On 04/07/2018 6:21 PM, Nelly Reduan wrote:
Dear all,
I would like to generate N random numbers with a given probability and
condition but I'm not sure how to do this.
For example, I have N = 20 and the vector from which to choose is seq(0, 10,
1). I have tested:
x <- sample(seq(0, 10, 1), 20,
Hi Nell,
As I said, the number of permutations increases rapidly with the
number of values to be permuted. Using the package "permute", which is
much more sophisticated than the basic function in the crank package,
a vector of length 20 has 2.432902e+18 possible permutations. While
your problem can
Many thanks Jim for your help. I am trying to apply the permutations with a
sequence of 20 but I obtain the error message:
Error in matrix(NA, nrow = nrows, ncol = lenx) :
invalid 'nrow' value (too large or NA)
In addition: Warning message:
In matrix(NA, nrow = nrows, ncol = lenx) :
NAs intr
Maybe I missed it, but I didn't see anyone suggest a visit to the CRAN Spatial
task view. This would be a good place to start learning how to work with
spatial data in R.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
Lab cell
Wasn't there also the requirement that the numbers be drawn from a uniform
distribution? These sequences are not. I wonder whether this can for all
practical purposes be simplified to consider only the sequence with maximum
entropy.
B.
> On 2018-07-11, at 06:23, Rolf Turner wrote:
>
> On
On 11/07/18 12:46, Jim Lemon wrote:
Hi Nell,
I may not have the right idea about this, but I think you need to do
this in two steps if it can be done. Let's say you want a sequence of
20 (N) numbers between 0 and 10 that sums to 10 (M). You can enumerate
the monotonically increasing sequences lik
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