> On Sep 18, 2017, at 9:26 AM, Fix Ace via R-help wrote:
>
> Dear R Community,
> I tried to generate heatmap for a matrix of 1500 columns by 106 rows using
> the following R script:
>> pheatmap(tf.vs.DE.1.removeAllZeroCol, fontsize=3,border_color=NA)
> and got the graph (as attached Fig 1)
>
>
> On Sep 17, 2017, at 9:24 PM, Ajay Arvind Rao
> wrote:
>
> Hi,
>
> We are using open source license of R to analyze data at our organization.
> The system configuration are as follows:
>
> *System configuration:
>
> o Operating System - Windows 7 Enterprise SP1, 64 bit (Desktop)
Yes. My understanding is that you want the identifier to have the same
number of rows as the data frame. A slight variant of David's solution
would then be:
do.call(paste0,x)
-- Bert
On Mon, Sep 18, 2017 at 8:29 AM, David Winsemius
wrote:
>
> > On Sep 18, 2017, at 5:13 AM, Therneau, Terry M
> On Sep 18, 2017, at 5:13 AM, Therneau, Terry M., Ph.D.
> wrote:
>
> This question likely has a 1 line answer, I'm just not seeing it. (2, 3, or
> 10 lines is fine too.)
>
> For a vector I can do group <- match(x, unqiue(x)) to get a vector that
> labels each element of x.
> What is an eq
You could use merge() with an ID column pasted onto the table of names, as
in
> tbl <- data.frame(FirstName=c("Abe","Abe","Bob","Chuck","Chuck"),
Surname=c("Xavier","Yates","Yates","Yates","Zapf"), Id=paste0("P",101:105))
> tbl
FirstName Surname Id
1 Abe Xavier P101
2 Abe Yates
If this is a bioconductor package, why do you not post on the bioconductor
list?
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Sep 18, 2017 at
Hi!
2017-09-18 07:13 -0500, Therneau, Terry M., Ph.D. wrote:
> This question likely has a 1 line answer, I'm just not seeing
> it. (2, 3, or 10 lines is
> fine too.)
>
> For a vector I can do group <- match(x, unqiue(x)) to get a vector
> that labels each
> element of x.
Actually, you get a v
"Label" is not a clear term for data frames, but most data frames have
rownames. If dta is a data frame, not a tibble,
rownames( dta )[ !duplicated( dta ) ]
Or could use row indexes directly
which( !duplicated( dta ) )
--
Sent from my phone. Please excuse my brevity.
On September 18, 2017 6
Depending on how you created df maybe your code has the column names
wrong. In any case these 4 alternatives all work. Start a fresh R
session and then copy and paste this into it.
library(zoo)
u <- "https://faculty.washington.edu/ezivot/econ424/sbuxPrices.csv";
fmt <- "%m/%d/%Y"
# 1
sbux1.z <
Hello,
I would like to perform a Partial least square discriminate analysis (PLSDA) in
R.
To do this I use the package mixOmics.
I could perform the PLSDA in R. however I would also like to perform a
leave-one-out cross validation in order to assess the performance of my model.
My supervisor
Hi Terry,
I take your question to mean how to label distinct rows of a data frame. If
that is not your question please clarify.
I found the row.match() function in the package prodlim that can be used to
solve this.
However since your request requires no additional dependencies I borrowed
the relev
Many thanks for the assistance. I am using a small sample of GUSTO-1 as a
teaching demonstration. The Gusto-1 dataset in various smaller subsets is
available from this website:
http://clinicalpredictionmodels.org/doku.php?id=rcode_and_data:start which is
associated with the Clinical Predicti
This question likely has a 1 line answer, I'm just not seeing it. (2, 3, or 10 lines is
fine too.)
For a vector I can do group <- match(x, unqiue(x)) to get a vector that labels each
element of x.
What is an equivalent if x is a data frame?
The result does not have to be fast: the data set
Dear All,
While i am trying convert data frame object to zoo object I am
getting numeric(0) error in performance analytics package.
The source code i am using from this website to learn r in finance:
https://faculty.washington.edu/ezivot/econ424/returnCalculations.r
# create zoo objects from dat
Hello,
I would like to do a partial least square discriminant analysis (PLSDA) in R
using the package "ropls"
Which is in R available via the R command :
source("https://bioconductor.org/biocLite.R";)
I try to do a PLSDA to illustrate the impact of two genders (AP,C) on 5
compounds measured in
Hello,
I would like to do a partial least square discriminant analysis (PLSDA) in R
using the package "ropls"
Which is in R available via the R command :
source("https://bioconductor.org/biocLite.R";)
When I try to do a PLSDA using my own data.
The impact of two genders (AP,C) on 5 compounds mea
16 matches
Mail list logo
