On Mon, 09 Jul 2018, Christofer Bogaso writes:
> Hi,
>
> Below is my code :
>
> library(zoo)
> Dat1 = structure(c(17890, 17770.01, 17600, 17593, 17630.01), index =
> structure(c(1512664740,
> 1512664800, 1512664860, 1512664920, 1512664980), class = c("POSIXct",
> "POSIXt"), tzone = "America/Los_An
Thanks for the answer.
Il gio 19 lug 2018, 01:04 Jim Lemon ha scritto:
> Hi Francesca,
> This looks like a fairly simple task. Try this:
>
> fpdf<-read.table(text="PASP SUBJC
> 0 0
> 4 1
> 0 0
> 8 0
> 4 0
> 0 1
> 0 1",
> he
it looks great, thank you very much Jeff for your time and kind help !
On Wed, Jul 18, 2018 at 7:51 PM, Jeff Newmiller
wrote:
> The traditional (SQL) way to attack this problem is to make the data
> structure simpler so that faster comparisons can be utilized:
>
>
> A <- data.fr
The traditional (SQL) way to attack this problem is to make the data
structure simpler so that faster comparisons can be utilized:
A <- data.frame(z=c("a*b", "c*d", "d*e", "e*f"), t =c(1, 2, 3, 4))
B <- data.frame(z=c("a*b::x*y", "c", "", "g*h"), t =c(1, 2, 3, 4))
library(dplyr
On Wed, 18 Jul 2018, Shawn Way wrote:
I have a dataframe that contains units using the units package.
Unfortunately, I really need the units for reporting. I'm assuming
that's because the data is in a class units and xtable doesn't know what
to do with this.
If you want a bug or feature in
On Wed, 18 Jul 2018, David Winsemius wrote:
It's not so much as factors but rather in a form that paste() will coerce
to character so you cna get the automatic format
David,
Now I understand.
Maybe you need to add a format string. It might force some of your pasted
date+time values to NA
> On Jul 18, 2018, at 4:07 PM, Rich Shepard wrote:
>
> On Wed, 18 Jul 2018, David Winsemius wrote:
>
>> I would not destroy the possibility of using the original values:
>
> David,
>
> What are the benefits of keeping date and time as factors?
>
>>> allyears$myDate <- as.Date(as.character(
Off topic for r-help (see posting guide linked below).
Suggest Posting on stats.stackexchange.com instead..
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic
Hi again,
Sorry, forgot this line:
fpdf$PASPpos<-fpdf$PASP > 0
just after reading in the data frame.
Jim
On Thu, Jul 19, 2018 at 9:04 AM, Jim Lemon wrote:
> Hi Francesca,
> This looks like a fairly simple task. Try this:
>
> fpdf<-read.table(text="PASP SUBJC
> 0 0
> 4 1
On Wed, 18 Jul 2018, David Winsemius wrote:
I would not destroy the possibility of using the original values:
David,
What are the benefits of keeping date and time as factors?
allyears$myDate <- as.Date(as.character(allyears$date))
allyears$myTime <- as.POSIXct(paste(allyears$date, allyea
Hi Francesca,
This looks like a fairly simple task. Try this:
fpdf<-read.table(text="PASP SUBJC
0 0
4 1
0 0
8 0
4 0
0 1
0 1",
header=TRUE)
# get the number of positive PASP results by group
ppos<-by(fpdf$SUBJC,fpdf$PASPpos,su
Dear Riley,
thank you very much for your help and solution. I got some inspiration from
stackoverflow website,
and I did use sqldf library. It looks that the formula below works too.
