point (1,2) I would get 1+2/1 = 3
for point (2,10) I would get 2+10/2 = 7
for point (4,8) I would get 4+8/4 = 6
I have tried using sapply here but I get this:
> sapply(m,function(x,y) x+y/x)
Error in y/x : 'y' is missing
what I am doing wrong?
thanks
ADias
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Hi
I am trying to create a function that is able to calculate this sum:
a<-c(2,3,5)
b<-(8,7)
with "a" meaning 235 and "b" 87. So the result of this sum would be 235 + 87
= 322.
I've searched a function like strsplit but that worked for integers and in
reverse - not spliting but combining.
Can
Petr Pikal wrote:
>
> Hi
>
> r-help-boun...@r-project.org napsal dne 31.01.2011 09:44:00:
>
>>
>>
>> David Winsemius wrote:
>> >
>> >
>> > On Jan 30, 2011, at 5:27 PM, ADias wrote:
>> >
>> >> dados<-
&g
David Winsemius wrote:
>
>
> On Jan 30, 2011, at 5:27 PM, ADias wrote:
>
>> dados<-
>> data
>> .frame
>> (Store
>> =
>> c
>> ("Setubal
>> ","lx
>> ","Aveiro
>> ","Coimbra
&
Hi,
I have a data.frame and I need to know witch store sold more "Lapiseiras". I
got a point where I am almost sure I am very closed to the answer but I am
missing somethiing.
So, the data frame is this one
dados<-data.frame(Store=c("Setubal","lx","Aveiro","Coimbra","Aveiro","Evora","Aveiro","
I have done like this to get the result I need more directly
A<-c("Tell me how many different letter this vector has?")
prop.table(table(strsplit(A,"")))
?acdefhilmnors
t
0.16 0.02 0.04 0.02 0.02 0.14 0.04 0.06 0.04 0.06 0.04 0.04 0
rent from what I
am used to with other softwares. So I get really lost sometimes. But I am
getting better and I more and more find what I need just researching the
help pages.
many thanks
Regards,
ADias
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Hi,
I have this character vector:
A<-c("Tell me how many different letter this vector has?")
Is there a way with R that it can let me know how many different letters I
have on this vector?
If I use nchar(A) que gives me the number 50. With this function he is
counting all the letters present a
Pete Brecknock wrote:
>
> try ...
>
> new_m = m[c(2,7,8),c(1,4,6,7)]
>
> HTH
>
> Pete
>
Hi Pete,
I haven't understood what you wanted to say here. Can you explain please?
thanks
ADias
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Hi,
yes it works perfectly.
I have another question:
Is there way of selecting with a vector the values I wish to take out from a
matrix.
Example:
I have this matrix and I want to take out the numbers in bold and get the
second matrix below
>m
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,
Hi,
Is there an expression to double the values of a matrix - without using a
loop?
What I need is this:
Suppose we have this matrix
> m
[,1] [,2] [,3]
[1,]7 174
[2,] 11 10 18
[3,] 15 19 18
and I want this matrix
[,1] [,2] [,3]
[1,] 112 102 115
Hi,
Suposse I have a vector:
v->c(10,13,4,6,45,27,32,21,1,8,14,36)
how do i sort just the odd numbers leaving the rest - the even numbers - on
the same positions as they already are on the vector?
thanks
AD.
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Hi
Suppose we have an object with strings:
A<-c("a","b","c","d")
Now I do:
B<-matrix(A,4,4, byrow=F)
and I get
a a a a
b b b b
c c c c
d d d d
But what I really want is:
a b c d
b c d a
c d a b
d a b c
How can I do this?
thank you
A. Dias
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Hi,
I am with a problem on how to do a comparison of values. My script is as
follows:
repeat{
cat("How many teams to use? (to end write 0) ")
nro<-scan(n=1)
if(nro==0)break
cat("write the", nro, "teams names \n")
teams<-readLines(n=nro)
if (teams[1]==teams[2)next
else print(teams)
}
On this ex
Hi
Suppose you have the code below. The result I get from the cat function is
from the avgs object. Now, I have 30 diferent objects like this and I wish
to make a summary table, something like:
Avgs1 Avgs2
Avgs3
i= 2 ave
Hi,
Still with the above problem:
But for instance, i have a data base with 30 variables and I created an
object each with one varibale missing:
DataBase - has 30 variables
DataBase1 has 29 variables with the 1st variable gone
DataBase2 has 29 variables with the 2nd variable gone
for(i in 1:le
Hi
thank you all. I think I have what I need to solve my problem.
Regards,
A.Dias
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__
Hi,
I am having a problem in doing something similar to this example:
Suppose I have this vector a, and from it I wish to create 5 other vector
each one with less one value than what object a has
So I have "a"
a<-c(1,2,3,4,5)
and I want
a1 that shoud have (2,3,4,5)
a2 that should have (1,3,4,
thank you for the answers, problem solved
Regards,
ADias.
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R-help@r
epeat" but it doesn't work
repeat {
cat("Please, enter a number (Zero ends)")
n<-scan(n=1)
if(n==0)break
i<-("The number is odd")
p<-("The number is even")
if (n%%2==0)
p else i
}
thanks,
Regards,
ADias
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Hello,
thank you all. I have been able to solve my problem with your help.
The problem I am trying to solve is:
I am working on a clustering method to group a data base. At the moment I am
using the clustering hierarchical method and trying to get to the best K
group value via the silhouette fu
ADias wrote:
>
> Hi,
>
> I am using the code below to get a plot that will show me on the X axis
> the number of clusters and on the Y axis the cluster average widths.
> However I am getting this error:
>
> Error in summary(silhouette(cutree(d, x), dist(
Hi,
I am using code below to get a plot that will show me on the X axis the
number of clusters and on the Y axis the cluster average widths. However I
am getting this error:
Error in summary(silhouette(cutree(d, x), dist(iris[, -5])))$si.summary :
$ operator is invalid for atomic vectors
the
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