On Saturday, May 31st, 2025 at 7:44 PM, Bert Gunter
wrote:
> JRG:
>
> I don't think your specification is correct -- perhaps just a thinko. I think
> a 10-tuple of "reals" (scare quotes because of computer precision) with your
> specifications is what is wanted.
>
> Bert
>
> "An educated perso
JRG:
I don't think your specification is correct -- perhaps just a thinko. I
think a 10-tuple of "reals" (scare quotes because of computer precision)
with your specifications is what is wanted.
Bert
"An educated person is one who can entertain new ideas, entertain others,
and entertain herself."
I'll second Bert's comments, also assuming this is not homework. In addition:
Your use of "mid-point" is not a standard one (in my world), nor perhaps is
that of "simulate".
Let me attempt to re-state your problem: You wish to choose 10-tuples of
integers 0 <= k <= 100 satisfying
1) 0 <= k_i
If this is a real problem and not homework, can you tell us the
context? It is not at all clear (to me) what you mean by "simulate",
i.e. what your target distribution is, which may depend on/be defined
by the context.
Bert
"An educated person is one who can entertain new ideas, entertain
others,
Your description is not clear at the point where you "project it to the
original space."
Anyway, this sounds like homework, as the solution to this particular example
is trivial when considered from the right point of view.
On May 31, 2025 12:06:49 PM PDT, Sergei Ko wrote:
>Hi!
>Just an idea.
Hi!
Just an idea. You randomly select the first point. Cut +/- 5 from the
original space [0;100]. Select second point. Project it to the original
space. Cut again. Repeat.
Simplified method without cutting: every time mark +/- 5 as a bad space and
select point again if it is in forbidden area.
Hope
Hi,
Let say I have a range [0, 100]
Now I need to simulate 1000 10 mid-points within the range with
accuracy upto second decimal number.
Let say, one simulated set is
X1, X2, ..., X10
Ofcourrse
X1 < X2 < ... https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide https:/
Hi,
I tried to convert a date-like string to date as below
as.Date("202012", format = "%y%m")
This gives NA
Could you please help why I am getting NA value?
__
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https://stat.ethz.ch/mai
Hello,
Inline.
Às 17:56 de 31/05/2025, Dirk Eddelbuettel escreveu:
On 31 May 2025 at 22:02, Christofer Bogaso wrote:
| I tried to convert a date-like string to date as below
|
| as.Date("202012", format = "%y%m")
|
| This gives NA
|
| Could you please help why I am getting NA value?
A _Date_
The akima package has a somewhat problematic license (the ACM license,
which doesn't allow commercial use). The interp package provides some
of the same functionality but is free open source.
rgl has some support for output from interp. I forget if it would also
work with akima.
Duncan
On
On 31 May 2025 at 22:02, Christofer Bogaso wrote:
| I tried to convert a date-like string to date as below
|
| as.Date("202012", format = "%y%m")
|
| This gives NA
|
| Could you please help why I am getting NA value?
A _Date_ is comprised of three values for _year_, _month_ and _day_.
What y
Read ?strptime.
%y is not the same thing as %Y.
On May 31, 2025 9:32:26 AM PDT, Christofer Bogaso
wrote:
>Hi,
>
>I tried to convert a date-like string to date as below
>
>as.Date("202012", format = "%y%m")
>
>This gives NA
>
>Could you please help why I am getting NA value?
>
>_
If I remember correctly, %y is the last 2 digits of the year, so 90 would
be 1990 and 15 would be 2015. I think you meant %Y
I think you can find this in ?Date, or maybe ?strptime, I can't remember
exactly.
On Sat, May 31, 2025, 12:38 Christofer Bogaso
wrote:
> Hi,
>
> I tried to convert a date
I'll mention that the 'akima' package is also handy for this kind of
interpolation.
On 5/31/25 11:18, Duncan Murdoch wrote:
On 2025-05-31 7:04 a.m., ravi via R-help wrote:
Hi,
rgl plots seem to require the z object in the form of a matrix. I
would like some help in constructing this matrix
On 2025-05-31 7:04 a.m., ravi via R-help wrote:
Hi,
rgl plots seem to require the z object in the form of a matrix. I would like
some help in constructing this matrix when I cannot use the outer function. Let
me explain.
library(rgl)
library(plot3D)
x <- 1:10
y <- 1:20
fun1 <- function (x,y) {x
In the general case you cannot do that... you have to choose a way to
interpolate your data points from a known x,y partition like your first example
(your interpolation gets used as "f").
In the special case where your points in the data frame were generated as a
grid, then you should still ha
Hi,
rgl plots seem to require the z object in the form of a matrix. I would like
some help in constructing this matrix when I cannot use the outer function. Let
me explain.
library(rgl)
library(plot3D)
x <- 1:10
y <- 1:20
fun1 <- function (x,y) {x^2+y^2}
z <- outer(x,y, fun1)
open3d()
surface3d(x
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