
<[EMAIL PROTECTED]>wrote:
> I feel there is something wrong in definition in weighted variance.
>
> Say for a fair dice the variance of outcome should be
Burns <[EMAIL PROTECTED]>wrote:
> Have you seen 'cov.wt'?
>
>
> Patrick Burns
> [EMAIL PROTECTED]
> +44 (0)20 8525 0696
> http://www.burns-stat.com
> (home of S Poetry and "A Guide for the Unwilling S User")
>
> Arun Kumar Saha wrote:
>
>&
ur prog gives following result:
weighted.var(c(1,-1), c(0.5,0.5))
[1] 2
is it ok?
On Thu, Jul 24, 2008 at 7:57 PM, Gavin Simpson <[EMAIL PROTECTED]>wrote:
> On Thu, 2008-07-24 at 02:25 +0530, Arun Kumar Saha wrote:
> > There is a R function to calculate weighted mean : weight
There is a R function to calculate weighted mean : weighted.mean() under
stats package. Is there any direct R function for calculating weighted
variance as well?
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https://s
ot;, "MIN", "MAX")){
>>
> + fun<-match.arg(fun);a=3;b=5
> + switch( fun,
> + MEAN=(a+b)/2,
> +SUM=a+b,
> +MIN=min(a,b),
> +MAX=max(a,b))
> +}
>
>>example("MEAN")
>>
> [1] 4
>
>>
There is "if-else" loop if I have to choose 1 item from a 2-item list.
However if I have a list of 4 items (let say) then how i can choose a single
item without employing 'if-else' loop? I mean in VBA I can use
"select-case", is there any equivalent in R as well?
Regards,
[[alternative HT
Suppose I have a Variance-covariance matrix A. Is there any fast way to
calculate correlation matrix from 'A' and vice-versa without emplying any
'for' loop?
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number is
> quite large!). So if f change continuously you may
> need the condition |f(x,y) - c| < epsilon for some
> epsilon > 0.
>
> Regards,
>
> Moshe.
>
>
> --- Arun Kumar Saha <[EMAIL PROTECTED]> wrote:
>
> > Here I am in a simulation study
Here I am in a simulation study where I want to find different values
of x and y such that f(x,y)=c (some known constant) w.r.t. x, y >0,
y<=x and x<=c1 (another known constant). Can anyone please tell me how
to do it efficiently in R. One way I thought that I will draw
different random numbers fro
e variance for
each group (here month) is significantly different or not.
Can anyone suggest me any easiest way how to construct the test statistic,
described above?
Thanks
On Wed, Apr 23, 2008 at 12:21 PM, Arun Kumar Saha <[EMAIL PROTECTED]>
wrote:
> Hi all,
>
> I am wondering
Hi all,
I am wondering how to write a 'list' object to a file. I already gone
through some threads like
http://mail.python.org/pipermail/python-list/2001-April/080639.html, however
could not trace out any reliable solution. I tried following :
> write.table(calc, file="c:/data.csv")
Error in data
I am using R 2.6.2. under windows
On Wed, Feb 27, 2008 at 12:43 PM, <[EMAIL PROTECTED]> wrote:
> >From: Arun Kumar Saha <[EMAIL PROTECTED]>
> >Date: 2008/02/27 Wed AM 01:03:26 CST
> >To: "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
> >Subject: [
Hi all,
I wrote some user defined function for my own. Now I want to get a mechanism
so that every time I start R, those function will automatically be loaded in
R without manually copying pasting. Can gurus here pls tell me how to do
that? Or I have to build my own packages bundled with those fun
*hi
I aam facing following problem
my action executing twice when i try to load the tileslayout page as
actionforward success
*
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Hi all,
I have a time series like that :
DateValue
01/03/05 -0.008471364
01/04/05 -0.008153802
01/05/05 -0.000780031
01/06/05 -0.000130064
01/07/05 -0.000650576
01/08/05 -0.000130166
01/10/05 -0.004174282
01/11/05 0.01027384
01/12/05 -0.006099558
01/13/05 -0.009811054
01/
ual date format.
Can anyone tell me what should i do here?
Regards,
On 9/18/07, Arun Kumar Saha <[EMAIL PROTECTED]> wrote:
>
> Dear all,
>
> I have a variable 'x' like that:
>
> > x
> [1] "2005-09-01"
>
> Here, 2005 represents year, 09 m
lt;- '([[:digit:]]{4})-([[:digit:]]{2})-([[:digit:]]{2})'
> y <- sub(pattern, '\\1', x)
> m <- sub(pattern, '\\2', x)
> d <- sub(pattern, '\\3', x)
>
> -- Jeff.
>
> On Sep 18, 2007, at 5:00 AM, Arun Kumar Saha wrote:
>
> > D
Dear all,
I have a variable 'x' like that:
> x
[1] "2005-09-01"
Here, 2005 represents year, 09 month and 01 day.
Now I want to create three variables naming: y, m, and d such that:
y = 2005
m = 09
d = 01
can anyone tell me how to do that?
Regards,
[[alternative HTML version deleted]
Hi all,
I am looking for a function for following calculation.
start.month = "July"
end.month = "January"
months = f(start.month, end.month, by=1)
* f is the function that I am looking for.
Actually I want to get months = c("July", "August",.."January")
If start.month = 6 and end.
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