Hi Phillip,
The following seems to do what you want:
phdf<-read.table(text="v1 v2 v3 v4 v5 code
0 0 0 0 01
1 4 0 0 01
1 1 0 0 01
1 0 1 0 01
2 0 1 0 01
0 1 0 0 01
0 1 2 0 01
0 1 2 3 01
0 2 3 4 41
0 0 0 2 31",
With the snippet of data below I’m trying to do an if/then type of thing:
row 1 – if all five variables equal 0 then code equals 1;
row 3 – if v1 = 1 and v2 = 1 then code = 5;
row 7 – if v1 = 0 and v2 = 1 and v3 = 2 then code = 10
There are 24 codes in the complete database.
v1 v2
Hello R users,
I am excited to introduce a new package for R which is now available on CRAN
called �backbone�.
The package can be found here:
https://cran.r-project.org/web/packages/backbone/index.html
The backbone package provides methods for extracting from a weighted graph a
binary or signe
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