## 1.
## This could be captured into a function
tmp <- matrix(0, 7, 4)
tmp
diag(tmp) <- 1
diag(tmp[-1,]) <- 2
diag(tmp[-(1:2),]) <- 3
diag(tmp[-(1:3),]) <- 4
tmp
## 2.
v <- 1:4
v2 <- c(v, rep(0, length(v)))
## this generates a warning that can safely be ignored (or turned off)
matrix(v2, length(
If your problem really requires genetics jargon to be expressed, then perhaps
you should be asking it in a forum where more of the participants are likely to
understand it... like the Bioconductor help forum?
https://www.bioconductor.org/help/support/
The Posting Guide mentioned in the footer h
Hi,
I am analyzing a huge excel table with OTUs. In the table, I have 2910
columns and 365 rows.Each column represents one individual (n=2910). Rows
represent microbial species (n=365).
I have the total of all OTUs of microbial species under each column. Then I
need to get the percentages of each s
Since 2008, Microsoft (formerly Revolution Analytics) staff and guests
have written about R every weekday at the Revolutions blog
(http://blog.revolutionanalytics.com) and every month I post a summary
of articles from the previous month of particular interest to readers
of r-help.
In case you miss
Perhaps FAQ 7.16 ? (Are you sourcing the code?)
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Mar 6, 2017 at 11:54 AM, Henry Cann wrote:
> I h
I have combined two layers to create a shapefile which I am colouring using
the Choropleth function in GISTools. The problem I am having is that
despite having no other problems with my code including with the actual
mapping of the choropleth itself, nothing I can do, using choro.legend,
actually a
Effectively you want a circulant matrix but filled by column.
Example input vector and number of columns
x = c(1:8,19:20)
nc = 5
For the result you specifically describe, the following generalises for any
vector and any arbitrary number of columns 'nc', padding with zeros as
necessary.
matrix
Well, of course, I *did* make a dumb error (again!!). Here's the
corrected version:
x <- c(1:5,10:12)
## generate vector of indices by outer and %%
i <- seq_along(x)
nc <- 4 ## number of columns desired
Corrected statement
indx <- (outer(i, rev(i-1),"+") %% length(x)) [,seq_len(nc)] +1
Try 3.3.3, it has
INSTALLATION on a UNIX-ALIKE:
* The configure check for the zlib version is now robust to
versions longer than 5 characters, including 1.2.11.
-pd
> On 06 Mar 2017, at 16:12 , Adamo Dahmani wrote:
>
> Hi,
>
> I am trying to install R-3.3.2 in my user account. I hav
Clever, Don.
Here's a more explicit approach that generalizes (if I haven't made
any dumb errors):
x <- c(1:5,10:12)
## generate vector of indices by outer and %%
i <- seq_along(x)
nc <- 4 ## number of columns desired
## get subscripting indices via outer() and %%
indx <- outer(i,rev(i),"+") %% (
Hello,
I see that quite some packages nowadays use testthat and that RUnit doesn't
have recent updates. On the other hand Rccp, fTrading and others (still)
test with RUnit.
My old code uses RUnit and I would prefer to keep it that way unless there
is an important reason to switch to testthat. If
Hello,
Try the following.
proj <- function(x){
n <- length(x)
y <- numeric(n)
z <- rep(c(x, y), times = n)
z <- z[-((length(z) - n + 1):length(z))]
matrix(z, ncol = n)
}
proj(1:4)
proj(1:5)
Hope this helps,
Rui Barradas
Em 06-03-2017 16:18, Peter Thure
How about this:
p0 <- 1:4
matrix( c( rep( c(p0, rep(0, 4)) , times=3) , p0) , 7, 4)
Of course, it would take some effort to generalize it to different lengths for
p0.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 3/6/
Probably should take this question to the R-sig-geo mailing list.
And you will need to tell people exactly what command(s) you used, and the
exact resulting error message.
Possibly you will have to ask for help from Rstudio, if it turns out the cause
somehow has to do with Rstudio; I have no id
Hello,
Is there a function in R which can transform, let say a vector:
c(1:4)
to a matrix where the vector is repeated but "projected" +1 one step down for
every (new) column.
I want the output below from the vector above, like this:
p<-c(1,2,3,4,0,0,0,0,1,2,3,4,0,0,0,0,1,2,3,4,0,0,0,0,1,2,3,4
Hi,
I am trying to install R-3.3.2 in my user account. I have already installed
all needed libraries.
I run this command :
./configure 'LDFLAGS=-R$HOME/software/bzip2-1.0.6/
-R$HOME/software/zlib-1.2.11 -L$HOME/software/bzip2-1.0.6
-L$HOME/software/zlib-1.2.11 -L$HOME/software/xz-5.2.3/bin/lib/
Dear all,
let me please announce two new R packages for interactive dendrogram
exploration: idendro and idendr0.
idendro [1] enables useRs to inspect hierarchical clustering dendrograms
interactively: to select and color clusters, to zoom and pan the
dendrogram, and to visualize the clustered dat
Hello
I am trying to install gdalutils package in R 3.3.2 and Rstudio 1.0.136 ,
but some error is happening and it is unable to install. can you help me
out ?
Thanks !!
Regards
Sruti
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R-help@r-project.or
On 06/03/2017 07:45, g.maub...@weinwolf.de wrote:
Hi Michael,
thank for you answer.
Where do I have to put the code snippet "p(3cm)"? Is it neither an
official argument to xtable() nor to print.xtable().
From the help about the align argument:
Character vector of length equal to the numbe
The build system rolled up R-3.3.3.tar.gz (codename "Another Canoe") this
morning.
The list below details the changes in this release.
You can get the source code from
http://cran.r-project.org/src/base/R-3/R-3.3.3.tar.gz
or wait for it to be mirrored at a CRAN site nearer to you.
Binaries fo
Hi laomeng,
If you know how to plot the means and calculate the standard
deviations, perhaps look at the "dispersion" function in the plotrix
package.
Jim
On Sat, Mar 4, 2017 at 5:39 PM, laomeng_3 wrote:
> hi all
> I have a question about drawing the confidence interval .
>
> For instance,if I
On 06/03/17 19:35, laomeng_3 wrote:
this is not homework, just a case which I made by myself.
Be that as it may, if you are going to use R you should learn something
about using R, rather than treating it as a magical black box.
There is, as far as I know (not really very far!) no currently
On 3/5/2017 10:35 PM, laomeng_3 wrote:
this is not homework,just a case which I made by myself.
�ʦ
On 2017-03-06 06:47 , Rolf Turner Wrote:
On 04/03/17 19:39, laomeng_3 wrote:
hi all I have a question about drawing the confidence interval .
For instance,if I want to sample 100
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