Hellow Rui,
The code helped.
I am very grateful.
Jibrin
On Mon, Jan 18, 2021 at 12:14 AM Rui Barradas wrote:
> Hello,
>
> My code didn't produce only 6 rows, it displayed only 6 rows. But all
> rows now have a date column.
>
> As for the first question,
>
> df2 <- df1[c("SWS", "date")]
>
>
> sel
Thanks David
Bernard
Sent from my iPhone so please excuse the spelling!"
> On Jan 17, 2021, at 5:59 PM, David Winsemius wrote:
>
>
>> On 1/17/21 12:15 PM, Bernard McGarvey wrote:
>> I have a data frame that consists of several factor columns say A, B, C, D,
>> and E and several columns conta
Hello,
My code didn't produce only 6 rows, it displayed only 6 rows. But all
rows now have a date column.
As for the first question,
df2 <- df1[c("SWS", "date")]
selects the columns with those names. I didn't rewrite the original df1,
but if you want to, assign to df1, without creating df2
On 1/17/21 12:15 PM, Bernard McGarvey wrote:
I have a data frame that consists of several factor columns say A, B, C, D, and
E and several columns containing numerical data, say X1, X2, X10. I would
like to create statistics of some of the numerical columns by some of the
factor columns
Hi, If I am using caret and MAE metric, how can we get median of MAE in
easy manner.
cart <-train(Result ~ ., data = tr,
method = "rf",
metric = "MAE",
preProc = c("center", "scale", "nzv"),
trControl = ctr)
[[alternative HTML version deleted]]
___
Thanks Bert
Bernard
Sent from my iPhone so please excuse the spelling!"
> On Jan 17, 2021, at 3:48 PM, Bert Gunter wrote:
>
>
> There are literally tons of ways to do this sort of thing in R.
>
> In base R ?tapply and friends, especially ?ave and ?by that may be close to
> what you want.
>
Dear Gregory Coast,
Thanks for your reply.
I searched so much regarding how to fix this problem. Unfortunately, it
stems from Bug Sur 11.0.1 and we should wait for its new version in which
the problem has been fixed.
Best,
Maedeh Kamali
On Sat, 16 Jan 2021, 08:18 Gregory Coats, wrote:
> I repo
There are literally tons of ways to do this sort of thing in R.
In base R ?tapply and friends, especially ?ave and ?by that may be close to
what you want.
But there is a whole parallel universe -- the so-called "tidyverse set of
packages -- that many folks prefer.
This link takes you down that rab
I have a data frame that consists of several factor columns say A, B, C, D, and
E and several columns containing numerical data, say X1, X2, X10. I would
like to create statistics of some of the numerical columns by some of the
factor columns. For example,
Calculate the mean, min, and max
Eric,
No problem. Let's see if somebody else has a solution. I have changed the
smooth basis from P-splines ('ps') to thin plate ('tp'). It still does not
work, but this time I get another error message.
##
#Data
y=c(34000,45000,19000,48900,65000,67000,78000,9,51000
This is an opportunity for you to think for yourself (r-help) instead of
expecting solutions neatly wrapped and delivered (r-do-my-work-for-me). Remove
the no-longer-needed columns once the desired columns are available.
On January 17, 2021 7:12:28 AM PST, Jibrin Alhassan
wrote:
>Hi Barradas,
Hi Barradas,
Thanks for your assistance. It has brought me closer to what I am looking
for. I tried your code as shown below:
> df1 <- read.table("SWSdata_1998_2002", header = TRUE)
> df1$date <- as.Date(paste(df1$year, df1$day),format = "%Y %j",origin =
"1998-01-01")
> head(df1)
year day Hr SWS
Hi Sacha,
I took a quick look. Sorry, I don't see immediately what is causing the
problem.
Maybe someone else can help.
On Sun, Jan 17, 2021 at 3:22 PM varin sacha wrote:
> Dear Eric,
>
> Many thanks, I correct your 2 points and now I get another error message
> (Error in splineDesign(knots, x,
Dear Eric,
Many thanks, I correct your 2 points and now I get another error message (Error
in splineDesign(knots, x, ord, derivs, outer.ok = outer.ok, sparse = sparse) :
empty 'derivs').
I have googleized and found some hints like (outer.ok=TRUE) but no one seems to
work.
https://r.789695.n4
Hi Sacha,
I never used these packages before but I installed them and tried your
code. I have a few observations that may help.
1. the statement
ypred = predict(fit18,newdata=Testing)
is wrong. Checkout the help page (?robustgam) which shows in the
Examples section at the bottom to use so
Dear R-experts,
Here below my reproducible R code. I get an error message (end of code) I can't
solve.
Many thanks for your help.
##
#Data
y=c(34000,45000,19000,48900,65000,67000,78000,9,51000,32000,54000,85000,38000,76345,87654,90990,78654,67894,56789,65432,18998,789
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