Greetings,
Firstly, I'd hope this is the correct e-mail address to ask about specific
problems refering to problems with R. If it isn't, I kindly ask of you to
re-direct me to the correct contact person.
So, the thing with my version of R (I'm using RStudio for R x64 3.3.0 in,
currently, Windows
> On Oct 14, 2016, at 6:53 PM, Joe Ceradini wrote:
>
> Hopefully this looks better. I did not realize gmail default was html.
>
> I have a dataframe with a column that has many field smashed together.
> I need to split the strings in the column into separate columns based
> on patterns.
>
> Ex
should be strsplit(ugly, attributes) not strplit(ugly, attributes)
On Fri, Oct 14, 2016 at 7:53 PM, Joe Ceradini wrote:
> Hopefully this looks better. I did not realize gmail default was html.
>
> I have a dataframe with a column that has many field smashed together.
> I need to split the str
Hopefully this looks better. I did not realize gmail default was html.
I have a dataframe with a column that has many field smashed together.
I need to split the strings in the column into separate columns based
on patterns.
Example of a string that needs to be split:
ugly <- c("Water temp:14: F
On Fri, 14 Oct 2016, David Winsemius wrote:
Notice that the formula has just the column names rather than using `$`.
But need to give `rain$date` to functions in hte scales list. It always
seemed to me that the evaluation of names inside the scales list should
also be evaluated inside the `data`
> On Oct 14, 2016, at 4:16 PM, Joe Ceradini wrote:
>
> Afternoon,
>
> I unfortunately inherited a dataframe with a column that has many fields
> smashed together. My goal is to split the strings in the column into
> separate columns based on patterns.
>
> Example of what I'm working with:
>
>
> On Oct 14, 2016, at 3:51 PM, Rich Shepard wrote:
>
> On Fri, 14 Oct 2016, David Winsemius wrote:
>
>>> rain <- source("~/raindata.dat")
>>> str(rain)
>> List of 2
>> $ value :'data.frame': 341 obs. of 3 variables:
>> ..$ station: Factor w/ 6 levels "0.3E","0.6W",..: 1 1 1 1 1 1 1 1 1 1
Afternoon,
I unfortunately inherited a dataframe with a column that has many fields
smashed together. My goal is to split the strings in the column into
separate columns based on patterns.
Example of what I'm working with:
ugly <- c("Water temp:14: F Waterbody type:Permanent Lake/Pond: Water
pH:
On Fri, 14 Oct 2016, David Winsemius wrote:
rain <- source("~/raindata.dat")
str(rain)
List of 2
$ value :'data.frame': 341 obs. of 3 variables:
..$ station: Factor w/ 6 levels "0.3E","0.6W",..: 1 1 1 1 1 1 1 1 1 1 ...
..$ date : Factor w/ 62 levels "2013-12-01","2013-12-02",..: 32 33 34
> On Oct 14, 2016, at 12:03 PM, Rich Shepard wrote:
>
> I've read chapters 7 and 8 in the Lattice book and do not see how to thin
> labels on the x and y axes of an xyplot(), and how to rotate the dates on
> the x axis for easier reading (rot did not do the job for me.)
>
> The data (as raind
Dear group,
I have a matrix (300 rows X 475columns).
The data is divided into many classes.
For examples:
475 columns are split into 3 categories - A, B and C
Is it possible to force clustering of columns in A followed by B and C.
I do not want to cluster whole matrix. I want to cluster by 3 categ
Hello,
You have to convert y1 to class "Date" first, then do date arithmetic.
The complete code would be
dat<-read.table(text=" y1, flag
24-01-2016,S
24-02-2016,R
24-03-2016,X
24-04-2016,H
24-01-2016,S
24-11-2016,R
24-10-2016,R
24-02-2016,X
24-01-2016,H
24-11-2016,S
24-02-2016,R
24-10-2016,X
Thank you Rui,
It Worked!
