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On May 26, 2021 9:29:10 PM PDT, Kai Yang via R-help
wrote:
>Hi List,
>I wrote the code to create a new variable:
>CRC$MMR.gene<-ifelse(grep("MLH1"|"MSH2",CRC$gene.all,value=T),"Yes","No")
>
>
>I need to create MMR.gene column in CRC data frame, ifgene.all column
>c
I meant:
x0 = c (1, 1e-3, 0)
Not:
x0 = c (1, 1e6, 0)
So, large intentional error may work too.
Possibly, better...?
On Thu, May 27, 2021 at 6:00 PM Abby Spurdle wrote:
>
> If I can re-answer the original post:
> There's a relatively simple solution.
> (For these problems, at least).
>
> #wrong
If I can re-answer the original post:
There's a relatively simple solution.
(For these problems, at least).
#wrong
x0 = c (1, 0, 0)
NlcOptim::solnl(x0, objfun = f, confun = conf)$par
Rdonlp2::donlp2(x0, fn = f, nlin = list(heq), nlin.lower = 0,
nlin.upper = 0)$par
#right
x0 = c (1, 1e6, 0)
NlcOpt
Hi List,
I wrote the code to create a new variable:
CRC$MMR.gene<-ifelse(grep("MLH1"|"MSH2",CRC$gene.all,value=T),"Yes","No")
I need to create MMR.gene column in CRC data frame, ifgene.all column contenes
MLH1 or MSH2, then the MMR.gene=Yes, if not,MMR.gene=No
But, the code doesn't work for me
I need to retract my previous post.
(Except the part that the R has extremely good numerical capabilities).
I ran some of the examples, and Hans W was correct.
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Thank you for the reprex. However your specification was too vague for me
to know exactly what your data are like, so I tried to assume the most
general possibility, with the consequence that I may be giving you an
answer to the wrong question. Hopefully, you can adjust as needed to get
what you wa
Hello,
I am trying to convert a df (given below as d1) into df2 (given below as
res).
I tried using loops for each row. I cannot get it right. Moreover the df
is 25 x 500 in dimension and I cannot get it to work.
Could anyone help me here please.
Thanks.
Adrian.
d1 <-
structure(list(S1 =
Hello,
I too don't see why grouping is needed but here it goes.
df1 %>%
group_by(Department, Class) %>%
mutate(Value = Value + 5*(Date == "4.01.2020"))
Hope this helps,
Rui Barradas
Às 17:01 de 26/05/21, Christopher W Ryan via R-help escreveu:
Is the grouping beforehand necessary? Coul
Is the grouping beforehand necessary? Could you simply, "for all the dates
that are "4.01.2020" and have the "Value" greater than zero add 5 to the
"Value" "? I may be missing something.
--Chris Ryan
On Wed, May 26, 2021 at 11:53 AM Elahe chalabi via R-help <
r-help@r-project.org> wrote:
> Hi
Hi everyone,
I have the following dataframe:
structure(list(Department = c("A", "A", "A", "A", "A", "A", "A",
"A", "B", "B", "B", "B", "B", "B", "B", "B"), Class = c(1L, 1L,
1L, 1L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L), Value = c(0L,
100L, 800L, 800L, 0L, 300L,
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