Hello,
I forgot to suggest package gmp. See the second example in
?gmp::bigz
Hope this helps,
Rui Barradas
Às 05:50 de 14/11/20, Rui Barradas escreveu:
Hello,
You can compute the exact result with package Rmpfr.
See ?mpfr and [1].
library(Rmpfr)
two <- mpfr(2, precBits = 64)
two^64 - 1
#
Hello,
You can compute the exact result with package Rmpfr.
See ?mpfr and [1].
library(Rmpfr)
two <- mpfr(2, precBits = 64)
two^64 - 1
#1 'mpfr' number of precision 64 bits
#[1] 18446744073709551615
[1] https://www.mpfr.org/
Hope this helps,
Rui Barradas
Às 01:44 de 14/11/20, Yousri F
It was explained in the video... his counts were so small that they spanned the
1-9 and 10-99 ranges.
On November 13, 2020 6:59:49 PM PST, Rolf Turner
wrote:
>
>On Thu, 12 Nov 2020 01:23:06 +0100
>Martin Møller Skarbiniks Pedersen wrote:
>
>> Please watch this video if you wrongly believe that
On Thu, 12 Nov 2020 01:23:06 +0100
Martin Møller Skarbiniks Pedersen wrote:
> Please watch this video if you wrongly believe that Benford's law
> easily can be applied to elections results.
>
> https://youtu.be/etx0k1nLn78
Just watched this video and found it to be delightfully enlightening
a
You need the Rmpfr package. Your calculation of 2^64 is an ordinary
double precision number with 53 bits of precision.
> library(Rmpfr)
Loading required package: gmp
Attaching package: ‘gmp’
The following objects are masked from ‘package:base’:
%*%, apply, crossprod, matrix, tcrossprod
C
The largest consecutive integer that can be represented in double
precision is 2^53.
You'll have to move past double precision.
---JRG
On 2020-11-13 20:44, Yousri Fanous wrote:
> I want to calculate 2^64-1 which is
> 18446744073709551615
>
> I set the following options to prevent scientific n
I want to calculate 2^64-1 which is
18446744073709551615
I set the following options to prevent scientific notation
options("scipen"=100, "digits"=4)
> x<-2^64 -1
> x
[1] 18446744073709551616
This is not correct. There seem to be still some approximation happening.
How can I get the correct resul
fit <- robustgam::robustgam(...) produces a list, with no class attached,
so residuals(fit) invokes the default method for residuals(), which
essentially returns the 'residuals' component of 'fit'. There is no such
component so it returns NULL, an object of length zero. The mean of a
length-zero
Dear R-experts,
Here below my reproducible example. No error message but I can not get a
result. I get "NaN" as a result. I don't understand what is going on. Many
thanks for your precious help, as usual.
# # # # # # # # # # # # # # # # # # # # # # # # #
x<-c(499,491,500,517,438,495,501,525,5
Hello,
The best option is package zoo, function(s) rollapply.
p <- zoo::rollapply(nordn, width = 15, FUN = max, fill = c(NA, 0, NA))
These are meant as checks, see the differences between the one-liner
above and your result.
dim(position)
length(p)
w <- which(position[, 1] == p)
position[
Dear r list,
I try to locate any local max value and location of data that follow 7
moving window condition, meaning that this data is largest and
centered in 7 values to the left and 7 values to the right. I can
solve it by using for and if function, like below:
dput(nordn)
c(`1` = 36.3167318892
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