How about if the first variable is date format? Like the following
dat<-read.table(text=" y1, flag
24-01-2016,S
24-02-2016,R
24-03-2016,X
24-04-2016,H
24-01-2016,S
24-11-2016,R
24-10-2016,R
24-02-2016,X
24-01-2016,H
24-11-2016,S
24-02-2016,R
24-10-2016,X
24-03-2016,H
24-
Ashta,
## I may have misunderstood your question and if so I apologize.
## I had to remove the extra line after "45" before
## the ",sep=" to use your code.
## You could have used dput(dat) to send a more reliable (robust) version.
dat <- structure(list(ID = c(1L, 1L, 1L, 1L, 2L, 2L, 2L, 3L, 3L,
I've read chapters 7 and 8 in the Lattice book and do not see how to thin
labels on the x and y axes of an xyplot(), and how to rotate the dates on
the x axis for easier reading (rot did not do the job for me.)
The data (as raindata.dat) and the existing plot (as precip.pdf) are
attached.
For the data you provide, it's simply:
summary(subset(dat, x1 == "x" & x2 == "z")$y)
Note that x1 and x2 are factors in your example.
We also don't know what you want to do if there are more than one
combination of that per ID, or if there ID values with no matching
rows.
Sarah
On Fri, Oct 14,
Hi all,
I am trying to summarize big data set by selecting a row
conditionally. and tried to do it in a loop
Here is the sample of my data and my attempt
dat<-read.table(text=" ID,x1,x2,y
1,a,b,15
1,x,z,21
1,x,b,16
1,x,k,25
2,d,z,31
2,x,z,28
2,g,t,41
3,h,e,32
3,x,z,38
3,x,g,45
",sep=",",he
Having worked in big pharma for over 10 years, I'm _fairly_ certain
AstraZeneca can afford some paid R consulting.
On Fri, Oct 14, 2016 at 2:14 PM, David Winsemius wrote:
>
>> On Oct 14, 2016, at 12:05 AM, Vijayakumar, Sowmya
>> wrote:
>>
>> Hi R-Help team,
>>
>>
>> Greeting from AstraZeneca In
> On Oct 14, 2016, at 12:05 AM, Vijayakumar, Sowmya
> wrote:
>
> Hi R-Help team,
>
>
> Greeting from AstraZeneca India!!
>
>
>
> We are currently using *R 3.1.1* in Windows machine for one of our
> application. We have a plan to upgrade the application. Please let us know
> the steps to
> On Oct 13, 2016, at 2:36 PM, Tan, Johnny wrote:
>
> I posted this on stackoverflow but there hasn't been any replies, does anyone
> know a solution for this?
>
>
>
>
>
> I am running a script via command line using Rscript nameOfmyRscript. I
> notice that when there is an error, my brow
Dear all,
I am trying to clean return data using the Return.clean() function in the
PerformanceAnalytics package. Hence, my code looks as follows but I get an
error message.
cleantest <- read.csv("D:/Studie_vola_difference/cleantest.csv")
data<-as.vector(cleantest)
test<-Return.clean(data,met
Ugly idea/option, but you could base64 encode the R script (solely to
avoid the need to do string quoting) and have that string in the
source of the R.net code, then pass it in to the eval portion or write
it out to a temp dir and pass that to the eval portion of the code.
That way the script is em
Thanks Duncan. That's useful to know.
On Fri, Oct 14, 2016 at 9:18 AM, Duncan Murdoch
wrote:
> On 14/10/2016 10:00 AM, Narendra Modi wrote:
>>
>> Hello Gurus,
>>
>> I have built a code snippet using R.net wherein I call couple of R
>> scripts to run optimization packages and use the output in C#
On 14/10/2016 10:00 AM, Narendra Modi wrote:
Hello Gurus,
I have built a code snippet using R.net wherein I call couple of R
scripts to run optimization packages and use the output in C# code.
