dmixgampar <- function (x, param1, param2, ...)
{
#compute density at x
}
On Wed, Oct 21, 2020 at 8:03 PM Charles Thuo wrote:
>
> Dear Sirs,
>
> The below listed code fits a gamma and a pareto distribution to a data set
> danishuni. However the distributions are not appropriate
Makes sense, thank you!
On Wed, 21 Oct 2020 at 17:46, Rolf Turner wrote:
>
> On Wed, 21 Oct 2020 16:15:22 -0500
> Ana Marija wrote:
>
> > Hello,
> >
> > I have a data frame with one column:
> >
> > > remove
> >
> > V1
> >
> > 1 ABAFT_g_4RWG569_BI_SNP_A10_35096
>
On Wed, 21 Oct 2020 16:15:22 -0500
Ana Marija wrote:
> Hello,
>
> I have a data frame with one column:
>
> > remove
>
> V1
>
> 1 ABAFT_g_4RWG569_BI_SNP_A10_35096
> 2 ABAFT_g_4RWG569_BI_SNP_B12_35130
> 3 ABAFT_g_4RWG569_BI_SNP_E09_35088
> 4 ABAFT_g_4RWG569_BI_
Thank you so much!
On Wed, Oct 21, 2020 at 4:47 PM Rui Barradas wrote:
>
> Hello,
>
> To remove the file extension it's much easier to use base R
>
>
> filename <- tools::file_path_sans_ext(basename(celFiles))
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 22:41 de 21/10/20, Rui Barradas escreveu
Hello,
To remove the file extension it's much easier to use base R
filename <- tools::file_path_sans_ext(basename(celFiles))
Hope this helps,
Rui Barradas
Às 22:41 de 21/10/20, Rui Barradas escreveu:
Hello,
This is probably because basename keeps the file extension, try instead
filename
Hello,
This is probably because basename keeps the file extension, try instead
filename <- sub("(^[^\\.]*)\\..+$", "\\1", basename(celFiles))
celFiles[!filename %in% as.character(remove$V1)]
Hope this helps,
Rui Barradas
Às 22:15 de 21/10/20, Ana Marija escreveu:
Hello,
I have a data fram
Hello,
I have a data frame with one column:
> remove
V1
1 ABAFT_g_4RWG569_BI_SNP_A10_35096
2 ABAFT_g_4RWG569_BI_SNP_B12_35130
3 ABAFT_g_4RWG569_BI_SNP_E09_35088
4 ABAFT_g_4RWG569_BI_SNP_E12_35136
5 ABAFT_g_4RWG569_BI_SNP_F11_35122
6 ABAFT_g_4RWG569_BI_SNP_F12_351
Hello,
You can subset the data argument.
And if you are plotting one year only, there's no point in color = year.
ggplot(subset(mpg, year == 1999), aes(displ, hwy)) +
geom_point()
If you are loading package dplyr, you can filter directly to ggplot:
library(dplyr)
mpg %>%
filter(year ==
Hi,
what about this one?
ggplot(data=mpg[mpg$year==1999,], aes(x=displ, y=hwy))+ geom_point()
Best, Robin
On 10/21/20 3:37 PM, Engin Yılmaz wrote:
> Dear
>
> I use dataset , as called "mpg"
>
> This is code
>
> ggplot(data=mpg)+ geom_point(mapping = aes(x=displ, y=hwy, colour=year))
>
> Bu
Dear
I use dataset , as called "mpg"
This is code
ggplot(data=mpg)+ geom_point(mapping = aes(x=displ, y=hwy, colour=year))
But I would like to see only "year of 1999" in this relationship between x
and y variables
How could I change the code in this direction?
I found the following code
libr
Dear Sirs,
The below listed code fits a gamma and a pareto distribution to a data set
danishuni. However the distributions are not appropriate to fit both tails
of the data set hence a mixed distribution is required which has ben
defined as "mixgampar"
as shown below.
library(fitdistrplus)
x<-
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