Hi
Here is one way to do it ...
col1 <- "red"
col2 <- "blue"
EU <- data.frame(EuStockMarkets)
with(EU, plot(DAX, CAC, col=col2, type="h", ylim=c(0,6000)))
par(new=TRUE)
with(EU, plot(DAX, FTSE, col=col1, type="h", ylim=c(0,6000)))
## Convert 'graphics' to 'grid'
library(gridGraphics)
grid.echo(
dear Sumi,
I am not familiar with the dplyr package (%>%..), however if you want to
fit the model for each subject times freq interaction, a simple for loop
will suffice.
Here possible code:
Assuming d is the dataframe, something like
subj<-levels(d$subject)
fr<-unique(d$freq)
#new dataframe
> On 4 Jun 2018, at 10:45 , Christofer Bogaso
> wrote:
>
> Hi,
>
> I have an automatic data feed and I obtained a Date vector in the following
> format:
>
>> Date
> [1] "03 Jun 2018 10:01 am CT""01 Jun 2018 22:04:25 pm CT"
>
> I now like to convert it to UTC time-zone
>
> Is there any
Good morning Don, thank you for your support. I will give this all more
investigation and submit my findings when finalized.
Cheers and thanks again for your help Sir.
WHP
From: MacQueen, Don [mailto:macque...@llnl.gov]
Sent: Friday, June 01, 2018 5:03 PM
To: Bill Poling ; r-help (r-help@r-pr
Hi,
I have an automatic data feed and I obtained a Date vector in the following
format:
> Date
[1] "03 Jun 2018 10:01 am CT""01 Jun 2018 22:04:25 pm CT"
I now like to convert it to UTC time-zone
Is there any easy way to convert them so, particularly since 1st element
doesnt have any Second
Glenn,
currently, this is currently not exposed in "colorspace" AFAICS. You can
modify it by changing .WhitePoint inside colorspace's NAMESPACE, though:
R> assignInNamespace(".WhitePoint", rbind(c(95, 100, 105)),
+ns = "colorspace")
R> as(XYZ(100, 100, 100), "LAB")
LA
In colorspace.R I see:
setAs("color", "LAB", function(from)
LAB(.Call("as_LAB", from@coords, class(from), .WhitePoint, PACKAGE = "
colorspace"),
names = dimnames(from@coords)[[1]]))
...
.WhitePoint = NULL
and then in colorspace.c and the function CheckWhite(),
I see
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