The way I call the R scripts is just by providing its location in the
C# code.
So, if I have to share
Hello Gurus,
I have built a code snippet using R.net wherein I call couple of R
scripts to run optimization packages and use the output in C# code.
The way I call the R scripts is just by providing its location in the
C# code.
So, if I have to share the .dll of the complete program, I will also
h
Hi
This sounds off topic, but as I want to analyse the data in R and the R
community is extremely knowledgeable in many respects.
So here I go:
I have "inherited" a literature list for further analysis containing
more than 5000 references. What I would like to do is construct citation
trees (who
Hi,
Is there any possibility that we can capture cpu usage ,memory usage and
disks info using R language on *windows family OS* ?
I would like to see data that’s looks like
a
below
Cpu usage : 70 %
Memory usage : 80 %
Disks: C drive – 40 % full,D dive – 60 %,full E
Hi
Another option is to use ave
1*(data2$molecule>ave(data2$molecule, data2$fruit, FUN=function(x) 2*sd(x)))
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Jim Lemon
> Sent: Friday, October 14, 2016 10:51 AM
> To: Andreas Nord
> Cc:
Hi
?factor
?expand.grid
something like
ff<-factor(sample(1:3, 10, replace=T))
factor(ff, labels=c("male", "female", "mixed"))
[1] male female mixed mixed female female female female mixed male
Levels: male female mixed
Cheers
Petr
>
> -Original Message-
> From: R-help [mailto:r-h
Hi Andreas,
Try this:
fruit_2sds<-by(data2$molecule,data2$fruit,sd)*2
data2$newcol<-ifelse(data2$molecule>fruit_2sds[data2$fruit],1,0)
or even just:
data$newcol<-as.numeric(data2$molecule>fruit_2sds[data2$fruit])
Jim
On Fri, Oct 14, 2016 at 5:17 PM, Andreas Nord wrote:
>
> Dear list,
>
> Apo
Thanks for everyone for your suggestions. I am trying to use the techniques
that you suggested and I will update you its outcome so that it might be
useful to other too.
Thanks,
On Thu, Oct 13, 2016 at 2:10 PM, Duncan Murdoch
wrote:
> On 13/10/2016 11:14 AM, Thomas Adams wrote:
>
>> Duncan,
>>
Hi Marna
These are a few suggestions for EDA of your data
Firstly check it – it is laborious work but it needs to be done – use a proper
database if R is not suitable (memory,time)
dat <- read.csv("G:/1/example_subsetdata.csv")
dat <- subset(dat, !is.na(depth))
apply(dat,2,range,n
Hi R-Help team,
Greeting from AstraZeneca India!!
We are currently using *R 3.1.1* in Windows machine for one of our application.
We have a plan to upgrade the application. Please let us know the steps to
download the R which is compatible with *Oracle Enterprise Linux (OEL) v6.5.*
Thanks,
Karline,
You may want to explore Green Kenue
(http://www.nrc-cnrc.gc.ca/eng/solutions/advisory/green_kenue_index.html). It
is freely available (download through an email request) and supports 3D data
visualization and I believe it now has a python API to allow some automation.
Unfortunately
I posted this on stackoverflow but there hasn't been any replies, does anyone
know a solution for this?
I am running a script via command line using Rscript nameOfmyRscript. I notice
that when there is an error, my browser would open with the help page. Now my
script contained repeated erro
Sorry to send this report by email, but I cannot see a way how to create
a login on https://bugs.r-project.org
Problem-Description:
I'm using the foreign package to read EPIINFO 6 files. (.REC)
All my .REC files end with a single character after the last line break.
Octal: 032 / Hex: 1A
The output
Dear list,
Apologies for a likely naive question.
I am trying to create a discriminating dummy variable using 'ifelse' based on
conditions in two variables.
Specifically, I want to assign levels in a new factor as '0' or '1' based on a
user-defined cut off. I.e. something similar to:
>da
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