Thanks. The trick was in the do.call() syntax -
p1<-do.call(gtable_combine, c(L1, list(along=2)))
On Jun 14, 2018, 6:30 PM, at 6:30 PM, Jeff Newmiller
wrote:
>I don't know gtable_combine well enough to answer based on hand waving.
>A reproducible example is more likely to tempt someone to dig
I don't know gtable_combine well enough to answer based on hand waving. A
reproducible example is more likely to tempt someone to dig a little.
On June 14, 2018 8:07:19 AM HST, Stats Student
wrote:
>Thanks for the replies. Wasn't aware that Gmail on Android sent HTML by
>default, apologies.
>
>
Marc
Thank you - that will save me some time.
Jeff
-Original Message-
From: Marc Schwartz
Sent: Thursday, June 14, 2018 4:07 PM
To: JEFFERY REICHMAN
Cc: R-help
Subject: Re: [R] Kendall tau a, b, or c
> On Jun 14, 2018, at 4:04 PM, JEFFERY REICHMAN
wrote:
>
> r-help Forum
>
> Is
> On Jun 14, 2018, at 4:04 PM, JEFFERY REICHMAN wrote:
>
> r-help Forum
>
> Is there a function to calculate either Kendall tau a, b, or c. It appears
> the Kendall library only calculates tau b. Just wanted to check before
> writing a function to calculate the concordant and discordant pa
r-help Forum
Is there a function to calculate either Kendall tau a, b, or c. It appears the
Kendall library only calculates tau b. Just wanted to check before writing a
function to calculate the concordant and discordant pairs. Then its pretty easy.
jeff
_
Answering my own post. On the particular machine in question, I managed to
install rJava after installing
(in the OS) libbz2-dev and liblzma-dev. There was a hint of this in the install
output,
but not as clear as would help a novice.
JN
__
R-help@r-p
Thanks for the replies. Wasn't aware that Gmail on Android sent HTML by
default, apologies.
Storing the tableGrob-s in a list worked but for some reason grid.arrange
complains on output from gtable_combine() using lists vs individual
tableGrob-s.
# works when supplying individual tableGrobs
Jim,
Actually, I got this to work.
df$NonAcceptanceOther[df$NonAcceptanceOther==""]<- NA
df$NonAcceptanceOther
missingDF <- plot_missing(df)
# missingDF
# featurenum_missing pct_missinggroup
# 13 NonAcceptanceOther 26157 0.86859932257 Remove
G
I am trying to learn and use the tidyverse tools and one peculiarity
that I seem to encounter is that converting some data frames to tibbles
gives surprising results. I tried to make a toy example illustrates the
problem but couldn't. Let me show some output that illustrates the problem.
> str
Keep replies on list please.
You are not accessing a value from vector Q if you access the zero'th element!
R > Q <- c(3, 5, 8)
R > Q[0]
numeric(0)
R > Q[1]
[1] 3
R > Q[2]
[1] 5
In the first iteration of the loop j is 2 thus j-2 is 0 and that's the reason
for the error message: you are trying to
#Good morning Jim, thank you for your response and guidance.
So I ran the suggested and got: Error in nchar(df2$NonAcceptanceOther) :
'nchar()' requires a character vector
So I ran this:
df2$NonAcceptanceOther[] <- lapply(df2$NonAcceptanceOther,as.character)
#Then tried again.
#But still g
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