Hi Rolf
I am not at all an expert in regex but
gsub("[[:alpha:]]","",x)
Works as you expected. Do not ask me why.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Rolf Turner
> Sent: Wednesday, August 23, 2017 7:46 AM
> To: r-help mail
> On 23 Aug 2017, at 07:45, Rolf Turner wrote:
>
> My reading of ?regex led me to believe that
>
>gsub("[:alpha:]","",x)
>
> should give the result that I want.
That's looking for any of the characters a, l, p, h, : .
What you meant to say was
gsub("[[:alpha:]]","",x)
i.e. the
Try options(digits=12)
sum(v)
BTW I don't get the same value as you did when you calculated manually.
On Tuesday, August 22, 2017, 10:39:26 AM EDT, Bert Gunter
wrote:
... and following up on Spencer's answer, see the "digits" argument of
?options and ?print.default.
Cheers,
Bert
Bert Gunter
I have a vector (say "x") of the form
[1] "mung5" "mung10" "mung20" "gorp5" "gorp10" "gorp20"
I want to extract just the numbers (strings of digits) that appear at
the end of the strings in "x".
My reading of ?regex led me to believe that
gsub("[:alpha:]","",x)
should give the re
R- Help Forum
Working with the "likert" package and find that my "bar" graphs are
backwards (see attached)
> summary(results)
Item low neutral high meansd
4 Q4 5 15 80 2.75 0.5501196
5 Q5 20 40 40 2.20 0.7677719
1 Q1 65 305 1.40 0.5982430
3
Hi Bogdan,
Messy, and very specific to your problem:
df.sample.gene<-read.table(
text="Chr Start End Ref Alt Func.refGene Gene.refGene
284 chr2 16080996 16080996 C T ncRNA_exonic GACAT3
448 chr2 113979920 113979920 C T ncRNA_exonic LINC01191,LOC100499194
465 chr2 1312793
I would appreciate please a suggestion on how to do the following :
i'm working with a dataframe in R that contains in a specific column
multiple gene names, eg :
> df.sample.gene[15:20,2:8]
Chr Start End Ref Alt Func.refGene
Gene.refGene284 chr2 16080996 16080996 C T ncRNA_e
OK, here's the problem. Continuing with your example:
strt1 <- lm(y1 ~1, dat)
strt2 <- lm(frm1,dat)
> strt1
Call:
lm(formula = y1 ~ 1, data = dat)
Coefficients:
(Intercept)
41.73
> strt2
Call:
lm(formula = frm1, data = dat)
Coefficients:
(Intercept)
41.73
Note that the formula
On 2017-08-22 2:04 PM, Patrick Casimir wrote:
>
> This is large data set Spencer. What about when the dates change as below:
>
� Have you tried what I suggested?� What were the results? Spencer
>
> COL1 COL2
> Jan-141-Aug-16
> Feb-141-Aug-16
> Mar-141-Aug-16
> Apr
This is large data set Spencer. What about when the dates change as below:
COL1COL2
Jan-14 1-Aug-16
Feb-14 1-Aug-16
Mar-14 1-Aug-16
Apr-14 1-Aug-16
May-14 1-Aug-16
Jun-14 1-Aug-16
Jul-14 1-Aug-16
Aug-14 1-Aug-16
Sep-14 1-Aug-16
Oct-14 1-Aug-16
Nov-14 1-Aug-16
Dec-14 1-Aug-16
Jan-1
On 22 August 2017 at 17:51, Александр Мащенко wrote:
>
>
> I don't know R absolutely, but I have to do this work for my diploma. So
I'm sorry for strange message below. Please, help me anybody decides this
issue.
[...]
> > write.xlsx(ab_ret,
"C:\\Users\\Sapl\\Desktop\\NATA\\code\\Results\\Create
On 2017-08-22 1:30 PM, Patrick Casimir wrote:
Dear R Fellows,
I Have a dataset( data1) with 2 columns of date showing a class of factor. How
to convert them to date? Then compare them, keep the greater date only in a new
column. Using as.Date to change the class to Date but the data becomes
Dear R Fellows,
I Have a dataset( data1) with 2 columns of date showing a class of factor. How
to convert them to date? Then compare them, keep the greater date only in a new
column. Using as.Date to change the class to Date but the data becomes NA.
Much Thanks
COL1COL2
Apr-16 1-Nov-16
SImplify your call to lm using the "." argument instead of
manipulating formulas.
