al Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of S Ellison
> Sent: Friday, May 26, 2017 8:28 AM
> To: A M Lavezzi ; r-help
> Subject: Re: [R] organizing data in a matrix avoiding loop
>
> > -Original Message-
> > From: A M > Lavezzi
Thanks a lot for your suggestion. I followed the suggestion of Sarah (the
first on the thread) and solved my problem
I will keep into account you suggestion anyway
Mario
On Fri, May 26, 2017 at 3:28 PM, S Ellison wrote:
> > -Original Message-
> > From: A M > Lavezzi
>
Hi Duncan
thanks a lot for your suggestion. I followed the suggestion of Sarah (the
first on the thread) and solved my problem
I will keep into account you suggestion anyway
Mario
On Fri, May 26, 2017 at 2:20 PM, Duncan Murdoch
wrote:
> On 26/05/2017 7:46 AM, A M Lavezzi wrote:
>
>
kage help?
>
> dfa<- data.frame(iso_o = letters[c(1, 1:4)], iso_d = letters[6:10], year =
> c(1985, 1985, 1986, 1987, 1988), flow = c(1,2,3,4, NA))
> reshape2::acast(dfa, iso_o ~ iso_d, fun.aggregate = sum, value.var =
> "flow")
>
> HTH
> Ulrik
>
> On Fri,
n't take forever as a loop,
> with only 215 entries.
>
> I find crosstab() from the ecodist package helpful. The current version is
> on GitHub, but not yet CRAN (soon!).
>
> Sarah
>
> On Fri, May 26, 2017 at 7:47 AM A M Lavezzi
> wrote:
>
>> Dear R-User
Dear R-Users
I have data on bilateral trade flows among countries in the following form:
> head(dataTrade)
iso_o iso_d year FLOW
1 ABW AFG 1985 NA
2 ABW AFG 1986 NA
3 ABW AFG 1987 NA
4 ABW AFG 1988 NA
5 ABW AFG 1989 NA
6 ABW AFG 1990 NA
where:
iso_o: co
id_cell$f_cell & f_cell_neigh %in%
> id_cell$f_cell)
> result.m <- matrix(NA, nrow=nrow(id_cell), ncol=nrow(id_cell))
> result.m[cbind(factor(result$f_cell), factor(result$f_cell_neigh))] <-
> result$distance
> })
>
> user system elapsed
> 0.361 0.0
to
"result" with the id of the firms.
On Fri, May 13, 2016 at 3:26 PM, A M Lavezzi wrote:
>
> Hello Sarah
> thanks a lot for your advice.
>
> I followed your suggestions unitl the creation of "result"
>
> The allocation of the values of result$distance t
neigh=seq_len(100))
> censDist$distance <- runif(nrow(censDist))
>
> # assemble the non-symmetric distance matrix
> result <- subset(censDist, fcell %in% idcell$fcell & cellneigh %in%
> idcell$fcell)
> result.m <- matrix(NA, nrow=nrow(idcell), ncol=nrow(idcell))
> res
Hello,
I have a sample of 1327 locations, each one idetified by an id and a
numerical code.
I need to build a spatial matrix, say, M, i.e. a 1327x1327 matrix
collecting distances among the locations.
M(i,i) should be 0, M(i,j) should contain the distance among location i and
j
I shoud use data
ot;,"0","1","1","0"),
SECTION = c(1288, 1261, 1287, 1264, 1287,
1262,1500,1505,1510,1520,1530,1610,1615)),
.Names = c("CODICE","STRADA", "AREADICIRCOLAZIONE", "NUMBER1",
"BARRATO1", "NUMBER2","BA
;,F1_ex[,2]))),word,c(1,3,4,2)),paste,collapse="
> ")
> vec2<- as.numeric(gsub("\\D+","",F1_ex[,2]))
> F1_ex[,1]<-F2_ex[sapply(vec2,function(x) which((x>F2_ex[,4] & x< F2_ex[,6])
> & paste(F2_ex[,2],F2_ex[,3])%in%vec1)),"SECTION"
the
> name is slightly different, element A15 should be added to row 1) of F1,
> producing an output such as:
>
> 1) Street | J.F. Kennedy | 30 | A15
>
>
> hope this clarifies the issue.
>
> thanks a lot! Mario
>
>
>
> Il 21/06/2013 15:29, arun ha scritto:
Hello everybody
I have this problem: I need to match an addresses database F1 with the
information contained in a toponymic database F2.
The format of F1 is given by three columns and 800 rows, with the
columns being:
A1. Street/Road/Avenue
A2. Name
A3. Number
Consider for instance Avenue J. Ke
ou should be able to make
> > the modifications.
> >
> > HTH,
> > Ivan
> >
> > --
> > Ivan CALANDRA
> > Université de Bourgogne
> > UMR CNRS/uB 6282 Biogéosciences
> > 6 Boulevard Gabriel
> > 21000 Dijon, FRANCE
> > +33(0)3.80.39.63.06
Hello everybody
I have the following problem. I have to load a number of xls files from
different folders (each xls file has the same number of columns, and
different numbers of rows). Each xls file is named with a number, i.e.
12345.xls and is contained in a folder with same name, say 12345)
Onc
it works!
thank you so much
Mario
On Fri, Jan 14, 2011 at 1:29 PM, Henrique Dallazuanna wrote:
> Try this:
>
> !list %in% c("aa", "bb")
>
> On Fri, Jan 14, 2011 at 10:19 AM, A M Lavezzi wrote:
>
>> Hi everybody,
>>
>> I have the
Hi everybody,
I have the following problem. I have a vector containing character elements,
such as:
list = c("aa","bb","cc","dd","ee")
I want to create an index which identifies the elements that are different
from, e.g. "aa" and "bb".
When I do the following:
jj = list!="aa" & list!="bb"
> j
Hello,
I'm starting to use CLUE to compare clusterings.
I have some cluster structures obtained outside R, which are simlply vectors
of lenght N (N: number of objects), which contain a number indicating the
cluster to which each object belongs. I report below a portion of one of
these:
--
[1:11] 2 2 2 2 3 3 5 4 2 1 ...
> > values : int [1:11] 3 1 3 1 3 1 3 1 3 1 ...
> >
> > > table(res$lengths[res$values == 1])
> >
> > 1 2 3 4
> > 1 2 1 1
> >
> >
> > HTH,
> >
> > Marc
> >
> >
> >
> > On Thu,
ncoding
> lengths: int [1:11] 2 2 2 2 3 3 5 4 2 1 ...
> values : int [1:11] 3 1 3 1 3 1 3 1 3 1 ...
>
> > table(res$lengths[res$values == 1])
>
>1 2 3 4
>1 2 1 1
>
>
>HTH,
>
>Marc
>
>
>On Thu, 2007-11-15 at 17:18 +0100, A M Lavezzi wrote:
> > Dea
ask how to do this?
Thanks again
Mario
At 16.48 15/11/2007, you wrote:
>On Thu, 2007-11-15 at 15:51 +0100, A M Lavezzi wrote:
> > Hello
> >
> > I have this problem. I have a large matrix of this sort:
> >
> > > prova
> > [,1] [,2] [,3] [,4]
>
Hello
I have this problem. I have a large matrix of this sort:
> prova
[,1] [,2] [,3] [,4]
[1,]3333
[2,]3331
[3,]1333
[4,]1113
[5,]3113
[6,]3113
[7,]1313
[8,]1333
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