This thread strikes me as pretty far off-topic for a forum dedicated to
software support on R.
https://www.r-project.org/mail.html#instructions
"The ‘main’ R mailing list, for discussion about problems and solutions
using R, announcements (not covered by ‘R-announce’ or ‘R-packages’,
see above), a
To check whether the data are being read in appropriately, what happens
when you plot the distribution of each of the independent variables on
the respective systems?
-A
On Wed, 5 Jun 2019 12:32:28 +0200
Olivier Crouzet wrote:
> Hi,
>
> 32bit vs. 64bit systems?
>
> Another thing I would look
Hi all,
Following some updates to R that I received via Synaptic Package
Manager on Ubuntu 16.04 (looks like I now have R 3.4.4-1xenial0), I
have been unable to reinstall rgdal, and I need help.
Initially I was getting error messages about dependencies on GDAL
1.11.4, but after following instruct
I'm trying to develop a linear model for crop productivity based on
variables published as part of the SSURGO database released by the
USDA. My default is to just run lm() with continuous predictor
variables as numeric, and discrete predictor variables as factors, but
some of the discrete variable
Good afternoon.
We have two typesof forecast using time series: statistical forecast and
dynamic forecast. I would like to make dynamic forecastsimilar to what uses
Eviews software.
Does anyone know any package in R? Please.
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alid 'envir' argument of type 'logical'
Does anyone know why this is, or if there is something wrong with my code?
Thanks!
--
*Alexandra Hua *
Yale University | MPH Candidate Class of 2016
Chronic Disease Epidemiology
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_
igher than the 5*sigma value, I would think it would just pass
to the next loop, yet it doesn't. I will keep trying!
Thanks,
Alexandra
On Fri, Apr 10, 2015 at 3:43 PM, Jim Lemon wrote:
> Hi Alexandra,
> The error probably comes from the first iteration of i in 0:23. As indexing
> in R
the day 0:23.
Thanks,
Alexandra
On Fri, Apr 10, 2015 at 1:07 PM, Alexandra Catena wrote:
> Hello,
>
> I have a large dataframe (windHW) of wind speeds (ws) at each hour
> from many days over a set of years. Some of these values are
> obviously wrong (600 m/s) and I want to get ri
t for specific hours:
windHW$ws[windHW$ws>=spring$sigma5] <- NA
I imported the data using readLines and into the dataframe windHW. I
also have R version 3.1.1
Any help would be appreciated!
Thanks,
Alexandra
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d')
I also tried to make a dataframe of the tapply output but it ends up
using the hours as the column names instead of putting it into the
dataframe. Please help!!
I have R version 3.1.1
Thanks a lot,
Alexandra
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ingful for factors
In addition: Warning messages:
1: In Ops.factor(mydata[[wd]], 10) : %% not meaningful for factors
2: In Ops.factor(mydata[[wd]], angle) : / not meaningful for factors
Can anyone tell me what this means/what I'm doing wrong?
Also, I have R
seem to do anything.
> ltdl.fix.df(windMV, zero2na = FALSE, coded = 999)
n = 9432 by p = 4 matrix checked, 0 NA(s) present
0 factor variable(s) present
5675 value(s) coded 999 set to NA
0 -ve value(s) set to +ve half the negative value
I have R version 3.1.1
Than
from the last year. Also, I tried
Data[i] = readLines(sprintf('file/%4i,i))
but it says:
"number of items to replace is not a multiple of replacement length"
How do I get it to not replace each year of data? I have R version 2.15.1
Thanks,
Alexandra
[[alternative
Hello,
Can someone help me with unzipping a .gz file. I used:
readLines(gzfile('/home/file.gz'))
I also found that I could use gunzip, but after trying to install it, it
says:
"package ‘gunzip’ is not available (for R version 2.15.1)"
Thanks,
Alexandra
[[alte
2005:2015?
Thanks,
Alexandra
On Thu, Feb 5, 2015 at 3:11 AM, Jon Skoien
wrote:
> In addition to following Jim's suggestion, you should probably also use
> full.names = TRUE, otherwise you will try to open a connection to files in
> your current directory, not in tmpdir.
