Hi Rachida,
My guess is that you create a vector of filenames:
filenames<-list.files(path="FicConfig",pattern="*.txt")
then use the filenames in the loop:
for(filename in filenames) {
nextfile<- read.table(filename, header = TRUE, sep = "\t" , dec =
",", skip = 0)
# do whatever you want with
Also (I think):
https://cran.r-project.org/web/views/NaturalLanguageProcessing.html
(get to know the CRAN resources!).
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip
Hi Marcelo,
Just google for "word cloud r". Too much information.
Jim
On Tue, Mar 30, 2021 at 11:18 AM Marcelo Laia wrote:
>
> Hi,
>
> I would like to do a word cloud in a specif site related to a specific
> word.
>
> For example, I could be interested in discovery what are the words
> linked to
Hi,
I would like to do a word cloud in a specif site related to a specific
word.
For example, I could be interested in discovery what are the words
linked to word "tree" in a site like www.foo.bar and have the result in
a wordcloud image.
Please, someone could me point me out a package or a bibl
Hi Abby,
Have a look at the first example in the radial.pie function (plotrix).
Jim
On Tue, Mar 30, 2021 at 7:59 AM Abby Spurdle wrote:
>
> I couldn't find a predefined function for this purpose.
> However, it wouldn't be too difficult to write a pair of functions.
>
> The big question is how fl
Dear V. K. Chetty,
Perhaps I'm missing something but why wouldn't you just use a list of
matrices, as in the following?
-- snip -
> set.seed(123) # for reproducibility
> (Matrices <- lapply(1:3, function(i) matrix(sample(1:50, 4), 2, 2)))
[[1]]
[,1] [,2]
[1,] 31 14
I understand that I came across this error after that
ind <- get_famd_ind(res.famd)
fviz_famd_ind(res.famd,
col.ind = ifelse(ind>10,"red","black"),
repel = TRUE)
Error in ifelse(ind > 10, "red", "black") :
'list' object cannot be coerced to type 'double'
Calls: fvi
I want to use map and purr functions to compute eigen values for 3000
matrices. Each matrix has 2 rows and 2 columns. The following code does not
work.
test.dat<- tibble(ID=c(1,2),a=c(1,1),b=c(1,1),c=c(2,2),d=c(4,3))
test.out<-test.dat %>% nest(-ID) %>% mutate(fit = purrr::map(data,~
function(x)
That error means that fviz_famd_ind has more than one argument that
starts with 'col' and you must type a more complete name to
disambiguate it. Perhaps col.ind=ifelse(...)?
> args(factoextra::fviz_famd_ind)
function (X, axes = c(1, 2), geom = c("point", "text"),
repel = FALSE, habillage = "n
Hi Jim,
It seems that the following proposed method doesn't work
ind <- get_famd_ind(res.famd)
fviz_famd_ind(res.famd,
col=ifelse(x>10,"red","black"),
repel = TRUE)
Result is:
Error in fviz_famd_ind(res.famd, col = ifelse(x > 10, "red", "black"), :
argument 2 m
I couldn't find a predefined function for this purpose.
However, it wouldn't be too difficult to write a pair of functions.
The big question is how flexible does the rendering function need to be?
#plot from angles, distances, etc
#(angles on arbitrary scale)
spiechart.render <- function (
an
Hi!
I am also learning, but I want try to help. I often use for-loop in R. I think
that it could be due to dimensions of CPM, not the structure of the loop.
What kind of error message do you get? Is it: �incorrect number of dimensions�?
What happens if you substitute in the end instead of CPM[i
Thank you Bill for your help! In other cases this surely is good thing to
check, but in my case it helped earlier today that I removed .RData file
according to Jeff�s answer:
�Check if you have a .RData file in your R startup directory. It may contain
the seed.�
Now that this file doesn�t exis
Maximum at the right endpoint is well accpted in both cases. If I am correst, I
just append -Inf at the right end and then I apply what you wrote.
Thank you.
(oo)
--oOO--( )--OOo--
Stefano Sofia PhD
Civil Protection - Marche Region - Italy
Meteo Secti
Your original query included
> x <- c(1,0,0,0,2,2,3,4,0,1,1,0,5,5,5,0,1)
... I need 8 10 13.
Did you also want the 1's at the ends to count as local maxima,
so the result would be c(1,8,10,13,17)?
Or do you want the maxima at endpoints only if there are no others?
-BIll
On Mon, Mar 29, 20
Does this happen if you start R with the --vanilla flag? If so it may
be that you have a startup file, .\.Rprofile or %HOME%\.Rprofile that
is calling set.seed(n) for a fixed n.
-Bill
On Mon, Mar 29, 2021 at 12:16 AM Mika Hamari wrote:
>
> Hi!
>
> I have Windows 10 on PC and different versions
Thank you Bill, your tip solved everything.
Stefano
(oo)
--oOO--( )--OOo--
Stefano Sofia PhD
Civil Protection - Marche Region - Italy
Meteo Section
Snow Section
Via del Colle Ameno 5
60126 Torrette di Ancona, Ancona (AN)
Uff: +39 071 806 7743
E-mail: s
If you want to accept maxima at the ends of the series, append -Inf to
each end and subtract one from the result. Note that this will make
even a constant sequence have a local maximum at 1.
On Mon, Mar 29, 2021 at 6:52 AM Stefano Sofia
wrote:
>
> Dear Bill, Bert, Greg and Abby,
> I tested your
Hi everyone,
I am new to R programming, and I am having difficulties modifying an R
script to introduce the "for" loop in the code.
While searching I found that this issue has already been raised, but I did
not know what to do to fix mine !
*The code that works (without for command):*
CPM <- read
Hello All,
Thanks Rui for your response to my question. I agree that it is possible to use
a workaround. Get most of what you want and then tidy it up afterwards. I too
have a workaround that I have pasted below. I wanted to avoid that initially. I
felt I was only using a workaround because I h
Stefano,
i notice that my and Bill's (pretty much isomorphic) solutions give a
zero-length vector. i don't remember Bert's, but it's probably gives
similar results. your code could check for that result, and react
accordingly.
cheers, Greg
__
R-help@
Dear Bill, Bert, Greg and Abby,
I tested your code (honestly apart from Abby's solution because it needed an
additional package and I run R in a server which is not administrated by
myself), they work and I found them equivalent. (Probably Bill's and Greg's
solutions are a bit faster than Bert's
Ferri,
Radar Charts are often used to compare two or more items or groups on various
features or characteristics. However, as the number of groups increases, the
user has a harder time making comparisons between groups. As the number of
groups increase, the number of spokes of the radar chart in
Thank you, Jeff! I had that file, and when I removed it, that solved the
problem. Now random numbers are really random. Excellent!
Mika
Lähetetty Samsung Galaxy -älypuhelimesta.
Alkuperäinen viesti
Lähettäjä: Jeff Newmiller
Päivämäärä: 29.3.2021 10.31 (GMT+02:00)
Saaja: r-h
Check if you have a .RData file in your R startup directory. It may contain the
seed.
.RData files (without anything in front of the period) are dangerous... many R
users avoid them because they can easily drag in mistakes from previous
sessions to plague you.
On March 28, 2021 9:02:17 AM PDT,
Hi!
I have Windows 10 on PC and different versions of R. I noticed that when I
executed simulation with R 4.0.3, it gave exactly the same results next time
when I re-opened the program. I didn�t set the seed.
I tested this also with simple �rnorm(10,100,10)�, and the results were every
time th
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