I believe this is unnecessarily complicated. What the OP did not seem to
get is that he had to specify the col's and pch's in the panel function
that were actually used via appropriate subscripting. He just passed in the
whole col and pch vector by default -- subscripting is not done unless
specifi
conditions look better as factors (their values are displayed in the
strip label).
groups should be a factor to get the uniqueness over panels.
To use two factors together for groups, take their interaction.
col and pch should be integers
xyplot(mpg ~ wt | factor(cyl), data=mtcars,
groups
Glad to be of help.
Peter
On Tue, Apr 9, 2019 at 10:03 PM Matthew Snyder wrote:
> You are not late to the party. And you solved it!
>
> Thank you very much. You just made my PhD a little closer to reality!
>
> Matt
>
>
>
> *Matthew R. Snyder*
> *~*
> PhD Candidate
> University F
You are not late to the party. And you solved it!
Thank you very much. You just made my PhD a little closer to reality!
Matt
*Matthew R. Snyder*
*~*
PhD Candidate
University Fellow
University of Toledo
Computational biologist, ecologist, and bioinformatician
Sponsored Guest Res
Sorry for being late to the party, but has anyone suggested a minor
but important modification of the code from stack exchange?
xyplot(mpg ~ wt | cyl,
panel = function(x, y, ..., groups, subscripts) {
pch <- mypch[factor(carb)[subscripts]]
col <- mycol[factor(
I tried this too:
xyplot(mpg ~ wt | cyl, data=mtcars,
# groups = carb,
subscripts = TRUE,
col = as.factor(mtcars$gear),
pch = as.factor(mtcars$carb)
)
Same problem...
*Matthew R. Snyder*
*~*
PhD Candidate
University Fellow
University of Toledo
Computa
I want to have one column in a dataframe define the color and another
define the pch.
This can be done easily with a single panel:
xyplot(mpg ~ wt,
data=mtcars,
col = mtcars$gear,
pch = mtcars$carb
)
This produces the expected result: two pch that are the same color are
uniq
1. I am quite sure that whatever it is that you want to do can be done.
Probably straightforwardly. The various R graphics systems are mature and
extensive.
2. But I, for one, do not understand from your post what it is that you
want to do. Nor does anyone else apparently.
Cheers,
Bert Gunter
Maybe you should use factors rather than character columns.
On April 9, 2019 8:09:43 PM PDT, Matthew Snyder wrote:
>Thanks, Jim.
>
>I appreciate your contributed answer, but neither of those make the
>desired
>plot either. I'm actually kind of shocked this isn't an easier more
>straightforward th
Thanks, Jim.
I appreciate your contributed answer, but neither of those make the desired
plot either. I'm actually kind of shocked this isn't an easier more
straightforward thing. It seems like this would be something that a user
would want to do frequently. I can actually do this for single plots
Hi Matthew,
How about this?
library(lattice)
xyplot(mpg ~ wt | cyl,
data=mtcars,
col = mtcars$gear,
pch = mtcars$carb
)
library(plotrix)
grange<-range(mtcars$gear)
xyplot(mpg ~ wt | cyl,
data=mtcars,
col = color.scale(mtcars$gear,extremes=c("blue","red"),xrange=g
On 09/04/2019 5:46 p.m., Sebastien Bihorel wrote:
Hi,
Is there a way to do a dry run of install.packages() or update.packages() to
simulate how an R environment would be modified by the installation or update
of a particular set of packages (with their dependencies)?
I am particularly interes
Hi,
Is there a way to do a dry run of install.packages() or update.packages() to
simulate how an R environment would be modified by the installation or update
of a particular set of packages (with their dependencies)?
I am particularly interested in finding how dependencies would be recursivel
I am making a lattice plot and I would like to use the value in one column
to define the pch and another column to define color of points. Something
like:
xyplot(mpg ~ wt | cyl,
data=mtcars,
col = gear,
pch = carb
)
There are unique pch points in the second and third panels,
And just for fun, yet another way
> cumsum((1:200)*c(1,-1))
On Tue, Apr 9, 2019 at 9:51 PM David L Carlson wrote:
> Here's another approach:
>
> > x <- c(rbind(1:100, -(1:100)))
> > head(x); tail(x)
> [1] 1 -1 2 -2 3 -3
> [1] 98 -98 99 -99 100 -100
>
> ---
Here's another approach:
> x <- c(rbind(1:100, -(1:100)))
> head(x); tail(x)
[1] 1 -1 2 -2 3 -3
[1] 98 -98 99 -99 100 -100
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77843-4352
-Original Message-
Dear all
A new R package 'otpr' is now available on CRAN. It's a wrapper for the
OpenTripPlanner (OTP) API and is primarily aimed at researchers and transport
planners who want to use OTP to carry out accessibility studies or generate
variables for transport models. The package consists of four
As there are many possible sources of the warning, to "sort it out" try
something like
which( is.na() & (! is.na()))
B.
> On 2019-04-09, at 11:02, Richard M. Heiberger wrote:
>
> My guess is that numbers formatted with commas are causing an unwanted
> coercion.
> Remove the commas with
My guess is that numbers formatted with commas are causing an unwanted coercion.
Remove the commas with gsub before converting to numeric.
> as.numeric(NA)
[1] NA
> as.numeric("1,234,567")
[1] NA
Warning message:
NAs introduced by coercion
> as.numeric(gsub(",", "", "1,234,567"))
[1] 1234567
>
On
This looks like homework, and there is a no homework policy on this list.
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Apr 9, 2019 at 5:51 AM Coder 634
Hi Bienvenue,
I believe that your problem is that R can't translate "one" to a number,
because it is not a number. R could translate to numeric for example this
vector, where numbers are expressed as strings,
c("1","4","7")
but "one" is just letters put together, therefore R can't understand the
> On Apr 9, 2019, at 9:07 AM, bienvenidoz...@gmail.com wrote:
>
> how to create
> u = (1, −1, 2, −2, . . . , 100, −100) in r
>
> Thanks
> Bienvenue
Hi,
See ?seq and ?rep
> rep(seq(100), each = 2) * c(1, -1)
[1]1 -12 -23 -34 -45 -56 -67
[14] -7
how to create
u = (1, −1, 2, −2, . . . , 100, −100) in r
Thanks
Bienvenue
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PLEASE do read the
On 09/04/2019 7:30 a.m., Jim Lemon wrote:
Hi Bienvenue,
Perhaps you should ask whether you really want to "sort it out". The
warning is telling you that you are converting the NA values to NA in
the returned numeric vector.
I don't think that's what it is saying. I think it is saying that a
n
Hi, I'm new at R programming and I need help to solve this problem.
The objective is to predict the change of the value of the Close variable:
D(t) =Close(t) – Close(t-1) for a given day t, using the known data until
t-1 to generate the prediction model.
We can use univariate and multivariate mo
Hi Bienvenue,
Perhaps you should ask whether you really want to "sort it out". The
warning is telling you that you are converting the NA values to NA in
the returned numeric vector. I can't think of anything more sensible
to do with NA values. You may also have character strings that cannot
be conv
Hi,
I am applyin function as.numeric to a vector having many values as NA
and it is giving :
Warning message:
NAs introduced by coercion
Can anyone help me to know how to remove this warning and sor it out?
Thanks
Bienvenue
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On Mon, 8 Apr 2019 18:41:16 +0300
kostas zogopoulos wrote:
> How do you read a csv file that contains greek characters as part of
> the header (i.e. α, β etc) in R studio?
Determine the character encoding used in the file (is it UTF-8,
ISO8859-7 or something else?) and pass it as fileEncoding=".
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