IMO assuming periodicity is a bad practice for this. Missing timestamps happen
too, and there is no reason to build a broken analysis process.
On August 29, 2021 7:09:01 PM PDT, Richard O'Keefe wrote:
>Why would you need a package for this?
>> samples.per.day <- 12*24
>
>That's 12 5-minute inter
Why would you need a package for this?
> samples.per.day <- 12*24
That's 12 5-minute intervals per hour and 24 hours per day.
Generate some fake data.
> x <- rnorm(samples.per.day * 365)
> length(x)
[1] 105120
Reshape the fake data into a matrix where each row represents one
24-hour period.
> m
On Sat, 28 Aug 2021, Rolf Turner wrote:
On Sat, 28 Aug 2021 12:49:04 +0300
Eric Berger wrote:
As Achim wrote in point (2), Makefile is your friend.
Well, all I can say is that Makefile is *not* my friend; I have never
made its acquaintance and wouldn't know where to begin looking.
Would i
On Sun, 29 Aug 2021, Rich Shepard wrote:
But, ... help.
Sigh. It helps to start ESS in emacs first.
Rich
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PLEASE do read the posting gu
Just upgraded to R-4.1.1-x86_64-1_SBo on Slackware-14.2/x86_64. While it's
been a while since I last ran R trying 'Alt + -' to enter the assignment
monitor is not working. Assuming the problem is with me I'm not finding what
I'm doing incorrectly in all the docs I searched and I'm suitably
embarra
On Sun, 29 Aug 2021, Andrew Simmons wrote:
I would suggest something like:
Thanks, Andrew.
Stay well,
Rich
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PLEASE do read the posting
On Sun, 29 Aug 2021, Rui Barradas wrote:
Hope this helps,
Rui,
Greatly! I'll study it carefully so I fully understand the process.
Many thanks.
Stay well,
Rich
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Hello,
I forgot in my previous answer, sorry for the duplicated mails.
The function in my previous mail has a na.rm argument, defaulting to
FALSE, pass na.rm = TRUE to remove the NA's.
agg <- aggregate(cfs ~ date, df1, fun, na.rm = TRUE)
Or simply change the default. I prefer to set na.rm
On Sun, 29 Aug 2021, Jeff Newmiller wrote:
You may find something useful on handling timestamp data here:
https://jdnewmil.github.io/
Jeff,
I'll certainly read those articles.
Many thanks,
Rich
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Hello,
You have date and hour in two separate columns, so to compute daily
stats part of the work is already done. (Were they in the same column
you would have to extract the date only.)
# convert to class "Date"
df1$date <- as.Date(df1$date)
# function to compute the stats required
# it's
Hello,
I would suggest something like:
date <- seq(as.Date("2020-01-01"), as.Date("2020-12-31"), 1)
time <- sprintf("%02d:%02d", rep(0:23, each = 12), seq.int(0, 55, 5))
x <- data.frame(
date = rep(date, each = length(time)),
time = time
)
x$cfs <- stats::rnorm(nrow(x))
cols2aggregate
On Sun, 29 Aug 2021, Rui Barradas wrote:
I forgot in my previous answer, sorry for the duplicated mails.
The function in my previous mail has a na.rm argument, defaulting to FALSE,
pass na.rm = TRUE to remove the NA's.
agg <- aggregate(cfs ~ date, df1, fun, na.rm = TRUE)
Or simply change the
You may find something useful on handling timestamp data here:
https://jdnewmil.github.io/
On August 29, 2021 9:23:31 AM PDT, Jeff Newmiller
wrote:
>The general idea is to create a "grouping" column with repeated values for
>each day, and then to use aggregate to compute your combined results.
On Sun, 29 Aug 2021, Jeff Newmiller wrote:
The general idea is to create a "grouping" column with repeated values for
each day, and then to use aggregate to compute your combined results. The
dplyr package's group_by/summarise functions can also do this, and there
are also proponents of the data
On Sun, 29 Aug 2021, Eric Berger wrote:
Provide dummy data (e.g. 5-10 lines), say like the contents of a csv file,
and calculate by hand what you'd like to see in the plot. (And describe
what the plot would look like.)
Eric,
Mea culpa! I extracted a set of sample data and forgot to include it
The general idea is to create a "grouping" column with repeated values for each
day, and then to use aggregate to compute your combined results. The dplyr
package's group_by/summarise functions can also do this, and there are also
proponents of the data.table package which is high performance bu
Hi Rich,
Your request is a bit open-ended but here's a suggestion that might help
get you an answer.
Provide dummy data (e.g. 5-10 lines), say like the contents of a csv file,
and calculate by hand what you'd like to see in the plot. (And describe
what the plot would look like.)
It sounds like what
I have a year's hydraulic data (discharge, stage height, velocity, etc.)
from a USGS monitoring gauge recording values every 5 minutes. The data
files contain 90K-93K lines and plotting all these data would produce a
solid block of color.
What I want are the daily means and standard deviation fro
Thanks Jeff,
It worked!!
From: Jeff Newmiller
Sent: Saturday 28 August 2021 16:32
To: r-help@r-project.org ; Eliza Botto
; r-help@r-project.org
Subject: Re: [R] Finding if numbers fall within a range
You messed up the dput somehow... but I think this works:
m <
dear Duncun,
Thanks a lot...
From: Duncan Murdoch
Sent: Sunday, August 29, 2021 5:49 PM
To: akshay kulkarni ; Enrico Schumann
Cc: R help Mailing list ; r-help-requ...@r-project.org
Subject: Re: [R] coercion to an object...
On 29/08/
On 29/08/2021 7:52 a.m., akshay kulkarni wrote:
dear Enrico,
it works. Thanks a lot. I spent over an hour looking
for this function in the web, but was bootless. Do you have any way to get
functions where you are given what it has to do? The most common case is that
you
Thank you Jeff. This solves my problem.
On 2021-08-28 21:54, Jeff Newmiller wrote:
Maybe you will find that coord_cartesian( ylim=c(-30,30) ) works
better since it doesn't filter out data before rendering.
On August 28, 2021 6:45:11 PM PDT, p...@philipsmith.ca wrote:
I am preparing a time serie
dear Enrico,
it works. Thanks a lot. I spent over an hour looking for
this function in the web, but was bootless. Do you have any way to get
functions where you are given what it has to do? The most common case is that
you are given a list of functions, but they number to
On Sun, 29 Aug 2021, akshay kulkarni writes:
> Dear members,
> I think the following question is rudimentary,
> but I couldn't find an answer in the Internet.
>
> Suppose there is an object A, and ls() lists it as "A". How do you convert
> this character object to th
Dear members,
I think the following question is rudimentary, but
I couldn't find an answer in the Internet.
Suppose there is an object A, and ls() lists it as "A". How do you convert this
character object to the object A. i.e I want a function f such that
class(f("A
It is a general "feature" of TeX that documents with tables of
contents, indices,
bibliographies, and so on, have to be "iterated to convergence". A couple of
PhD theses came out of Stanford; the problem is in that which page one thing
goes on depends on where other things went, which depends on w
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