To be honest, I've only used the hex values as that was the format in which the
patterns were passed to me.
However from your explanation, I now understand what's going on. I didn't
appreciate that the characters were passed to another layer and not seeing the
hex code as the raw backslash.
In my opinion, using hexadecimal ASCII is much more obscure than simply using
the escape character properly... that is, you are doing no-one any favors by
using them. But to attain clarity here, you need to envision what the various
software layers are doing.
In your case, SQLServer may not uti
The feed is coming from a SQL table and this is using the embedded support for
R which comes with SQL 2016. The source is therefore a SELECT statement.
As an aside, I found a workaround by changing the pattern from:
"[\x22\x27\x2c\x3f\x5c\x60]"
to:
"[\x22\x27\x2c\x3f\x5c\x5c\x60]"
This s
1. I am far from an expert on such matters
2. It is unclear to me what your input is -- I assume a file.
The problem, as you indicate, is that R's parser sees "\B" as an incorrect
escape character, so, for example:
> cat("\B")
Error: '\B' is an unrecognized escape in character string starting ""\B
If you don't worry too much about an additive constant, then half the negative
squared deviance residuals should do. (Not quite sure how weights factor in.
Looks like they are accounted for.)
-pd
> On 25 Aug 2020, at 17:33 , John Smith wrote:
>
> Dear R-help,
>
> The function logLik can be u
If you look at
stats:::logLik.glm #3 ":" because it's unexported, as is true of most
methods
it should be obvious.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County"
In SQL, I'm using R as a way to filter data based on:
- 20 characters in the range to
- excluding , , , , ,
Given a SQL column containing the data:
code
A\BCDEFG
and the T-SQL script:
EXEC [sys].[sp_execute_external_script]
@language=N'R',
Dear R-help,
The function logLik can be used to obtain the maximum log-likelihood value
from a glm object. This is an aggregated value, a summation of individual
log-likelihood values. How do I obtain individual values? In the following
example, I would expect 9 numbers since the response has leng
As Bert advised correctly, this is not an R programming question. There is
some misunderstanding on how training//test data work together
in predictions. Suppose your test data has only one class. Therefore, you can
get the following rate by betting on the majority class every time, again
using dat
Thank you for your comment! This tree function is from the tree package.
Although it might be a pure statistical question, it could be related to
how the tree function is used. I will explore the site that you suggested.
But if there is anyone who can figure it out off the top of their head, I'd
ve
On Tue, 25 Aug 2020 14:26:43 +0200
Mike wrote:
> But which.min only does so if the values don't contain fractions.
> And I get
>
> > identical (data3ba, c(2.9,2.9))
> [1] FALSE
>
> Why is which.min not always returning 1 but which.max does?
It's the unfortunate consequence of the way floatin
Hi,
According to ?which.min it returns the "index of the (first)
minimum". So I would expect it to also return the first minimum when
providing two identical extrema. But my minimal reproducible doesn't
do so:
data1a <- c(3.2,4.2)
data1b <- c(3.1,4.1)
data2a <- c(0.2,1.2)
data2b <- c(4.2,5.2)
d
Hello,
If you want a predetermined number of colors, discretise the data and
use scale_color_manual. In the code below I first compute another vector
z, with a different range, 0 to 2. (In my first mail it was 0 to 1.)
g <- function(x, a = 0, b = 1){
(b - a)*(x - min(x))/(max(x) - min(x)) +
Hi
Maybe scale_colour_manual?
Cheers
Petr
> -Original Message-
> From: R-help On Behalf Of April Ettington
> Sent: Tuesday, August 25, 2020 11:39 AM
> To: Rui Barradas
> Cc: r-help@r-project.org
> Subject: Re: [R] ggplot 3-color gradient scales
>
> Is there a way to set it to 3 color c
Is there a way to set it to 3 color categories instead of a gradient? Like
if the color is based on the numbers in a dataframe column, can I make it
so anything >1.2 is red, <0.8 is blue, and anything in the middle is green?
On Mon, Aug 24, 2020 at 6:28 PM April Ettington
wrote:
> Thank you so
Hi,
It seems like the package "mvpart" is quite outdated and not available for
the current R release. Since PCA is a very common need I'll suggest finding
a replacement for it so that the error will either go away, or it is easier
for us to reproduce it.
Best,
Jiefei
On Tue, Aug 25, 2020 at 1:06
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