> It is correctly signalling that it hasn't converged (look at
> optim.sol$convergence, which "indicates that the iteration limit maxit
> had been reached".) But CG should be taking bigger steps. On a 1D
> quadratic objective function with no errors in the derivatives, it
> should take one step t
Thanks a lot Jin..
If my total number of observations are 500,
n will be 500,
mu will be average (500)
s will be sd (500)
and m will be RMSE value i.e. 4500 in this case?
tovecv(n=500, mu=average (500), s=sd, m=4500, measure="rmse")
On Fri, Mar 13, 2020 at 12:46 AM Jin Li wrote:
> Hi,
> Why d
Hello,
Why would it be awkward to show values like 4600? If those are the
values, show them. When there is a large difference, orders of
magnitude, you can plot logs by setting parameter log = "y" as in
boxplot(10^(0:5), log = "y")
But I don't see why to have values in the range 2900-4600 (s
Once again, CG and its successors aren't envisaged for 1D problems. Do you
really want to perform brain surgery with a chain saw?
Note that
production4 <- function(L) { - production3(L) }
sjn2 <- optimize(production3, c(900, 1100))
sjn2
gives
$minimum
[1] 900.0001
$objective
[1] 84.44156
Whe
On 12/03/2020 8:52 p.m., Abby Spurdle wrote:
L= 1006.536
L= 1006.537
L= 1006.535
It appears to have chosen step size 0.001, not 0.1. It should be
getting adequate accuracy in both 1st and 2nd derivatives.
Those little ripples you see in the plot are not relevant.
I'm impressed.
But you're
Dear Martin,
Great news, thanks!
If you wish, please also consider my initial note about help(hist),
this is definitely worrying new R users.
With best wishes,
Alexey
пт, 13 мар. 2020 г. в 02:16, Martin Maechler :
>
> > Alexey Shipunov
> > on Tue, 18 Feb 2020 14:34:48 +0900 writes:
I am trying to get information about the output produced by the bounds
function. Code that runs the package along with sample output is below.
Questions (1) Do the values given under boundaries, lower and upper
(Boundaries:
TimeLower UpperExit pr. Diff. pr.
1 0.10 -6.9913 6.9913
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