> strt <- lm(y1 ~ ., data = dat)
and you do not need to explicitly specify the "1+" on the rhs for lm, so
> frm2<-as.formula(paste(trg," ~ ", paste(xvars,collapse = "+")))
works fine, too.
Anyway, doing this gives
Failed? What was the error message?
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Aug 22, 2017 at 8:17 AM, Stephen O'hagan
wrote:
> I'm
Note that if you force a garbage collection each iteration the times are
more stable. However, on the average it is faster to let the garbage
collector decide when to leap into action.
mb_gc <- microbenchmark::microbenchmark(gc(), { x <- as.list(sin(1:5e5)); x
<- unlist(x) / cos(1:5e5) ; sum(x) }
The error is "the model fit failed in 50 bootstrap samples
Error: non-character argument"
Cheers,
SOH.
On 22/08/2017 17:52, Bert Gunter wrote:
Failed? What was the error message?
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking t
This query is offtopic for this list, as it is about statistics, not R
programming. stats.stackexchange.com is a good venue for statistics
questions.
However, you are confused. Wilcoxon does NOT test for differences in
population means. e.g.
Consider the 2 samples:
A: 5,6,7
B: 1,2, 50
Cheers,
Hi,
I am using wilcox.test function to test the difference between the means of
two samples. The data points are paired, so I am using a paired test.
There is one strange case. Sample A has a higher mean than a sample B.
However, wilcox.test function says that sample B has a significantly higher
Caching happens, both within the operating system and within the C standard
library. Ostensibly the intent for those caches is to help performance, but you
are right that different low-level caching algorithms can be a poor match for
specific application level use cases such as copying files or
The large value for maximum time may be due to garbage collection, which
happens periodically. E.g., try the following, where the
unlist(as.list()) creates a lot of garbage. I get a very large time every
102 or 51 iterations and a moderately large time more often
mb <- microbenchmark::microbenc
I don't know R absolutely, but I have to do this work for my diploma. So I'm
sorry for strange message below. Please, help me anybody decides this issue.
If you need any information, I'll show you all what you need.
**error**:
> #save
> #csv
>file.create("C:\\Users\\Sapl\\Desktop\\NATA\\code\\Res
I'm trying to use boot.stepAIC for feature selection; I need to be able to
specify the name of the dependent variable programmatically, but this appear to
fail:
In R-Studio with MS R Open 3.4:
library(bootStepAIC)
#Fake data
n<-200
x1 <- runif(n, -3, 3)
x2 <- runif(n, -3, 3)
x3 <- runif(n, -3
... and following up on Spencer's answer, see the "digits" argument of
?options and ?print.default.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On 2017-08-22 9:26 AM, niharika singhal wrote:
Hello I have a vector
v=c(0.0886,0.1744455,0.1379778,0.1209769,0.1573065,0.1134463,0.2074027)
when i do
sum(v)
or
0.0886+0.1744455+0.1379778+0.1209769+0.1573065+0.1134463+0.2074027
i am getting output as 1
No: That's only the display:
Hello I have a vector
v=c(0.0886,0.1744455,0.1379778,0.1209769,0.1573065,0.1134463,0.2074027)
when i do
sum(v)
or
0.0886+0.1744455+0.1379778+0.1209769+0.1573065+0.1134463+0.2074027
i am getting output as 1
But if i add them manually i get
1.0026
I do not want to round of my value since
Not convinced Jeff is completely right about this not concerning R, since I've found that the application language (R,
perl, etc.) makes a difference in how files are accessed by/to OS. He is certainly correct that OS (and versions) are
where the actual reading and writing happens, but sometimes
You need to study how reading files works in your operating system. This
question is not about R.
--
Sent from my phone. Please excuse my brevity.
On August 22, 2017 5:53:09 AM PDT, raphael.fel...@agroscope.admin.ch wrote:
>Dear all
>
>I was thinking about efficient reading data into R and tried
Dear all
I was thinking about efficient reading data into R and tried several ways to
test if load(file.Rdata) or readRDS(file.rds) is faster. The files file.Rdata
and file.rds contain the same data, the first created with save(d, '
file.Rdata', compress=F) and the second with saveRDS(d, ' file
Dear Jeff,
Thank you! You helped me a lot!
Tagmarie
Am 19.08.2017 um 08:11 schrieb Jeff Newmiller:
Thank you for providing the example code... for the request of running
it multiple times it would have helped if you could have confirmed
that the example ran through without errors... there we
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