> Another
quot;/tmp/RtmpKvB4Wz/724927-23285-2015.gz"
next to 2015. and files returns 724927-23285-2015.gz. However, when I try
to unzip the gz file using the last line, it says it cannot open the
connection and the probable reason is that there is no such file or
directory.
T
Hey everybody,
I am looking for a R implementation of uni- and multivariate GMM clustering
which is both fast and can provide me with estimates of the respective
components' means and covariance matrices, not just the observations'
labels for the components which I am not interested in. As it is me
Hi,
Is there any package related to Analysis of a factorial experiment with
more than one control treatment?
if there is no package to do this, then, could you give me references of
books about it? For help to create a program for it.
Thanks.
Fiorella Flores
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Thank you for the reply!
I need to use it in the package for constructing the contrast matrices.
Renaming a variable like y2 <- y^2 will not be a solution for me...
Will try to look whether the function dummy.coef can be modified to work this
issue.
With best regards,
Alexandra
-Origi
ts_2.11.3 grid_3.0.1 gtools_3.0.0
minqa_1.2.1nlme_3.1-109
[8] rpart_4.1-1tools_3.0.1
With best wishes,
Alexandra
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] on behalf of
Alexandra Kuznetsova [a...@dtu.dk]
Sent: Thurs
gdata_2.13.2 gplots_2.11.3 grid_3.0.1 gtools_3.0.0
minqa_1.2.1nlme_3.1-109
[8] rpart_4.1-1tools_3.0.1
With best wishes,
Alexandra
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Hello,
I have data which I have arcsin transformed to analyse.
I want to plot my data with error bars however as my data is
back-transformed my standard errors are uneven.
Is there a simple way to draw these asymmetric error bars in R?
Thanks for your help.
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s
this example?
thanks a lot in advance I'm very desperate.
Alexandra
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eights as
this example?
thanks a lot in advance.
Alexandra
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umber of columns:
ncol(X1) ## 9
> ncol(X2) ## 11
## rank of design matrices:
qr(X1)$rank ## 9
qr(X2)$rank ## 10
Will be very grateful if someone could help me here!
Thanks,
Alexandra
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Dear members,
I'm trying to do a local polynomial estimation where the weight function is the
inverse of the kernel (using a gaussian kernel). Does anybody know how I can do
it?
When I work with a weigth function usual I use:
locfif(y~lp(x,deg=1,h=0.75),kern="gauss")
Does anybody know
Dear members,
I'm trying to estimate a varying coefficients model using the local polynomial
estimation method in two case (univariate and bivariate) and with two smooth
functions.
In the univariate case I use:
m1<-smooth.lf(x=lp(z1,by=x1,deg=1,h=0.7,ev=z1)+lp(z3,by=expl2,deg=1,h=0.7,ev=z1
his is not what I have to do.
Please, can somebody help me?
Thanks a lot.
Alexandra
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any other way to get a bivariate bandwidth in a local regression
polynomial?
I'll appreciate any query. I'm very lost and very desperate. I cannot find a
solution.
Thank you a lot in advance.
Alexandra
[[alternative HTML versi
t
if I state "x" is a matrix with 2 columns the program also works.
Please, somebody can help me?
Thanks a lot
Alexandra
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to find a way to do it in the bivariate case.
Please, help me.
Thanks you in advance
Alexandra
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PLEASE do read the pos
Dear all,
I'm trying to do a multivariate local regression whit the locfit instruction,
such as:Y=m(Z,X,W)+u
However, I have a problem at the moment of calculte the bandwith of the
regression. If I had a univarite local regression model I could use the
instruction "regband". However, t
Hello,
I want to create 2 variables with normal distribution that the correlation
between them is equal to 0.8 and also each one has a serial correlation equal
to 0.6.
To generate variables with correlation between them I use:
t1<-10
N<-45
sigma2<-matrix(c(1,0.8*sqrt(1),0.8*sqrt(1),1),
w how to do it with
variables uniformly distributed.
