The file may have been stored in the UTF-16 encoding (what Windows Notepad
calls "Unicode"). If so, adding fileEncoding="UTF-16" to the read.table
command might read it correctly.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Thu, Jul 14, 2016 at 3:49 PM, Christa Rose wrote:
> Can someone pl
Christa,
As others are noting, the file is not a text file.
Open the file in Notebook or Notepad. If the editor complains, then
open it in Word. Save it as a "plain text" file. You will have to
choose the file type in the "Save As" dialog. You may run into other
issues such as the field separ
On 14/07/2016 6:49 PM, Christa Rose wrote:
Can someone please help? The read.table command is not working for me I
think because Windows has my account name stored as "Christa Rose" with a
space in it. Is this a problem? I have tried many syntax iterations, and
cannot get around this.
I don't t
Hi Christa,
The error messages tell you that the file contains NULL characters,
which can cause problems with reading files. You can remove these
characters with a "hex editor". I am not familiar with those used on
Windows, but look at this Web page:
http://alternativeto.net/software/okteta/?platf
Can someone please help? The read.table command is not working for me I
think because Windows has my account name stored as "Christa Rose" with a
space in it. Is this a problem? I have tried many syntax iterations, and
cannot get around this.
Here is an example of the syntax I've used:
> RanMinePl
Dear all,
I hope you’re enjoying your summer!
I've been asked to "aggregate" my time lags from simple 1 year time lag to 1-3
year time lag. This could be done --I've been told --by simply taking the sum
or mean of time lag 1,2, and 3.
I need your help here. How can I generate this "aggrega
> txt <- "|ATP Group|Business Event|Category|
|02 |A |AC |
|02 |A |AD |
|02 |A |EQ |
|ZM |A |AU |
|ZM |A |AV |
|ZM |A |AW |
|02 |B |AC |
|
I took a wild guess as to what your data looked like (please use
dput() to provide data, and please do not post in HTML), and took your
request literally.
Here's one way to approach the problem:
mydat <- structure(list(ATP.Group = c("02", "02", "02", "ZM", "ZM", "ZM",
"02", "02", "02"), Business
Hello All:
I would like to get your help on the following problem.
I have the following data and the first row is the header. Spaces are not
important.
I want to find out distinct combinations of ATP Group and Business Event
(these are the field names that you can see in the data below) that have
Thank you very much, Sarah, for your help. The colvar argument was
certainly what I needed. I will follow your suggestion.
Cheers,
Jorge.-
On Thu, Jul 14, 2016 at 1:29 PM, Sarah Goslee
wrote:
> I assume you want some variant of:
> with(d0, scatter3D(X, Z, Y, bty = "b2", col = cols, colvar =
I assume you want some variant of:
with(d0, scatter3D(X, Z, Y, bty = "b2", col = cols, colvar = c(1, 2, 3),
pch = 20, cex = 4, ticktype = "detailed", colkey = FALSE, phi =
20, theta = -140, zlim = c(-14, 14), xlim = c(-14, 14), ylim = c(-14, 14),
xlab = "X", ylab = "Z", zlab = "Y", CI =
Dear R-help,
I am using the plot3D package to produce 3D spheres along with 95% CIs
distinguishing each sphere with a predefined colour (see the reproducible
example at the end).
I have been successful in producing a similar plot using a different data
set (kindly see
https://www.dropbox.com/s/sn
Thanks.
-Original Message-
From: David L Carlson [mailto:dcarl...@tamu.edu]
Sent: 13 July 2016 05:05 PM
To: Mangalani Peter Makananisa; r-help@r-project.org
Subject: RE: Dates in R (Year Month)
You need to look at the examples on the manual pages for ?yearmon and ?strptime:
> Z <- as.ye
It would be possible to ease the task of returning full rows from the matching
dates (min or max) by wrapping the aggregate function up in a utility function
and just returning the dates. I also borrowed the use of format() from Bill
Dunlap’s example so that loading the zoo package is not neces
I did not use aggregate because it did not make it convenient to
return the rest of the row with the min or max data in it.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Thu, Jul 14, 2016 at 9:22 AM, Nordlund, Dan (DSHS/RDA) <
nord...@dshs.wa.gov> wrote:
> Using William Dunlap's data, here is
Thanks. That is a slick one.
