Hello,
Or in one go with *apply, function '[[':
sapply(result, '[[', 'p.value')
# EPAP
#2.564503e-04 4.173480e-06
Hope this helps,
Rui Barradas
Às 23:20 de 12/06/20, Sarah Goslee escreveu:
Where you have
result[1]$p.value
result[2]$p.value
You need
result[[1]]$p.value
Great idea!
Here it is:
> b[is.na(b$FLASER) | is.na(b$PLASER),]
FID IID FLASER PLASER pheno
1: fam1837 G1837 1 NA 2
2: fam2410 G2410 NA NA 2
3: fam2838 G2838 NA 2 2
4: fam3367 G3367 1 NA 2
5: fam3410 G3410 1 NA 2
6: fam
Since you have only a few troublesome NA values, if you look at them,
or even better, post them:
b[is.na(b$FLASER) | is.na(b$PLASER),]
perhaps we can work out the appropriate logic to get rid of only the
ones you don't want.
Jim
On Sat, Jun 13, 2020 at 12:50 PM Ana Marija wrote:
>
> Hi Rasmus,
Hi Rasmus,
thank you for getting back to be, the command your provided seems to
add all 11 NAs to 2s
> b$pheno <-
+ ifelse(b$PLASER==2 |
+ b$FLASER==2 |
+ is.na(b$PLASER) |
+ is.na(b$PLASER) & b$FLASER %in% 1:2 |
+ is.na
On 2020-06-13 11:30 +1000, Jim Lemon wrote:
> On Fri, Jun 12, 2020 at 8:06 PM Jim Lemon wrote:
> > On Sat, Jun 13, 2020 at 10:46 AM Ana Marija wrote:
> > >
> > > I am trying to make a new column
> > > "pheno" so that I reduce the number
> > > of NAs
> >
> > it looks like those two NA values in
>
Obviously my guess was wrong. I thought you wanted to impute the value
of "pheno" from FLASER if PLASER was missing. From just your summary
table, it's hard to guess the distribution of NA values. My guess that
the two undesirable NAs were cases where PLASER was missing and FLASER
was 2. My tactic
Hi Jim,
I tried it:
> b$pheno<-ifelse(b$PLASER==2 | b$FLASER==2 |is.na(b$PLASER) & b$FLASER ==
> 2,2,1)
> table(b$pheno,exclude = NULL)
12
859 828 11
> b$pheno<-ifelse(b$PLASER==2 | b$FLASER==2 |is.na(b$FLASER) & b$PLASER ==
> 2,2,1)
> table(b$pheno,exclude = NULL)
12
859
Hi Ana,
>From your desired result, it looks like those two NA values in PLASER
are the ones you want to drop.
If so, try this:
b$pheno<-ifelse(b$PLASER==2 | b$FLASER==2 |
is.na(b$PLASER) & b$FLASER == 2,2,1)
and if I have it the wrong way round, swap FLASER and PLASER in the
bit I have added.
J
Hello
I have a data frame like this:
> head(b)
FID IID FLASER PLASER
1: fam1000 G1000 1 1
2: fam1001 G1001 1 1
3: fam1003 G1003 1 2
4: fam1005 G1005 1 1
5: fam1009 G1009 1 1
6: fam1052 G1052 1 1
...
> table(b$PLASER,b$FLASER, e
On 2020-06-13 01:54 +0200, Rasmus Liland wrote:
> Dear Alejandro,
Sorry, I programmed and wrote that email at
the same time, changed the “toma_de_muestras”
perhaps other things, then continued
programming, thus this might make more
sense ...
Firstly, it would be easier to help you if
you pro
On 2020-06-10 13:14 -0700, Bert Gunter wrote:
> On Wed, Jun 10, 2020 at 11:48 AM Alejandro Ureta wrote:
> >
> > hi, I am trying to fuse (cbind, merge...
> > NOT rbind) several dataframes with
> > different numbers of rows, all df
> > included in a list, and using the code
> > extract shown bel
Where you have
result[1]$p.value
result[2]$p.value
You need
result[[1]]$p.value
result[[2]]$p.value
to get the first component of the list.
Sarah
On Fri, Jun 12, 2020 at 5:35 PM Sorkin, John wrote:
>
> Colleagues,
> I am trying to retrieve the p values produced by a Student's t-test run usin
Define a wrapper function for the t test that only returns the p-value?
by(mydata$WtBaseline,mydata$Group, function(...) t.test(...)$p.value)
S Ellison
From: R-help [r-help-boun...@r-project.org] on behalf of Sorkin, John
[jsor...@som.umaryland.edu]
Sent:
Colleagues,
I am trying to retrieve the p values produced by a Student's t-test run using a
by function, but can not do so. I can easily get the p value when I run s
Student's t-test without a by function. What is the secret to obtaining results
returned from a function run within a by function.
Questions on mixed models methodology, which this is, should be posted on
the r-sig-mixed-models list, not here.
That's where both the interest and expertise are.
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley
I have added a couple of what I would like to think are worthwhile features
to my addScales package. More important, also a short vignette. While this
is part of the lattice graphics ecosystem, have a look at the vignette as
it may have ideas that can be adapted/improved on in other graphics
paradi
Hi Jim,
So many thanks for your reply. I actually made a mistake in presenting the
problem; I should have clarified that the 1-10 linear scale questions went
as: 10 most humorous/closest to Egyptian culture and 1 the least. Also, I
should have attached some examples so the participant issue could
Thanks for your quick response. It works as I wanted.
From: Rui Barradas
Sent: Friday, June 12, 2020 7:08 AM
To: Naresh Gurbuxani ; r-help@r-project.org
Subject: Re: [R] function to return plots
Hello,
plot.list is a list, try '[[' to access its members.
('[' returns sub-lists.)
plot(
Hello,
plot.list is a list, try '[[' to access its members.
('[' returns sub-lists.)
plot(plot.list[[1]], position = c(0, 0, 1, 0.5), more = TRUE) #Works
plot(plot.list[[2]], position = c(0, 0.5, 1, 1), more = FALSE) #Works
Hope this helps,
Rui Barradas
Às 10:52 de 12/06/20, Naresh Gurbuxan
Hi Naresh,
The somewhat obscure syntax of lattice.
print(plot.list[[1]])
print(plot.list[[2]])
Jim
On Fri, Jun 12, 2020 at 7:53 PM Naresh Gurbuxani
wrote:
>
>
> I want to write a function that will return lattice plots. This simple
> function output a list of two plots. These plots can be
> i
I want to write a function that will return lattice plots. This simple
function output a list of two plots. These plots can be
individually shown on the console. But I am unable to put them on two
panels of a single plot.
What changes do I need to make to this function?
Thanks,
Naresh
libra
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