Re: [R] transforming dates

Well, one way to do it is via regex's -- no splitting and recombining needed. Note: This will convert a factor into a character vector. > z <- c("11/7/2016", "14-07-16") > z <- gsub("-([[:digit:]]{2})-([[:digit:]]{2})", "/\\1/20\\2",z) ## /\ is / and \ > z [1] "11/7/2016" "14/07/2016" I leave it

[R] Recall: transforming dates

reichm...@sbcglobal.net would like to recall the message, "transforming dates". __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/pos

[R] transforming dates

R-Help Forum I have a data set that contains a date field but the dates are in two formats 11/7/2016dd/mm/ 14-07-16 dd-mm-yy How would I go about correcting this problem. Should I separate the dates, format them , and then recombine? Sincerely Jeff