Thanks a lot.
Alexandra
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450x1).
Thanks a lot for your help.
Alexandra
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rfect for making
comparisons!
Thanks again to everybody who's tried to help me out on this!
Alexandra
On Thu, 2011-06-23 at 21:29 +0200, Jan van der Laan wrote:
> Alexandra,
>
> Have a look at add1 and drop1.
>
> Regards,
> Jan
>
>
> On 06/23/2011 07:32 PM, Ale
been able to
find is stepAIC(), which as far as I can tell only gives back the best
submodel, not a ranking of all submodels.
Thanks in advance,
Alexandra
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PLEASE do read t
On Thu, 2011-06-23 at 09:29 -0400, Alexandra Thorn wrote:
> Ok, here's some example code showing how I get different output for
AIC
> vs. mle.aic(). Now that I've taken another look at the independent
> variables, I'm wondering whether missing values in one of the
vari
avior
changes when I remove those...
Alexandra
#Code with outputs
R> require(wle)
R> xA # 1st independent variable (categorical)
[1] Diffuse Diffuse Diffuse Diffuse Diffuse Diffuse Diffuse Diffuse
Diffuse
[10] Diffuse Diffuse RingDiffuse Diffuse RingDiffuse Diffuse
Diffuse
[19] Diffu
The packages is wle.
I'll put together some code that shows the behavior I'm talking about,
and send it to the list.
Alexandra
On Thu, 2011-06-23 at 13:51 +0200, Rubén Roa wrote:
> I don't find the mle.aic function. Thus it does not ship with R and it's in
> some c
best
models and also compare to far inferior models?
Failing that, could someone point me to an appropriate resource that
might help me understand?
Thanks in advance,
Alexandra
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Hello,
I would like to find the power of the comparison of two ROC curves (paired
data). Is there an R function that does this?
Thank you,
Alexandra
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"You could try rlm in the MASS package; it doesn't use he resampling
step."
That seems to do the trick. Thank you!
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Sent from the R help mailing list archiv
Hello.
I've got a dataset that may have outliers in both x and y. While I am not
at all familiar with robust regression, it looked like the function lmrob in
package robustbase should handle this situation. When I try to use it, I
get:
Too many singular resamples
Aborting fast_s_w_mem()
Looki
Hi R users,
Does anyone know if Lo's modified R/S statistic is implemented in R?
Thank you very much,
Alexandra Almeida
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I am trying to plot fitted lme values as a smooth line of a graph
showing the exponential relationship between temperature and soil
respiration.
In the plot, the x-axis has temperature, and the y-axis has soil
respiration. When I try to add a line showing temperature versus the
fitted va
Hi everybody!
I´m with a problem that probably is easy for you but I really don´t know how
to solve.
On the following script:
for(j in 1:length(limiares))
{
excessos<-limiares[j]-estacao[estacao__
R-help@r-project.org mailing list
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Hi everybody!
I´m with a problem that probably is easy for you, but I really don´t know
how to solve.
On the following script:
for(j in 1:length(limiares))
{
excessos<-limiares[j]-estacao[estacao__
R-help@r-project.org mailing list
https://stat.ethz.
People,
I'm a ubunto user and I used to write my scipts in "Java Gui for R", but it
is a very slow tool to run my scripts...
Do you know some efficient IDE for R?
Thankssss!!!
Alexandra Almeida
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. Can anyone help
me?
Alexandra
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and provide comm
Hi,
Does anyone know an instruction to perform a test (or to construct a confidence
interval) for the variance of a normal population (distribution).
The test statistic is (n-1)*S´^2/sigma^2 and has chi square (n-1)
distribution.
Thank you,
Alexandra
[[alternative HTML
I am attempting to model data with the following variables:
timepoint - n=48, monthly over 4 years
hospital - n=3
opsn1 - no of outcomes
total.patients
skillmixpc - skill mix percentage
nurse.hours.per.day
Aims
To determine if skillmix affects rate (i.e. no.of.outcomes/total.patien
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