> On Aug 25, 2016, at 10:18 AM, David Remotti wrote:
>
> hello all, and thanks in advance for any eventual help.
> I'am quite new to R, and want to use the package SURVEY to calculate results
> from a sampling.
First: It is spelled "survey"
> I have installed the package and started studying
If you label opening times with +1 and closing times with -1 then
cumsum(thoseLabels) will tell you how many shops are open immediately after
each of those times. You can use findInterval() on the times to map an
arbitrary time to the number of shops open at that time. You do need to
deal with st
Hi Alexander,
A time series comes to mind, but perhaps all you need is a matrix with
0s for closed and 1s for open. Each row is a shop. Column names as the
times and the resolution is up to you. I think colSums will produce
what you want.
Jim
On Fri, Aug 26, 2016 at 1:10 AM, alexander.som...@tu-d
Hello,
I used the function "mix" (package "mixdist'') to fit Gamma mixture
distributions. The function gives mu and sigma parameters (output below). How
can I find the scale and shape parameters of the Gamma distributions ?
Parameters:
pimu sigma
1 0.2089 185.7 285.4
2 0.7911 530.1
Mmm...The other option working with R for importing the dta file but
obtaining the values and deleting or ignoring the value labels.
I think some time ago i did that, but now i can't remember it.
On Thu, Aug 25, 2016 at 4:11 PM, wrote:
> So you should do
>
> table(region[sex=="Hombre"],type[se
Dear R-users,
We are currently conducting a user study evaluating visualization methods
from the R-package VIM
(https://cran.r-project.org/web/packages/VIM/VIM.pdf) in the context of
displaying missing data. Our aim is to evaluate what type of visualization
may be best for solving particular task
> str(sex)
Factor w/ 2 levels "Hombre","Mujer": 1 2 2 1 2 2 1 1 1 1 ...
On Thu, Aug 25, 2016 at 1:42 PM, wrote:
> Maybe sex is a factor and Man its label. Factors are coded internally as
> integers, to see it use
>
> str(sex)
>
> Rui Barradas
>
>
> Citando Juan Ceccarelli Arias :
>
> Nop. I did
hello all, and thanks in advance for any eventual help.
I'am quite new to R, and want to use the package SURVEY to calculate
results from a sampling.
I have installed the package and started studying it, but I find
difficulties in understanding how to prepare my data (I actually have
them in a
So you should do
table(region[sex=="Hombre"],type[sex=="Hombre"]
Rui Barradas
Citando Juan Ceccarelli Arias :
str(sex)
Factor w/ 2 levels "Hombre","Mujer": 1 2 2 1 2 2 1 1 1 1 ...
On Thu, Aug 25, 2016 at 1:42 PM, wrote:
_Maybe sex is a factor and Man its label. Factors are coded
inte
You need to (re-)read the "Introduction to R" document that comes with R. R Is
not Stata, and you should not expect R to look syntactically like Stata.
Note that if you, against normal R convention, wish to manipulate the integers
that a factor is implemented with, you can create such a variabl
Maybe sex is a factor and Man its label. Factors are coded internally
as integers, to see it use
str(sex)
Rui Barradas
Citando Juan Ceccarelli Arias :
> Nop. I didn't work. But using the following it does work.
> table(region[sex=="Men"],type[sex=="Men"])
> When i use the dta file with stat
Nop. I didn't work. But using the following it does work.
table(region[sex=="Men"],type[sex=="Men"])
When i use the dta file with stata i declare the condition with sex==1 and
not sex=="Man".
On Thu, Aug 25, 2016 at 12:39 PM, wrote:
> Hello,
>
> Try instead
>
> table(region[sex==1],type[sex==1])
Hi fellow R-users,
I am wondering about the best way to store business hours and the like in R.
(Best in the sense of best for analyzing them.)
Say, I got a number of “shops”:
Shop A opens at 8am and closes at 8pm;
shop B opens at 9am, closes at 11.45am for a siesta, reopens at 1.30pm and
close
Hello,
Try instead
table(region[sex==1],type[sex==1])
To test for equality use == not =.
Hope this helps,
Rui Barradas
Citando Juan Ceccarelli Arias :
> Hi
> Im a bit lost.
> Ive imported a stata13 file. When i try to make a simple
> table(region[sex=1],type[sex=1])
> i get something as
>
Hi
Im a bit lost.
Ive imported a stata13 file. When i try to make a simple
table(region[sex=1],type[sex=1])
i get something as
type1 type2
region1 0 0
region2 0 0
region3 0 0
I don't know how to operate with the value labels.
Sex is defined as 1 as "Man" and 2 as "Female".
And region1 i
I am getting a warning message when I run lme:
Warning message:
In lme.formula(fixed = value ~ CorT + time + CorT * time, data = GD) :
fewer observations than random effects in all level 1 groups
I don't know what the message means, nor if I need to be concerned about the
message. I would be
g
Hi everyone,
How do I run Heckman models in R with two binary dependent variables?
sampleSelection package in R works with standard heckman models ( binary DV for
the selection equation and continuous DV for the outcome equation). In my case
dependent variables are both binary (actually order
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Dear John,
lme() not longer requires a GroupedData object. You can directly use a
data.frame which is easier to specify different models.
You want something like
lme(value ~ time * group, random = ~ time|SS, data = data1)
PS Note that the R-Sig-mixedmodels is more suited for this kind of questi
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