On 11/02/17 00:27, mamuash bukana wrote:
Suppose we calculate probability of an event using Binomial
distribution and got p1. Then probability of that same event is
calculated using the Normal approximation to Binomial and got p2.
Can't we evaluate the goodness of our approximation by comparing
Please use R-SIG-Mac and include important details such as your sessionInfo()
as well as how you installed the packages. Also make sure you have re-installed
Rcpp and that you don't have an older version on your library path.
Cheers,
Simon
> On Jan 1, 2016, at 9:54 PM, Paul Schlesinger wrote
IMHO, You were given an appropriate answer. Please follow its advice.
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Fri, Feb 10, 2017 at 3:27 AM, ma
Dear Mamuash
I expect you will shortly get an email telling you that this is
off-topic as it is about statistics not R but in the mean time you might
search for "scoring rules" or even "Brier score". I am afraid I am not
an expert in this area and they possibly do not answer your question but
Suppose we calculate probability of an event using Binomial
distribution and got p1. Then probability of that same event is
calculated using the Normal approximation to Binomial and got p2.
Can't we evaluate the goodness of our approximation by comparing the
difference between p1&p2? If yes, how to
On 10/02/17 21:12, mamuash bukana wrote:
Dear R users,
I wanted to test if there is significant difference between
probabilities of the same event calculated in different ways. I am
aware about the prop.test() which does the comparison between two
proportions given the number of successes and s
Dear R users,
I wanted to test if there is significant difference between
probabilities of the same event calculated in different ways. I am
aware about the prop.test() which does the comparison between two
proportions given the number of successes and sample sizes. But in my
case the only values I
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