A) You have been given a workaround (colClasses).
B) 3.2.3 is not the current version of R. Support for older versions may vary
from CRAN mirror to mirror. You could try another mirror.
C) Technically, "Linux" is not an operating system, it is a kernel. Debian and
Fedora are examples of operat
Dear Rxperts..
I am using R version 3.2.3 on Linux.. it says bit64 is not available for R
version 3.2.3..
Thanks and your assistance much appreciated!
Best regards,
Santosh
On Wed, Mar 22, 2017 at 7:50 PM, Santosh wrote:
> Thanks so much for your suggestions! Will try them out!
>
> Santosh
>
>
Thanks so much for your suggestions! Will try them out!
Santosh
On Wed, Mar 22, 2017 at 12:17 PM, Matt Dowle wrote:
> Thanks Bill for cc.
>
> Santosh,
>
> I'm almost certain you don't have package bit64 installed. When you do it
> works fine :
>
> > remove.packages("bit64")
> > data.table::fre
I can't see anything wrong with your code. You should read the posting
guide and produce a minimal example showing the problem and any other
details requested there.
If I take just the small sample of data that you have provided and run a
slightly adapted version of your code
data = read.table("q
Hello,
There's a paenthesis missing in
> relativerisk<- matrix(log(c(1,1,2,2),ncol=4,byrow = TRUE)
+ beta_true<-relativerisk
Error: unexpected symbol in:
"relativerisk<- matrix(log(c(1,1,2,2),ncol=4,byrow = TRUE)
beta_true"
The correct instruction would be
relativerisk<- matrix(log(c(1,1,2,2))
Thanks Bill for cc.
Santosh,
I'm almost certain you don't have package bit64 installed. When you do it
works fine :
> remove.packages("bit64")
> data.table::fread("9876543210\n")
V1
1: 4.879661e-314
> install.packages("bit64")
> data.table::fread("9876543210\n")
V1
1: 9
Good afternoon,
I was wondering if someone could help me with what I am sure is likely to be a
really simple problem but I cannot work out what I have done wrong. I have
tried searching the forums/Google etc but can't find anything quite like the
code I am using other than things that do not di
Here is a way to reproduce the problem:
> data.table::fread("9876543210\n") # number bigger than 2^31-1
V1
1: 4.879661e-314
and your work-around does fix things up
> data.table::fread("9876543210\n", colClasses="numeric")
V1
1: 9876543210
Bill Dunlap
TIBCO Soft
You failed to provide a reproducible example, and you posted HTML so the
quality of any answer will be limited by the quality of your question.
My stab at your problem is that you should read ?fread, and in particular
should try using the colClasses argument.
--
Sent from my phone. Please excus
Hi
I have been using "fread" utility of "data.table" packge .. on a dataset of
about 20 million rows. It's a fantastic package to read datasets. Thank
you, Matt D.
However, I am faced with a peculiar instance of certain numbers in a
column being transformed.
In the dataset, a column has values
You did not describe the goal of your pattern matching. Were you trying
to match any string that could be interpreted as an R expression containing
X1 and X3 as additive terms? If so, you could turn the string into a one-sided
formula and use the terms() function. E.g.,
f <- function(string) {
The subset argument is evaluated in "data" first, then in the caller's
environment, etc.
So:
1) In your first example, stype is a *vector*, and the subset
expression is identically TRUE, hence is equivalent to making the call
without the subset argument.
2) The second call fits the subset with st
The `c` function is extremely common. You CAN redefine this object as a numeric
variable if you want but I strongly recommend against it.
I don't recognize the function you are using to create cvfits, but it looks
like the coef method for that object is not returning a numeric vector, so your
Hi ,I have some question about simulate, I don't know how to paste question
to this website,so I paste below.
I use genoud to find the maximum likelihood value, but when I use numcut=3
,it will get error message,like this " coxph.wtest(fit$var[nabeta, nabeta],
temp, control$toler.chol) : NA/NaN/Inf
I'm trying to run the code: inds<-which(c != 0 ), but it gave me error: Error
in base::which(x, arr.ind, useNames, ...) : argument to 'which' is not logical
Here is code:
alphas <- seq(0, 1, by=.002)mses <- numeric(501)mins <- numeric(501)maxes <-
numeric(501)for(i in 1:501){ cvfits <- cv.glmn
Wow. Thanks to everyone (Jim, Ng Bo Lin, Bert, David, and Ulrik) for
all the quick and helpful responses. They have given me a better
understanding of regular expressions, and certainly answered my
question.
Joe
On Wed, Mar 22, 2017 at 12:22 AM, Ulrik Stervbo wrote:
> Hi Joe,
>
> you could also
I implemented the second as well. It was much easier to create a function to
automate this as well as assign the results to a single data.frame
Shawn Way, PE
-Original Message-
From: Jeff Newmiller [mailto:jdnew...@dcn.davis.ca.us]
Sent: Tuesday, March 21, 2017 5:40 PM
To: r-help@r-pr
Tree dbh haut Btot
1 35.00 18.90 0.357
2 25.00 16.60 0.214
3 23.00 19.50 0.173
4 13.50 15.60 0.060
5 20.00 18.80 0.134
6 23.00 17.40 0.137
7 29.00 19.90 0.428
8 17.60 18.20 0.100
9 31.00 25.30 0.514
10 26.00 23.50 0.273
11 13.00 13.00 0.031
12 32.00 20.70 0.356
13 28.00 28.50 0.349
14 15.00 18.20 0
Dear All,
I am trying to extract a time series dataset from a netCDF file.
I want to extract data for the time period 1971-1 to 1990-12-31 only.
time axis units is 'days since 1850-1-1'
For one or two files I can use "count" argument, but I have more than 100
such files and its time units a
On Wed, 22 Mar 2017, Michael Dayan wrote:
The method of setting the initial values given lambda, alpha1, etc. should
not depend on the exact values of lambda, alpha1, etc. in my situation,
i.e. it does not depend on my data.
Presently, flexmix() that betamix() is built on cannot take the param
Hi
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of RAHUL
> 14BCE0064
> Sent: Monday, March 20, 2017 12:24 PM
> To: r-help@r-project.org
> Subject: [R] A request
>
> Hello there!!
>
> Could somebody please go through the question (
> http://stats.stack
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