Hi Marc,
Yes, you got it to the point! That is exactly what I want. But I do not know
how to do that. I know how to randomly pick the first day but I do not know how
to set a range of values which cover the 25 days starting from that random
value.
Best,
Dagmar
Hi,
I am confused.
As far as
I am using terms.formula function to substract the variables from a formula
environment.
Concretely, with the attr(*, "term.labels") I get the right side terms
specified in the formula.
However, when introducing the same variable two or more times, this appears
only once.
For example, when ty
Dear Jim,
I used a bit of my data in my attempt to follow the code.
I got the attached plot after some tweaks.
I would like to add horizontal color bar legend that could be used to
explain the number of lightning counts at different points on the
latitude band as plotted.
Thank you
Warm regards
"... if("factor" %in% class(x)) x <- as.character(x) ## since ifelse wont
work with factors "
Nonsense!
> x <- factor(c("a","", "b"))
> x
[1] a b
Levels: a b
> levels(x)
[1] "" "a" "b"
> x <- factor(ifelse(x==(""),NA,x))
> x
[1] 2 3
Levels: 2 3
Bert Gunter
"The trouble with having
Dear All,
## function to relpace empty cell by NA
empty_as_na <- function(x){
if("factor" %in% class(x)) x <- as.character(x) ## since ifelse wont work
with factors
ifelse(as.character(x)!="", x, NA)
}
## connect to spark local
sc <- spark_connect(master = "local")
# load an example of datafra
Hi Ogbos,
Here is a slight modification of a method I use to display trip
density on a map:
oolt<-read.table(text="Lat Lon
30.1426 104.7854
30.5622 105.0837
30.0966 104.6213
29.9795 104.8430
39.2802 147.7295
30.2469 104.6543
26.4428 157.7293
29.4782 104.5590
32.3839 105.3293
26.4746 157.8411
25.10
Yes, there are many ways to do this. Search rseek.org for "2d density
plots". Also check the CRAN "Spatial" task view. Also see the kde2d
function in the MASS package and especially the examples there that use the
image() function to plot densities.
Cheers,
Bert
Bert Gunter
"The trouble with hav
Hello,
cbind alone will return a matrix, cbind.data.frame is probably what the
OP wants.
class(cbind(x = 1:3, mat))
#[1] "matrix"
cbind.data.frame(x = 1:3, mat)
# x (1) (2) (3)
#1 1 1 4 7
#2 2 2 5 8
#3 3 3 6 9
Hope this helps,
Rui Barradas
Às 15:11 de 09/12/2018, Micha
Dear Contributors,
I have a data of the form:
Lat Lon
30.1426 104.7854
30.5622 105.0837
30.0966 104.6213
29.9795 104.8430
39.2802 147.7295
30.2469 104.6543
26.4428 157.7293
29.4782 104.5590
32.3839 105.3293
26.4746 157.8411
25.1014 159.6959
25.1242 159.6558
30.1607 104.9100
31.4900 -71.89
Read ?data.frame
In particular, notice the check.names argument.
On December 9, 2018 7:11:52 AM PST, Michael Dewey
wrote:
>Dear Jinsong
>
>Try cbind(x = 1:3, mat)
>and see if that helps
>
>Michael
>
>On 09/12/2018 15:05, Jinsong Zhao wrote:
>> Hi there,
>>
>> In the following mini-example, I
Your names are not syntactically valid.
Consider:
> mat <- matrix(1:9, nrow = 3)
> colnames(mat) <- letters[1:3]
> mat
a b c
[1,] 1 4 7
[2,] 2 5 8
[3,] 3 6 9
> data.frame(x=1:3,mat)
x a b c
1 1 1 4 7
2 2 2 5 8
3 3 3 6 9
See ?make.names, and the "Value" section of ?data.frame for how names
Dear Jinsong
Try cbind(x = 1:3, mat)
and see if that helps
Michael
On 09/12/2018 15:05, Jinsong Zhao wrote:
Hi there,
In the following mini-example, I hope to keep the column names of mat, but
failed.
# mini-example
mat <- matrix(1:9, nrow = 3)
colnames(mat) <- paste("(", 1:3, ")", sep = "
Hi there,
In the following mini-example, I hope to keep the column names of mat, but
failed.
# mini-example
> mat <- matrix(1:9, nrow = 3)
> colnames(mat) <- paste("(", 1:3, ")", sep = "")
> mat
(1) (2) (3)
[1,] 1 4 7
[2,] 2 5 8
[3,] 3 6 9
> data.frame(x = 1:3, mat)
x X.
Hello,
Às 00:28 de 09/12/2018, David Winsemius escreveu:
Most of those answers are in the R-FAQ. It ships with every distribution
copy from CRTAN and is also available online.
Estimating the number of R users would be difficult. There are probably
20,000+ subscriblers to Rhelp.
The OP ask
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