On 17/07/2016 6:31 PM, Shivi Bhatia wrote:
Hi Team,
Please suggest.
On Sun, Jul 17, 2016 at 2:55 AM, Shivi Bhatia wrote:
Good Day,
I am working on a text mining assignment and have built the document
matrix using the tm package.
We don't do homework here. You should ask your instructor f
Here is an example of using dplyr. Please provide a reasonable subset of
data. Your was all for the same date. Use 'dput' to put in your email.
> x <- read.table(text = " X.YY MM DD hh WDI R.WSP D.GST PRES ATMP
DEWP
+ 2015 1 1 0 328 3.6 4.5 1028.0 3.8 -3.5
+ 2015 1 1 1 3
Dear Pamela,
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Pamela
> Wong
> Sent: Sunday, July 17, 2016 1:58 AM
> To: r-help@r-project.org
> Subject: [R] Type III SS and collinearity in R
>
> Hi there
> It appears the Anova() function in the car pac
Hi Team,
Please suggest.
On Sun, Jul 17, 2016 at 2:55 AM, Shivi Bhatia wrote:
> Good Day,
>
> I am working on a text mining assignment and have built the document
> matrix using the tm package.
>
> Now I need to run findAssocs from my dtm with some word say 'like' with a
> correlation of 0.70 b
Hello Tom,
try aggregate() or cast(). Both works.I prefer the latter.
library(reshape)
desc<-melt(mydata, measure.vars=c("WDI","R.WSP", "D.GST", "PRES",
"ATMP", "DEWP"),
id.vars=c("X.YY","MM","DD"))
summary<-cast(desc, X.YY+MM+DD~variable, mean)
On 17 July 2016 at 06:22, Tom
Hello Good Folk,
My dataframe looks like this:
> mydata
X.YY MM DD hh WDI R.WSP D.GST PRES ATMP DEWP
12015 1 1 0 328 3.6 4.5 1028.0 3.8 -3.5
22015 1 1 1 300 2.1 2.7 1027.9 3.7 -4.4
32015 1 1 2 264 2.4 2.9 1027.7 3.6 -4.5
42015 1 1 3 230 4
Solved it myself:
aggregate(mydata, by=mydata[c("MM","DD")], FUN=mean)
Thank you.
# -
My dataframe looks like this:
> mydata
X.YY MM DD hh WDI R.WSP D.GST PRES ATMP DEWP
12015 1 1 0 328 3.6 4.5 102
Hi there
It appears the Anova() function in the car package cannot compute type III SS
when there is collinearity in the model. Has anyone else run into this problem?
I would use drop1() to obtain the SS but it does not provide the intercept...
__
R-he
Dear Pamela,
It's very hard to tell from your message what you did, but I'm guessing that
you passed the object produced by Anova() to drop1(). If this is in fact what
you did, it makes no sense, because Anova() doesn't produce a linear-model
object but rather takes such an object as its argume
> On Jul 16, 2016, at 7:43 PM, Ashta wrote:
>
> HI Denes, Duncan,Michael and all,
>
> Thank you very much for the helpful suggestion. Some of my data sets
> were not square matrix, however, Denes's suggestion,"
> as.data.frame.table() ", handled that one.
>
`as.data.frame.table` should work
On 17/07/2016 11:33 AM, Erin Hodgess wrote:
Hello everyone!
I'm looking at this problem, and I'm sure there is a straightforward
solution. I have a matrix and some of the values have zeroes to the right
of the decimal point. When I write these to a file, the zeroes disappear.
The material belo
write.table(format(x2,drop0trailing=FALSE),file="",col.name=FALSE,row.name
=FALSE,quote=FALSE)
--
Erin Hodgess
Associate Professor
Department of Mathematical and Statistics
University of Houston - Downtown
mailto: erinm.hodg...@gmail.com
[[alternative HTML version deleted]]
Hello everyone!
I'm looking at this problem, and I'm sure there is a straightforward
solution. I have a matrix and some of the values have zeroes to the right
of the decimal point. When I write these to a file, the zeroes disappear.
The material below is what I have tried so far.
> x2
The R version was not stated (RStudio is a shell, so you cannot infer the
version of R from its version number), but the warning messages suggest that it
is less than 3.2.3. Recent versions of pbkrtest depend on R >= 3.2.3. I happen
to know that because it led to infelicities which should probab
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