Hi Troels,
I get no error. I think we need more information to be of any help.
Best wishes,
Ulrik
On Fri, 7 Apr 2017 at 08:17 Troels Ring wrote:
> Dear friends - I have further problems handling dates_times, as
> demonstrated below where concatenating two formatted vectors of
> date_times res
Dear friends - I have further problems handling dates_times, as
demonstrated below where concatenating two formatted vectors of
date_times results in errors.
I wonder why this happens and what was wrong in trying to take these two
vectors together
All best wishes
Troels Ring
Aalborg, Denmark
W
Hi All,
I am using mailR package to send emails by attaching my local image files.
However the image still refers to my file location and never truly embeds
the image in the email.
This came up in testing when my colleague was getting a red cross instead
of an image.
Any thoughts to resolve this
Ulrik's solution gives you factors. To get them as characters, add as.is=TRUE:
> m %>%
+as_tibble() %>%
+lapply(type.convert, as.is=TRUE) %>%
+as_tibble()
# A tibble: 4 × 5
A B C D E
1 a e i 1 11.2
2 b f j 2 12.2
3 c
I believe the answer is: No. "Line number" is an ambiguous concept.
Does it mean physical line on a display of a given width? a line of
code demarcated by e.g. ; a step in the execution of script (that
might display over several physical lines?)
However, various IDE's have and display "line numbe
Hello,
Is there a way to get the current line number in an R script?
As a silly example, if I have the following script and a function called
getLineNumber (suppose one exists!), then the result would be 3.
1 # This is start of script
2
3 print( getLineNumber() )
4
5 # End of script
Thanks for
Hi,
Thanks for this solution! Very slick!
I see what you mean about the two calls to as_tibble(). I suppose I could do
the following, but I doubt it is a gain...
mm <- lapply(colnames(m), function(nm, m) type.convert(m[,nm], as.is = TRUE),
m=m)
names(mm) <- colnames(m)
as_tibble(mm)
# # A t
On Thu, 6 Apr 2017, Massimo Bressan wrote:
hello
given my reproducible example
#---
date<-seq(ISOdate(2017,1, 1, 0), by="hour", length.out = 48)
v1<-1:48
df<-data.frame(date,v1)
#--
"date" and "df" are functions in base R... best to avoid hiding them by
re-using those names in the global e
Hi Ben,
type.convert should do the trick:
m %>%
as_tibble() %>%
lapply(type.convert) %>%
as_tibble()
I am not too happy about to double 'as_tibble' but it get the job done.
HTH
Ulrik
On Thu, 6 Apr 2017 at 16:41 Ben Tupper wrote:
> Hello,
>
> I have a workflow yields a character matrix
This is far from portable programming but as R looks to search for
/etc/localtime it is simpler for me do like that.
I will not patch R source code to make "make check" step works.
Then for my own code, I will use
x <- as.POSIXct(strptime("2002-02-02 02:02", "%Y-%m-%d %H:%M"))
or
Sys.set
I cannot imagine a less desirable solution. This is the opposite of portable
programming.
--
Sent from my phone. Please excuse my brevity.
On April 6, 2017 5:29:08 AM PDT, Sebastien Moretti
wrote:
>I have just found the solution.
>
>We have a custom Linux distribution that allows us to have
>
> gamObj=gam(brainVolume~ s(correctedAge) + s(subjIndexF, bs="re") +
> s(subjIndexF, correctedAge, bs="re"), method="REML", data=mydata),
> where subjIndexF is a factor for each subject. I was thrown an error
> saying "more coefficients than data".
>
--- I'm not sure exactly how many scans a
You always need to set your timezone somehow when converting to POSIXt.
Technically the method for doing this varies by OS, but on all environments I
have worked with you can set the default timezone with something like
Sys.setenv( TZ="Etc/GMT+5" )
In your example, some timezones supporting da
Hello,
I have a workflow yields a character matrix that I convert to a tibble. Here is
a simple example.
library(tibble)
library(readr)
m <- matrix(c(letters[1:12], 1:4, (11:14 + 0.2)), ncol = 5)
colnames(m) <- LETTERS[1:5]
x <- as_tibble(m)
# # A tibble: 4 × 5
# A B C D
See 'shade' parameter in ?plot.gam (mgcv)
On 06/04/17 00:34, Husam El Alqamy wrote:
Dear List
I am fitting some GAM models using the package mgcv. When plotting the
response curves of the individual predictors using gam.plot I get a dotted
line of the confidence interval around the fitted line.
My guess is that the model has identifiability problems and that this is
then causing a problem (not caught properly) in the model fitting
optimizer. Is there any chance you could send data that produces the
problem (off list) and I can try it out (I will only use any data for
this investigatio
I have just found the solution.
We have a custom Linux distribution that allows us to have several R (+
glibc and others) versions in parallel for tools related to our job domain.
We have another etc/ folder for those tools and R looks for the
localtime file there, not in /etc/.
So linking /
If 'subjIndexF' is a factor for subject, then s(subjIndexF, bs="re")
will produce a random effect for subject. i.e. each subject will be
given its own random intercept term, which is a way that repeated
measures data like this are often handled.
The reason for the s(subjIndexF, bs="re") syntax
hello
given my reproducible example
#---
date<-seq(ISOdate(2017,1, 1, 0), by="hour", length.out = 48)
v1<-1:48
df<-data.frame(date,v1)
#--
I need to calculate the average of variable v1 at specific hour "endpoints" of
the day: i.e. at hours 6.00 and 22.00 respectively
the desired resu
Hello Louisa,
THis is not a R solution but would it not be easier to use ImageMagick to do
what you are wanting to do? Look up
https://www.imagemagick.org/script/index.php
HTH,
Ranjan
On Wed, 5 Apr 2017 08:23:51 +0100 Louisa Reynolds via R-help
wrote:
> Ok. I have a tiff of size over 2GB. It
[With apologies for cross-posting]
Hi all,
We have today published a blog post on eLife Labs about how scientists can
use the dynamic document language, R Markdown, for creating reproducible
manuscripts.
At eLife, we aim to make the communication of results more beneficial for
the scientific com
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