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Nordlund, Dan
(DSHS/RDA)
Sent: 14 July 2016 17:22
To: R-help Mailing List
Subject: Re: [R] Selecting 1st and last dates from a set of dates
Using William Dunlap's data, here i
Using William Dunlap's data, here is another alternative:
library(zoo)
aggregate(d$Date,list(as.yearmon(d$Date)),min)
aggregate(d$Date,list(as.yearmon(d$Date)),max)
Hope this is helpful,
Dan
Daniel Nordlund, PhD
Research and Data Analysis Division
Services & Enterprise Support Administration
W
Thanks William.
This works. Thanks again.
From: William Dunlap [mailto:wdun...@tibco.com]
Sent: 14 July 2016 16:42
To: Mehta, Gaurang
Cc: Jeff Newmiller; R-help Mailing List
Subject: Re: [R] Selecting 1st and last dates from a set of dates
Does the following example help? isFirstInRun() and isLa
Does the following example help? isFirstInRun() and isLastInRun() are handy
utility functions.
> d <- transform(data.frame(Date=as.Date(c("2016-01-05", "2016-03-04",
"2016-03-30", "2015-12-02", "2016-03-04", "2015-12-21"))),
DaysSince1970=as.integer(Date), I=seq_along(Date))
> d
Date Days
Hi Jeff,
I would say my problem is what you described in 2 below. My data is as follows:
DateUC11UC12UC13
02/01/1997 1 2 0
03/01/1997 5 6 3
06/01/1997 5 4 6
07/01/1997 6 4 3
08/01/1997 6 5 5
09/01/1997
It looks like a common problem when using do.call("order", dataFrame).
If dataFrame has a column whose name matches an argument to order
you will get this problem. The solution is to use do.call("order",
unname(dataFrame)).
E.g.,
> do.call("order", tuneAcc)
Error in match.arg(method) : 'arg' m
It has never been obvious to me that the lasso approach can handle
interactions among predictor variables well at all. I'ld be curious to see
what others think and what you learn.
Brian
Brian S. Cade, PhD
U. S. Geological Survey
Fort Collins Science Center
2150 Centre Ave., Bldg. C
Fort Collins
I suspect the answer to your question (is there a function...) is almost
certainly yes, but your question is too vague to be sure.
1) Data frames and matrices are different in important ways... it is highly
unlikely that matrices would be appropriate for date data.
2) Do you mean "select recor
I am merging two data frames:
tuneAcc <- structure(list(select = c(FALSE, TRUE), method =
structure(c(1L, 1L), .Label = "GCV.Cp", class = "factor"), RMSE =
c(29.2102056093962, 28.9743318817886), Rsquared =
c(0.0322612161559773, 0.0281713457306074), RMSESD = c(0.981573768028697,
0.791307778398384),
1) Although it can be as easy as this, when you are dealing with packages the
complications of namespaces may prevent your modified version of the function
now in the global namespace from being used by other functions in the package.
That is, you may have to redefine all of the interrelated fun
Hi Team,
I am struggling to select the first date and last date of the month where there
is data in a dataframe/matrix.
Is there any r function that can help to easily select data on the first and
last day of the month from the given set of dates and values.
Thanks for the help in advance.
Regard
I am not aware of a detailed documentation of this beyond the actual source
code.
However, the principles are fairly straightforward, except that the rules for
constructing the design matrix from the model formula can be a bit arcane at
times.
The two main tools are the design matrix construct
Hi Timo,
To perform the first point, you just have to write the function name in R
without using parentheses and arguments after it. You will see the code of the
function. Copy and Paste it on notepad, change the name of the function in the
notepad, then change what you want to change in your fu
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