Re: [R] Adjusting The size and Orientation of x-axis labes for Pareto Charts

2020-09-11 Thread PIKAL Petr
Hi. You could try call pareto.chart with las=2 option. See ?par. But I am not sure if it will work as I do not have experience with this. Cheers Petr > -Original Message- > From: R-help On Behalf Of Paul Bernal > Sent: Friday, September 11, 2020 4:38 PM > To: R > Subject: [R] Adjusti

[R] Adjusting The size and Orientation of x-axis labes for Pareto Charts

2020-09-11 Thread Paul Bernal
Dear friends, Hope you are doing well. I am currently using R version 3.6.2. I installed and loaded package qcc by Mr. Luca Scrucca. I generated the pareto chart using qcc´s pareto.chart function, but when the graph gets generated, the x-axis labels aren´t fully shown, and so the text can´t be vi

Re: [R] Some code to run Hutcheson t-test using R

2020-09-11 Thread Luigi Marongiu
Thank you for the clarification. On Fri, Sep 11, 2020 at 2:36 PM Karl Schilling wrote: > > Dear Luigi: > > no, µ1µ2 is not "missing" > > First, it should actually be "µ1 - µ2". > > And as your usual null-hypothesis when comparing h1 and h2 is that they > are not different (i.e. µ1 = µ2), the latt

Re: [R] Some code to run Hutcheson t-test using R

2020-09-11 Thread Karl Schilling
Dear Luigi: no, µ1µ2 is not "missing" First, it should actually be "µ1 - µ2". And as your usual null-hypothesis when comparing h1 and h2 is that they are not different (i.e. µ1 = µ2), the latter term adds up to 0 and may be omitted. Karl Schilling __

Re: [R] Some code to run Hutcheson t-test using R

2020-09-11 Thread Luigi Marongiu
Actually, in the working example, Hutcheson himself did not report the term µ1µ2: `t0 = h1-h2/(var1-var2)^1/2`. so I think we can live without it. Case closed. Thank you On Fri, Sep 11, 2020 at 11:11 AM Luigi Marongiu wrote: > > Hello, > I have just realized in the original paper, the t test is d

Re: [R] Some code to run Hutcheson t-test using R

2020-09-11 Thread Luigi Marongiu
Hello, I have just realized in the original paper, the t test is defined as: `t = h1-h2 -(µ1µ2)/(var1-var2)^1/2`. is the term -(µ1µ2) missing in your formula? How to calculate µ1µ2? Thank you On Thu, Sep 10, 2020 at 2:41 PM Luigi Marongiu wrote: > > Update: > I also added the confidence interval