Thanks a lot !
sqldf("select B.*, A.* from B left join A on instr(B.z, A.z)")
On Wed, Jul 18, 2018 at 3:57 PM,
Thanks a lot ! It looks that I am getting the same results with :
B %>% regex_left_join(A, by = c(z = 'z'))
On Wed, Jul 18, 2018 at 3:57 PM, Riley Finn wrote:
> please may I ask for a piece of advise regarding merging two dataframes :
>> A <- data.frame(z=c("a*b", "c*d", "d*e", "e*f"), t =c(1,
I have a dataframe that contains units using the units package. Unfortunately,
I really need the units for reporting. I'm assuming that's because the data is
in a class units and xtable doesn't know what to do with this.
The following is a MWE:
library(xtable)
library(units)
data
> On Jul 18, 2018, at 2:50 PM, Rich Shepard wrote:
>
> A set of data files have this format:
>
> date,time,elev
> 1988-10-01,00:30,87.6849
> 1988-10-01,01:00,87.6849
> 1988-10-01,01:30,87.6849
> 1988-10-01,02:00,87.6879
> 1988-10-01,02:30,87.6879
> 1988-10-01,03:00,87.691
> 1988-10-01,03:30,8
Dear all,
please may I ask for a piece of advise regarding merging two dataframes :
A <- data.frame(z=c("a*b", "c*d", "d*e", "e*f"), t =c(1, 2, 3, 4))
B <- data.frame(z=c("a*b::x*y", "c", "", "g*h"), t =c(1, 2, 3, 4))
function of the criteria :
if "the elements in the 1st column of A could be
A set of data files have this format:
date,time,elev
1988-10-01,00:30,87.6849
1988-10-01,01:00,87.6849
1988-10-01,01:30,87.6849
1988-10-01,02:00,87.6879
1988-10-01,02:30,87.6879
1988-10-01,03:00,87.691
1988-10-01,03:30,87.694
Importing it with this command:
allyears <- read.table('allyears.da
Hi there,
I am an MS student from Bangladesh. I am doing thesis in my MS degree. In
my research, I am generating data from weibull distribution and my model is
accelerated failure time (AFT) model. I am considering right censoring as
well as covariates. Now I have been facing difficulties to genera
> On Jul 18, 2018, at 1:55 PM, Rich Shepard wrote:
>
> I have daily precipitation data for 58 locations from 2005-01-01 through
> 2018-06-18. Among other plots and analyses I want to apply lattice's
> xyplot() to illustrate the abundance and patterns of the data.
>
> I've used a vector of co
I have daily precipitation data for 58 locations from 2005-01-01 through
2018-06-18. Among other plots and analyses I want to apply lattice's
xyplot() to illustrate the abundance and patterns of the data.
I've used a vector of colors (and a key) when there were only eight
weather stations and
On Wed, 18 Jul 2018, Francesca wrote:
Dear R help,
I am new to ggplot so I apologize if my question is a bit obvious.
Or perhaps not, as this is the "R-help" mailing list, not the
"Ggplot-help" mailing list. Fortunately for you, what you really need to
learn is R, and then ggplot will be
Hello,
Your request is not entirely clear.
What kind of a graph do you want? A bar graph with a bar of the fraction
of positive levels of PASP per each level of SUBJC?
You need to be more specific.
Also, please post data like this:
# post the output of this command in your next mail
dput(hea
Dear R help,
I am new to ggplot so I apologize if my question is a bit obvious.
I would like to create a plot where a compare the fraction of the values of a
variable called PASP out of the number of subjects, for two groups of subject
codified with a dummy variable called SUBJC.
The variable
Hi,
I worked through this excellent tutorial:
#Elegant regression results tables and plots in R: the finalfit package
https://www.r-bloggers.com/elegant-regression-results-tables-and-plots-in-r-the-finalfit-package/
Now I am applying it to my own data.
In the tutorial there is mention of:
# Ta
My thanks to all contributors, and while I was not in the right place, I
certainly got the answers I needed. My students will benefit, so thank you all.
Regards,
Michael Thompson M.Prof.Studies Data Science
09 975 4678
Senior Lecturer, Digital Technologies
Manukau Campus
We all, like sheep, have
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