Hi Chao Liu,
I'm having difficulty following your question, and examples.
And also, I don't see the motivation for increasing, then decreasing
the sample sizes.
Intuitively, one would compute the correct sample sizes, first time round...
But I thought I'd add some comments, just in case they're u
Don't set the header argument to TRUE if your data does not have a header?
On December 16, 2020 11:09:18 AM PST, Gregory Coats via R-help
wrote:
>I would like to be able to draw and label a vertical line, representing
>the date of some arbitrary event. The date of the first non-zero entry
>is 20
- Forwarded Message - From: PIKAL Petr To:
azam jaafari Cc: r-help mailing list
Sent: Wednesday, December 16, 2020, 3:39:06 PM
GMT+3:30Subject: RE: [R] space between bars of a group in ggplot2
Hi,
Keep your emails on the list, please.
here are some artificial data
dput(dat)
str
I would like to be able to draw and label a vertical line, representing the
date of some arbitrary event. The date of the first non-zero entry is
2013-11-29. How would I draw and label a red vertical line at 2019-04-06? Greg
gcdf<-read.table(text="2013-11-29 00.000
2013-12-29 19.175
2014-01-20 1
You didn't show the entire call to read.table. If it included the argument
header=TRUE then it would make the first entry in each column the name of
the column. Use header=FALSE (or omit the header argument) if you don't
want the first entry to be considered the column name.
-Bill
On Wed, Dec 1
I added a zero initial entry to the data set. Greg
gcdf<-read.table(text="2013-11-29 00.000
2013-12-29 19.175
2014-01-20 10.072
2014-02-12 10.241
2014-03-02 05.916
> On Dec 16, 2020, at 12:32 PM, Gregory Coats via R-help
> wrote:
>
> Jim, Thank you!
> The data set begins
> gcdf<-read.table(text
Sigh. You still haven't read the Posting Guide? HTML email causes problems with
this mailing list so do send email using your mail client's plain text option.
You assert that
>The probability of excluding an observation within each cluster was not uniform
but having a different number excluded
Jim, Thank you!
The data set begins
gcdf<-read.table(text="2013-12-29 19.175
2014-01-20 10.072
2014-02-12 10.241
I note that data begins in 2013. But the plot command does not show this first
entry in 2013, and instead shows the second data pair as the first data pair.
As a consequence, plot does
Thank you for the reminder, Jeff. I am new to R-help and so please
bear with my ignorance. This is not homework and here is a
reproducible example. The number of observations per cluster doesn't
follow the condition specified above though, I just used this to
convey my idea.
> y <- rnorm(20)
>
Indeed it was the issue with data.table. I converted it to data.frame
and it worked like a charm.
Thank you so much for your insight!
This is the code that worked:
library(parallel)
library(data.table)
library(doSNOW)
n <- parallel::detectCores()
cl <- parallel::makeCluster(n, type = "SOCK")
do
HI Jim,
this is what I as running:
library(parallel)
library(data.table)
library(foreach)
library(doSNOW)
n <- parallel::detectCores()
cl <- parallel::makeCluster(n, type = "SOCK")
doSNOW::registerDoSNOW(cl)
files <- list.files("/WEIGHTS1/Retina", pattern=".RDat", ignore.case=T)
lst_out <- for
Thanks a lot!
exp <- expression(atop("Cumulative Na-Cl balance and",paste("(red)
",Delta,HCO[3]^"-"," (mmol)")))
did the trick
All best
Troels
-Oprindelig meddelelse-
Fra: R-help På vegne af Jeff Newmiller
Sendt: 16. december 2020 14:17
Til: r-help@r-project.org; tr...@gvdnet.dk; r
This is R-help, not R-do-my-work-for-me. It is also not a homework help line.
The Posting Guide is required reading. Assuming this is not homework, since
each step in your problem definition can be mapped to a fairly basic operation
in R (the sample function and indexing being key tools), you sh
Perhaps [1] has some useful ideas?
[1]
https://stackoverflow.com/questions/13223846/ggplot2-two-line-label-with-expression
On December 16, 2020 5:02:59 AM PST, tr...@gvdnet.dk wrote:
>Dear friends - I need an ylab on 2 lines -
>
>Here is what I want:
>
>exp <- expression(paste("Cumulative Na-Cl
Dear friends - I need an ylab on 2 lines -
Here is what I want:
exp <- expression(paste("Cumulative Na-Cl balance ","\n",
"and (red) ",Delta,HCO[3]^"-"," mmol"))
So if exp was OK ylab(exp) would work - but the "\n" doesn't seem to do
anything and it all comes on one lin
Hi,
Keep your emails on the list, please.
here are some artificial data
dput(dat)
structure(list(x = c("a", "a", "a", "b", "b", "b"), y = c(1,
1, 1, 3, 3, 3), cond = c("x1", "x2", "x3", "y1", "y2", "y3")), row.names =
c(NA,
6L), class = "data.frame")
And possible result
hist <- ggplot(dat, aes(
Dear R experts,
I want to simulate some unbalanced clustered data. The number of clusters
is 20 and the average number of observations is 30. However, I would like
to create an unbalanced clustered data per cluster where there are 10% more
observations than specified (i.e., 33 rather than 30). I t
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